Can the MVVM-Light ViewModelLocator be used in nested ViewModels? - wpf

Question

The Visual Studio 2008 Designer doesn't seem to like UserControls that reference the MVVM-Light ViewModelLocator. I get an error message like:
Could not create an instance of type 'MyUserControl'.
For example, the following XAML will cause this behavior if MyUserControl uses the ViewModelLocator to establish its DataContext.
<Page x:Class="MyProject.Views.MainView"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:Views="clr-namespace:MyProject.Views"
>
<Grid>
<Views:MyUserControl/>
</Grid>
</Page>
MyUserControl is extremely simple:
<UserControl x:Class="MyProject.Views.MyUserControl"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
DataContext="{Binding MyNestedViewModel, Source={StaticResource Locator}}"
>
<Grid>
<TextBlock>Hello</TextBlock>
</Grid>
</UserControl>
And the "MyNestedViewModel" property simply instantiates an instance of the MyNestedViewModel class, which has absolutely no code in its default constructor.
Two questions:
Am I using the ViewModelLocator correctly? That is, can it be used in nested views or is it only meant for top-level Views?
Could this just be another bug in Cider, the Visual Studio 2008 designer?
Note that everything works perfectly at runtime. I only have problems at design time. But I hate coding XAML blind.

Answer 1

I encounter the same situation in VS 2010. A partial workaround I JUST discovered...
In your UserControl, change DataContext to d:DataContext
<UserControl x:Class="MyProject.Views.MyUserControl"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
d:DataContext="{Binding MyNestedViewModel, Source={StaticResource Locator}}"
>
<Grid>
<TextBlock>Hello</TextBlock>
</Grid>
</UserControl>
Unfortunately, I can't get it to display data in the UserControl YET, just the UserControl itself.