problem with fork() - c

Question

I'm writing a shell which forks, with the parent reading the input and the child process parsing and executing it with execvp.
pseudocode of main method:
do{
pid = fork();
print pid;
if (p<0) { error; exit; }
if (p>0) { wait for child to finish; read input; }
else { call function to parse input; exit; }
}while condition
return;
what happens is that i never seem to enter the child process (pid printed is always positive, i never enter the else). however, if i don't call the parse function and just have else exit, i do correctly enter parent and child alternatingly.
full code:
int main(int argc, char *argv[]){
char input[500];
pid_t p;
int firstrun = 1;
do{
p = fork();
printf("PID: %d", p);
if (p < 0) {printf("Error forking"); exit(-1);}
if (p > 0){
wait(NULL);
firstrun = 0;
printf("\n> ");
bzero(input, 500);
fflush(stdout);
read(0, input, 499);
input[strlen(input)-1] = '\0';
}
else exit(0);
else { if (parse(input) != 0 && firstrun != 1) { printf("Error parsing"); exit(-1); } exit(0); }
}while(strcmp(input, "exit") != 0);
return 0;
}
EDIT:
-that else exit(0) just something i forgot there from playing around
-adding a newlines to the prints shows that it does in fact correctly fork and enter the child process; thank you, the problem seems to be in the parse

Answer 1

One culprit is else exit(0);
That would execute in the child shell, which means it never gets to the parsing stage. The code is also syntactically invalid because after that you have another else.

Answer 2

`if (p >= 0) {
if (p == 0) {/* chile process */}
else if (p > 0) {/* parent process */}
} else {
/* handle the error returned by fork() */
}`
I'd do it like the above pseudo code.
else exit(0); is what the child process is doing in your code.

Answer 3

Your core is a tad messy with all the nested if's and else's. There are some dangling else statements as well (else exit(0);). I'd start by cleaning those up. I can't see any other logical problems with your code. It's simple enough.

Answer 4

Swap the lines
else exit(0);
and
else { if (parse(input) != 0 && firstrun != 1) { printf("Error parsing"); exit(-1); } exit(0); }

Answer 5

Apart from everything everybody else has said about the fact that the else's are a complete mess, there are some other issues you will hit when you have fixed them.
In the child, the input array will be garbage on the first run because you don't put anything in it before forking.
It seems completely pointless to fork at all since you are not exec'ing anything in the child but you are waiting for the child to finish in the parent. Why not just call parse from the parent?