Is it a proper way to access a private function in cakePHP - cakephp

In a controller, I got two functions that one is made to be private:
function toavail(){
$this->autoRender=false;
$result2=$this->__avail();
if($result2==0){return "OK";}
else{return 0;}
}
function __avail(){
$result1=$this->Site1->findByusername('1');
if($result1){
return 1;
}
else{
return 0;
}
}
I am not sure if it is a proper way to access the private function in this case.

You're accessing it correctly (assuming that both methods are in the same controller class), but in case you're not aware, your __avail() method isn't really private. The double underscore (__) prefix is something of a convention, but it's only a convention. Your "private" method is really public in actuality. To make it private you need to specify it as such in the signature:
private function __avail() { ... }

you are accessing it correctly, but, you are not declaring correctly the function.
You should declare it as protected -> protected function __avail()
Source: http://book.cakephp.org/2.0/en/getting-started/cakephp-conventions.html

Related

Subclassing in Objective C Runtime

I am attempting to implement a solution from How to set canBecomeKeyWindow? Into my native C application using Objective-C runtime (The app is already written with objective C Runtime). Is there a way to create a subclass purely in Objective-C Runtime?
Right now I just create NSWindow object but need to be able to create my own so I can override the function specified in that question.
objc_msgSend((id)objc_getClass("NSWindow"), sel_registerName("alloc"));
The signature of can_become_key_window_true is slightly incorrect. According to the documentation (https://developer.apple.com/documentation/objectivec/objective-c_runtime/imp?language=objc) the function should have at least two arguments: "self" and "_cmd". So the signature should be like:
static bool can_become_key_window_true(__unused id _self, __unused SEL _cmd) {
return true;
}
You could also use #encode to construct the type encoding for the function.
char encoding[10]; // should be enough
snprintf(encoding, 10, "%s%s%s", #encode(BOOL), #encode(id), #encode(SEL));
... or you could get a method from UIWindow and get its type encoding like:
Method m = class_getInstanceMethod(objc_lookUpClass("UIWindow"), sel_getUid("canBecomeKeyWindow"));
const char *encoding = method_getTypeEncoding(m);
And as you might have noticed you could use sel_getUid() instead of sel_registerName as you expect this selector to be already registered by this time (because you are about to override an existing method).
To allocate a new instance you could use
window = class_createInstance(__UIWindow);
Figured it out after a lot of code searching:
// Subclass NSWindow with overridden function
Class __NSWindow =
objc_allocateClassPair(objc_getClass("NSWindow"), "__NSWindow", 0);
class_addMethod(__NSWindow,
sel_registerName("canBecomeKeyWindow"),
(IMP)can_become_key_window_true, "B#:");
objc_registerClassPair(__NSWindow);
// Allocate a new __NSWindow
window = objc_msgSend((id)__NSWindow, sel_registerName("alloc"));
And then can_become_key_window_true is defined as:
static bool can_become_key_window_true() {
return true;
}
I use objc_allocateClassPair to subclass the object and return a Class of that object. Then I use class_addMethod to override the method canBecomeKeyWindow. And finally use objc_registerClassPair to register my new class before using it as I would a normal NSWindow.

Extjs 5 - static function call other static function from same class

I have code like this:
Ext.define( 'someClass', {
statics : {
methodA : function( ) { return 'A'; },
methodAB : function( ) {
var A = this.methodA();
return A + 'B';
}
}
} );
I have problem with accessing static methodA.
Can someone help me what would be a proper way to do it ?
you should call statics using the fully qualified className.methodName() syntax. 'this' inside a static is not going to be what you think it is. For example, if called from an event handler it will probably be the 'window' object, which certainly doesn't have a methodA() method. In other cases 'this' may be the prototype. In that case you may get away with this syntax but it is misleading and likely to cause future bugs.

Static extension methods in Kotlin

How do you define a static extension method in Kotlin? Is this even possible? I currently have an extension method as shown below.
public fun Uber.doMagic(context: Context) {
// ...
}
The above extension can be invoked on an instance.
uberInstance.doMagic(context) // Instance method
but how do I make it static method like shown below.
Uber.doMagic(context) // Static or class method
To achieve Uber.doMagic(context), you can write an extension to the companion object of Uber (the companion object declaration is required):
class Uber {
companion object {}
}
fun Uber.Companion.doMagic(context: Context) { }
This is what the official documentation says:
Kotlin generates static methods for package-level functions. Kotlin
can also generate static methods for functions defined in named
objects or companion objects if you annotate those functions as
#JvmStatic. For example:
Kotlin static methods
class C {
companion object {
#JvmStatic fun foo() {}
fun bar() {}
}
}
Now, foo() is static in Java, while bar() is not:
C.foo(); // works fine
C.bar(); // error: not a static method
I actually had this exact question 30 minutes ago, so I started digging around and couldn't find any solution or workaround for this, BUT while searching I found this section on the Kotlinglang website that states that:
Note that extensions can be defined with a nullable receiver type. Such extensions can be called on an object variable even if its value is null.
So then I had the craziest idea ever, why not define an extension function with a nullable receiver (without actually using that receiver) and then call it on a null object!
So I tried that, and it worked pretty well, but it looked so ugly. It was like this:
(null as Type?).staticFunction(param1, param2)
So I went around that by creating a val in my extensions file of the receiver type that had a value of null and then use it in my other class.
So, as an example, here is how I implemented a "static" extension function for the Navigation class in Android:
In my NavigationExtensions.kt file:
val SNavigation: Navigation? = null
fun Navigation?.createNavigateOnClickListener(#IdRes resId: Int, args: Bundle? = null, navOptions: NavOptions? = null,
navigationExtras: Navigator.Extras? = null) : (View) -> Unit {
//This is just implementation details, don't worry too much about them, just focus on the Navigation? part in the method declaration
return { view: View -> view.navigate(resId, args, navOptions, navigationExtras) }
}
In the code that uses it:
SNavigation.createNavigateOnClickListener(R.id.action_gameWonFragment_to_gameFragment)
Obviously, this isn't a class name, it is just a variable of the class type that has a null value. This is obviously ugly on the extension maker side (because they have to create the variable) and on the developer side (because they have to use the SType format instead of the actual class name), but it is the closest that can be achieved right now compared to actual static functions. Hopefully, the Kotlin language makers will respond to the issue that was created and add that feature in the language.
Since I keep coming across this when searching, here's a different approach I haven't seen anyone mention that works in a static way and it works with generics!
Extension definitions:
// Extension function
fun <T> KClass<T>.doSomething() = /* do something */
// Extension Property
val <T> KClass<T>.someVal get() = /* something */
Usage:
MyType::class.doSomething()
MyType::class.someVal
As you can see, the trick is attaching the extension function to the KClass of the type instead since that can be referenced statically.
You can create a static method with using Companion object like:
class Foo {
// ...
companion object {
public fun bar() {
// do anything
}
}
}
and then you can call it like:
class Baz {
// ...
private fun callBar() {
Foo.bar()
}
}
Recomend you to look at this link. As you can see there, you just should declare method at the top-level of the package (file):
package strings
public fun joinToString(...): String { ... }
This is equal to
package strings;
public class JoinKt {
public static String joinToString(...) { ... }
}
With constans everything are the same. This declaration
val UNIX_LINE_SEPARATOR = "\n"
is equal to
public static final String UNIX_LINE_SEPARATOR = "\n";
I also required the ability to extend a Java object with a static method and found the best solution for me was to create a Kotlin object that extended the Java class and add my method there.
object Colour: Color(){
fun parseColor(r: Int?, g: Int?, b: Int?) = parseColor(String.format("#%02x%02x%02x", r, g, b))
}
invocation:
val colour = Colour.parseColor(62, 0, 100)
I'm also quite fond of having the possibility to add static extension methods in Kotlin. As a workaround for now I'm adding the exntension method to multiple classes instead of using one static extension method in all of them.
class Util
fun Util.isDeviceOnline(context: Context): Boolean {
val connMgr = context.getSystemService(Context.CONNECTIVITY_SERVICE) as ConnectivityManager
val networkInfo = connMgr.activeNetworkInfo
return networkInfo != null && networkInfo.isConnected
}
fun Activity.isDeviceOnline(context: Context) = { Util().isDeviceOnline(context) }
fun OkHttpClient.isDeviceOnline(context: Context) = { Util().isDeviceOnline(context) }
To create an extension method in kotlin you have to create a kotlin file(not a class) then declare your method in the file
Eg:
public fun String.toLowercase(){
// **this** is the string object
}
Import the function in the class or file you are working on and use it.

How to exit an apex function?

I have an apex function which has a void return type. I want to exit the function at a specific position. Is this possible in apex without changing return type pagereference?
In apex, the return keyword signals to immediately stop processing statements in that function.
public void doNothing() {
return;
}
I'm not sure that I correctly understood your question (more detailed description will be useful), but it seems that you can use a return statement by the following way:
public PageReference method() {
//some your code ....
if (some specific condition) {
return null;
}
PageReference pageRef = new PageReference('someURL');
return pageRef;
}
Please show your code for a more target help

How do I get class of a Ruby object in C?

I have a function that handles two types: NVector and NMatrix; the former is derived from the latter. This function is basically a specialized copy constructor. I want it to return an object of the same type as that upon which it was called, so, NVector returns NVector, not NMatrix.
static VALUE nm_init_modifiedcopy(VALUE self) {
// ... some code ...
// formerly, I had cNMatrix where klass is. But it could also be cNVector!
return Data_Wrap_Struct(klass, mark_func, delete_func, unwrapped_self_copy);
}
How do I get the class property of an object to pass into Data_Wrap_Struct?
Like clockwork, as soon as I ask a question on Stackoverflow, I find the answer.
The macro is CLASS_OF.
static VALUE nm_init_modifiedcopy(VALUE self) {
// ... some code ...
return Data_Wrap_Struct(CLASS_OF(self), mark_func, delete_func, unwrapped_self_copy);
}

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