I'm using glob function for a autocompletion function. I'm showing you the problem because it's difficult to explain:
matched = ~/.tcsh
glob(matched, 0, NULL, &pglob);
glob put all matched files in a char ** and when I print it I have:
case[0] = .tcshrc
case[1] =
I should have .tcshrc~ in case[1], but nothing =S, I've seen a flag "GLOB_TILDE" like this "
glob(matched, GLOB_TILDE, NULL, &pglob);
But it doesn't change anything! Can someone help me?
The GLOB_TILDE flag only affects the output when the ~ appears at the beginning of the glob. See here:
http://www.gnu.org/s/libc/manual/html_node/More-Flags-for-Globbing.html
As for your problem, it appears to me that your matched value is wrong. Seems like you should be sticking a * at the end of it for it to be useful for autocompletion, i.e.:
matched = ~/.tcsh*
I'm a little bit confused as how your previous example found even the first one. The bottom part of this man page article has some interesting examples too:
http://www.opengroup.org/onlinepubs/000095399/functions/glob.html
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How can I pull the "discord.gg/rsCC8y7WC4" link from a text like this
console.log(invitelink) ==> discord.gg/rsCC8y7WC4
Use String.match() for this. String.match accepts a regex argument which looks like this:
let str = 'hey there this is just a random string';
let res = str.match(/random/);
//res is now ['random']
Now for your problem, you are probably looking for this:
if(msg.content.match(/discord\.gg\/.+/) || msg.content.match(/discordapp\.com\/invite\/.+/)) return msg.channel.send('Hey! You put an invite in your message!');
Now that regex may look a bit messy/complicated but the \s are to escape the character and make sure regex knows that it’s not the special character it uses, and is actually just a character part of the search. To clarify why the above example should work, here’s a little explanation:
match() returns either an array (if it gets a match) or null (if it gets no match). You are searching for the strings 'discord.gg/' followed by any characters and also checking for the string 'discordapp.com/invite/' also followed by any characters.
If this doesn’t work, please tell me.
I have been working on this program for over a week with no breakthrough. The questions states as follows:
A disc file ‘REQUESTS.TXT’ contains airline flight data formatted
(STR6, STR3, STR3, INT).
Example:
AA1011SFxLAx34 (American Airlines 1010, SF to LA, 34 seats)
W0924DNVDFW101 (Western 0924, DNV to DFW, 101 seats)
Another file ‘AVAILABL.TXT’ contains an unspecified number of reservation request records formatted identically as described above except the Seats Available field is a Seats Requested field.
Guidelines:
Read reservation flights and process requests. If the request can be fullfilled (i.e.. it is in AVAILABL and REQUESTS) then print "Reservation Processed", otherwise print "Reservation Denied".
Print out flight data file before and after reservations are processed, ordered by flight ID in a four(4) column format.
Print an overall outcome report for all processed.(Present totals for the number of requests satisfied and denied)
I have tried a few different approaches.. I tried to split up the first STR6 by isalpha/isdigit and combine them to make the FlightID (AA + 1011). Proceeded to try to then split up the remaining characters between STR3 and STR3 via isalpha + for loop. And lastly, I tried to take the last 3+ digits for the # of seats during each for loop iteration and multiply the first digit by 100(for a 3-digit value) or 10(for a 2-digit value), adding it to a running total for availSeats(INT). This, at least I thought so, would produce a
AA+1011 = AA1011(STR6) // W+0924 = W0924(STR6)
SFx(STR3) // DNV(STR3)
LAx(STR3) // DFW(STR3)
(3*10)+(4*1) = 34(INT) // (1*100)+(0*10)+(1*1) = 101(INT)
All of this stored within a Struct Array.
i.e...
FlightData Flight; ............................................FlightData Flight;
Flight[0].flightID = AA1011; .........................Flight[1].flightID = W0924;
Flight[0].fromCity = SFx; ...............................Flight[1].fromCity = DNV;
Flight[0].toCity = LAx; ..................................Flight[1].toCity = DFW;
Flight[0].seatsAvail = 34; .............................Flight[1].seatsAvail = 101;
I am really at a loss right now and have no other way to progress other than searching up different techniques/methods to use to make this work. I am a beginner clearly and will continue to practice and progress in C, but if anyone could provide me with a push in the right direction on how one would execute this via .txt into a Struct would be amazing. Also, if anyone has another method they used to solve this problem I would love to analyze it. Thanks!
(This is my first post, I spent a lot of time formatting it to be clear on Stackoverflow, so If i messed up in areas some constructive critisism would be useful! This applies to my posting and my coding practices. Thanks again!)
EDIT: The question I am asking here is how to successfully take a string such as AA1011SFxLAx34 and turn it into a Structure like the above diagram. It must also work for the second string W0924DNVDFW101 which has only 1 Char in its ID. (rather than two in AA1011). Im not sure what else I am supposed to edit after reading the guidelines.
I consider this a home work question, so I answer according to
How do I ask and answer homework questions?
Find a tutorial on C, work through it.
Then take a HelloWorld, modify it in small steps to approach your goal in steps from working program to working program. This way you should at least get to being able to read text from a file and print it.
Then learn to store parts of what you print into basic variables.
Then learn about structures.
And so on.
This way you will get quite close to the solution.
If it is not completely what you need show the code you have here at that point and ask a specific question about the first problem explaining what you suspect the problem to be. Show code which has exactly that one problem and makes it visible and has not other warnings (using at least e.g. gcc -Wall mycode).
Fix with the help of commments/answers you receive, repeat.
I have done some searching but cannot see how to actually code this. I am new to Python and not really sure what method I should use to try to do this.
I have some files that I would like to rename. Unfortunately the portion towards the file extension is never the same and would like to just remove it.
File name is like AC_DC - Shot Down In Flames (Official Video)-UKwVvSleM6w.mp3
Any help would be appreciated.
Since this looks like the result from youtube-dl, the "random" substring is most likely the unique video id, which in my experience is always 11 characters long. It can, however, include dashes (-), so the regex-approach suggested by smitrp would not always work.
I use this "dirty" workaround:
>>> original_name="AC_DC - Shot Down In Flames (Official Video)-UKwVvSleM6w.mp3"
>>> new_name=original_name[:-16]+".mp3"
>>> new_name
'AC_DC - Shot Down In Flames (Official Video).mp3'
Edit:
If you really, REALLY want to find the "-XXXX"-portion, have a look at str.rfind(). This will help you to find the index of the last dash (-), which you can directly use for the slice notation of the string.
Disclaimer:
This will provide wrong results, if the video id contains a dash, e.g. here: https://www.youtube.com/watch?v=7WVBEB8-wa0
Then you will find the last dash, remove -wa0 and be left with -7WVBEB8 at the end of the filename.
Using idea of the above answer, one can also take into account that a normal word does not
contain more than one capital character.
def youtube_name_fix(folder):
import os
from pathlib import Path
import re
REGEX = re.compile(r'[A-Z]')
for name in os.listdir(folder):
basename = Path(name)
last_12 = basename.stem[-12:]
# check if the end string is not all uppercase (then it could be part of a valid name)
if not last_12.isupper():
# check if the last string has more than one uppercase letters
if len(REGEX.findall(last_12)) > 1:
# remove the end youtube string and create new full path
new_name = os.path.join(folder, basename.stem[:-12] + basename.suffix)
try:
os.rename(os.path.join(folder,name), new_name)
except Exception as e:
print(e)
> youtube_name_fix(p)
old name -> "4-Discrete and Continuous Probability Models-esHwigpYggU.mp4"
new name -> "4-Discrete and Continuous Probability Models.mp4"
Problem:
Hello, I have been struggling recently in my programming endeavours. I have managed to receive the output below from Google Speech to Text, but I cannot figure out how draw data from this block.
Excerpt 1:
[VoiceMain]: Successfully initialized
{"result":[]}
{"result":[{"alternative":[{"transcript":"hello","confidence":0.46152416},{"transcript":"how low"},{"transcript":"how lo"},{"transcript":"how long"},{"transcript":"Polo"}],"final":true}],"result_index":0}
[VoiceMain]: Successfully initialized
{"result":[]}
{"result":[{"alternative":[{"transcript":"hello"},{"transcript":"how long"},{"transcript":"how low"},{"transcript":"howlong"}],"final":true}],"result_index":0}
Objective:
My goal is to extract the string "hello" (without the quotation marks) from the first transcript of each block and set it equal to a variable. The problem arises when I do not know what the phrase will be. Instead of "hello", the phrase may be a string of any length. Even if it is a different string, I would still like to set it to the same variable to which the phrase "hello" would have been set to.
Furthermore, I would like to extract the number after the word "confidence". In this case, it is 0.46152416. Data type does not matter for the confidence variable. The confidence variable appears to be more difficult to extract from the blocks because it may or may not be present. If it is not present, it must be ignored. If it is present however, it must be detected and stored as a variable.
Also please note that this text block is stored within a file named "CurlOutput.txt".
All help or advice related to solving this problem is greatly appreciated.
You could do this with regex, but then I am assuming you will want to use this as a dict later in your code. So here is a python approach to building this result as a dictionary.
import json
with open('CurlOutput.txt') as f:
lines = f.read().splitlines()
flag = '{"result":[]} '
for line in lines: # Loop through each lin in file
if flag in line: # check if this is a line with data on it
results = json.loads(line.replace(flag, ''))['result'] # Load data as a dict
# If you just want to change first index of alternative
# results[0]['alternative'][0]['transcript'] = 'myNewString'
# If you want to check all alternative for confidence and transcript
for result in results[0]['alternative']: # Loop over each alternative
transcript = result['transcript']
confidence = None
if 'confidence' in result:
confidence = result['confidence']
# now do whatever you want with confidence and transcript.
I have created an array of objects and I would like assign a property value in a vector operation without using a for loop. Unfortunately I get an error.
A simplified example of the problem.
classdef clsMyClass < handle
properties
dblMyProperty1
end
methods
function obj = clsMyClass()
end
end
end
And when running
vecMyArray = clsMyClass.empty(100,0);
vecMyArray(100) = clsMyClass;
vecMyArray.dblMyProperty1 = 1:100;
We get the following error:
??? Incorrect number of right hand side elements in dot name
assignment. Missing [] around left hand side is a likely cause.
Any help would be appreciated.
I see what you're trying to do now. Use disperse from the MATLAB File Exchange:
>> [vecMyArray.dblMyProperty1] = disperse(1:100);
>> vecMyArray(1).dblMyProperty1
ans =
1
>> vecMyArray(10).dblMyProperty1
ans =
10
You can use the deal function for exactly this purpose:
[vecMyArray.dblMyProperty1] = deal(1:100);
See: http://www.mathworks.com/company/newsletters/articles/whats-the-big-deal.html
Edit: No you can't, actually; that'll set them to all be the vector 1:100.
I think you'll find your answer here in "Struct array errors." Even though this is a class, similar rules apply.
Unfortunately missing [] is not the cause, since adding them causes more errors. The cause is that you cannot assign the same value to all fields of the same name at once, you must do it one at a time, as in the following code:
So you'll need:
for ii=1:100
vecMyArray(ii).dblMyProperty1 = ii;
end
I know it's not satisfying, but I think it at least helps us to definitively understand this error.