Adding User License Agreement in Solaris package - licensing

I have asked similar question for Linux RPM (Adding License Agreement in RPM package). Now i have same query for Solaris package. I could not get any helpful link / details if it is possible. But I have found a package which does exactly the same thing but how it has been implemented, its not mentioned.
$pkgadd -d . SUNWsamfsr SUNWsamfsu
Processing package instance from
Sun SAM and Sun SAM-QFS software Solaris 10 (root)(i386) 4.6.5,REV=5.10.2007.03.12
Sun SAMFS - Storage & Archiving Management File System
Copyright (c) 2007 Sun Microsystems, Inc.
All Rights Reserved.
-----------------------------------------------------
In order to install SUNWsamfsr, you must accept the terms of
the Sun License Agreement.
Enter "y" if you do, "n" if you don't, or "v" to view agreement. y
-The administrator commands will be executable by root only (group bin).
If this is the desired value, enter "y". If you want to change
the specified value enter "c". y
...
...
Any ideas how to implement such thing for Solaris package?

I have found a way to solve it.
The self-extracting binary is the way to do it.
Create a shell script which will first dipslay the end user license and take user input whether user agrees or not.
Once user agrees, extract the binary (solaris package file) embed in the shell script and install it.
To embed installer pacakge, first add a marker lets say PKG_DATA:
shell script contents
exit 0
PKG_DATA
Append the package file:
cat pkg_file_name >> your_shell_script
Extract the package and install it:
ARCHIVE=awk '/^__PKG_DATA__/ {print NR + 1; exit 0; }' $0
outname=install.$$
tail -n+$ARCHIVE $0 > $outname
echo "Extracting..."
pkgadd -d $outname
rm -f $outname #we dont need it anymore
exit 0
PKG_DATA
<pkg file data here>

I would implement that using the checkinstall script.
"exit 3" in that script gracefully ends the package installation.
That's not trivial as you need to create a request script and reference it in the checkinstall one.
http://docs.oracle.com/cd/E18752_01/html/817-0406/ch1designpkg-24309.html#ch1designpkg-4

Related

How to view apps packageName with ADB commands? [duplicate]

I need to get the package name of an Android APK. I have tried to unzip the APK and read the contents of the AndroidManifest.xml file but it seems that it's not a text file.
How can I extract the APK's package name?
aapt dump badging <path-to-apk> | grep package:\ name
Install the apk on your Android device. Then
you can launch adb shell and execute pm list packages -f, which shows the package name for each installed apk.
This is taken from
Find package name for Android apps to use Intent to launch Market app from web.
Based on #hackbod answer ... but related to windows.
aapt command is located on Android\SDK\build-tools\version.
If you need more info about what is appt command (Android Asset Packaging Tool) read this https://stackoverflow.com/a/28234956/812915
The dump sub-command of aapt is used to display the values of individual elements or parts of a package:
aapt dump badging <path-to-apk>
If you want see only the line with package: name info, use findstr
aapt dump badging <path-to-apk> | findstr -n "package: name" | findstr "1:"
Hope it help other windows user!
If you are looking at google play and want to know its package name then you can look at url or address bar. You will get package name. Here com.landshark.yaum is the package name
https://play.google.com/store/apps/details?id=com.landshark.yaum&feature=search_result#?t=W251bGwsMSwyLDEsImNvbS5sYW5kc2hhcmsueWF1bSJd
The following bash script will display the package name and the main activity name:
apk_package.sh
package=$(aapt dump badging "$*" | awk '/package/{gsub("name=|'"'"'",""); print $2}')
activity=$(aapt dump badging "$*" | awk '/activity/{gsub("name=|'"'"'",""); print $2}')
echo
echo " file : $1"
echo "package : $package"
echo "activity: $activity"
run it like so:
apk_package.sh /path/to/my.apk
If you open the AndroidManifest.xml using MS Notepad, search for phrase package and you'll find following:
package manifest $xxx.xxxxxxx.xxxxxxx |
where xxx.xxxxxxx.xxxxxxx is your package name, just written with a space after each character.
It's useful way when you don't have any specific tools installed.
Since its mentioned in Android documentation that AAPT has been deprecated, getting the package name using AAPT2 command in Linux is as follows:
./aapt2 dump packagename <path_to_apk>
Since I am using an older version of Gradle build, I had to download a newer version of AAPT2 as mentioned here :
Download AAPT2 from Google Maven
Using the build-tools in my sdk - 25.0.3, 26.0.1 and 27.0.3, executing the aapt2 command shows an error: Unable to open 'packagename': No such file or directory. That's why I went for the newer versions of AAPT2.
I used 3.3.0-5013011 for linux.
A Programmatic Answer
If you need to do this programmatically, it's a little more involved than just getting the answer into your brain. I have a script that I use to sign all of our apps, but each use a different key. Here are 2 ways to get just the Package Name as output so you can put it in a variable or do whatever you need with it.
Example output: com.example.appname (and nothing more)
Requirements
aapt - Android Asset Packaging Tool, part of the SDK Tools download
Solution 1
Using awk specify ' as the Field Separator, search for a line with package: name=, and print only the 2nd "field" in the line:
aapt dump badging /path/to/file.apk | awk -v FS="'" '/package: name=/{print $2}'
A weakness of this method is that it relies on aapt to output the package information fields in the same order:
package: name='com.example.appname' versionCode='3461' versionName='2.2.4' platformBuildVersionName='4.2.2-1425461'
We have no commitments from the developers to maintain this format.
Solution 2
Using awk specify " as the Field Separator, search for a line with package=, and print only the 2nd "field" in the line:
aapt list -a /path/to/file.apk | awk -v FS='"' '/package=/{print $2}'
A weakness of this method is that it relies on aapt to output package= only in the Android Manifest: section of the output. We have no commitments from the developers to maintain this format.
Solution 3
Expand the apk file with apktool d and read the AndroidManifest.xml.
This would be the best method, but the AndroidManifest.xml is a binary file and all the SO answers I see for converting it to text do not work. (Using apktool d instead of a simple unzip is supposed to do this for you, but it does not.) Please comment if you have an solution to this issue
A simple solution would be Open Android Studio -> Build -> Analyze Apk... browse and select the APK now you can find the package name and pretty much you can read.
You can use Analyze APK... from the Build menu in Android Studio, it will display the package name at the top of new window.
If you don't have the Android SDK installed, like in some test scenarios, you can get the package name using the following bash method:
getAppIdFromApk() {
local apk_path="$1"
# regular expression (required)
local re="^\"L.*/MainActivity;"
# sed substitute expression
local se="s:^\"L\(.*\)/MainActivity;:\1:p"
# tr expression
local te=' / .';
local app_id="$(unzip -p $apk_path classes.dex | strings | grep -Eo $re | sed -n -e $se | tr $te)"
echo "$app_id"
}
Tested on a mac. 'strings' and 'unzip' are standard on most linux's, so should work on linux too.
A very simple method is to use apkanalyzer.
apkanalyzer manifest application-id "${_path_to_apk}"
On Mac:
Way 1:
zgong$ /Users/zgong/Library/Android/sdk/build-tools/29.0.3/aapt dump badging ~/Downloads/NonSIMCC-151-app-release-signed.apk
package: name='com.A.B' versionCode='2020111801' versionName='1.0.40' compileSdkVersion='29' compileSdkVersionCodename='10'
sdkVersion:'24'
targetSdkVersion:'29'
......
Way 2:
/Users/zgong/Library/Android/sdk/build-tools/29.0.3/aapt2 dump packagename ~/Downloads/NonSIMCC-151-app-release-signed.apk
com.A.B
If you just want to know package name, run adb logcat, launch the activity you want , you will get a hint on the package name.
Another solution is to use aapt list and use sed to parse through that:
aapt list -a $PATH_TO_YOUR_APK | sed -n "/^Package Group[^s]/s/.*name=//p"
I think the best and simplest way to extract only the package name in Linux is
aapt dump badging <APK_path> | grep package | sed -r "s/package: name='([a-z0-9.]*)'.*/\1/"
Explanation:
AAPT extracts the APK information
Grep "package" to keep only the line about the package information
Make sed replace the whole line with the package name only using the following regex: package: name='([a-z0-9.]*)'.* and replacing with the first (and only) matching group.
There's a very simple way if you got your APK allready on your Smartphone. Just use one of these APPs:
Package Name Viewer Apps
To use this in batch scripting it's handy to have the script return just the package name (e.g. for uninstalling an app when you have the APK).
Here's the script I use:
# extract the android package id from a built apk file
# usage ./getPackageName.sh <path-to-apk>
line=`aapt dump badging "$1" | grep package:\ name`
# above returns:
# package: name='com.calvium.myapp' versionCode='1' versionName='1.0'
if [[ $line =~ name=\'(.+)\'\ versionCode ]]; then
echo ${BASH_REMATCH[1]}
else
echo "Failed to find package name"
exit 1
fi
available on gist
So you could write:
adb uninstall `./getPackageName.sh file.apk`
You can extract AndroidManifest.xml from the APK, remove all NULL bytes, skip everything until after the string 'manifest', and then you are at a length byte followed by the package name (and what comes after it). For the difficult task I use the great GEMA tool, so the command looks like this:
7z e -so MyApp.apk AndroidManifest.xml | gema '\x00=' | gema -match 'manifest<U1><U>=#substring{0;#char-int{$1};$2}'
Of course, you can use any other tool to do the filtering.
For Windows following worked for me:
:: // Initializing variables
SET adb="C:\Users\<User name>\AppData\Local\Android\Sdk\platform-tools\adb"
SET aapt="C:\Users\<User name>\AppData\Local\Android\Sdk\build-tools\22.0.0\aapt"
SET APKPath=C:\Users\<User name>\Desktop\APK\Instant_Instal\
CD %APKPath%
:: // Searching for apk file and storing it
FOR /F "delims=" %%f IN ('dir /S /B *.apk') DO SET "APKFullPath=%%f"
SET apk=%APKFullPath%
:: // Command adb install apk, run apk
%adb% install %apk%
:: // Fetching package name from apk
%aapt% dump badging %APKFullPath% | FIND "package: name=" > temp.txt
FOR /F "tokens=2 delims='" %%s IN (temp.txt) DO SET pkgName=%%s
del temp.txt
:: // Launching apk
%adb% shell monkey -p %pkgName% -c android.intent.category.LAUNCHER 1
pause
Note
Please edit the paths of adb, aapt, APKPath according to the paths of adb, aapt, and the apk location in your system.
Working:
Here I have added the apk in a folder on Desktop "\Desktop\APK\Instant_Instal\".
The command %adb% install %apk% installs the application if the device is connected.
This %aapt% dump badging %APKFullPath% | FIND "package: name=" > temp.txt fetches package name and a few other details like version etc. of the apk and stores in a temp.txt file in same location as that of the apk.
FOR /F "tokens=2 delims='" %%s IN (temp.txt) DO SET pkgName=%%sextracts the package name and assigns topkgName` variable
Finally %adb% shell monkey -p %pkgName% -c android.intent.category.LAUNCHER 1 launches the app.
In essence the above code installs the apk from given location in desktop "Desktop\APK\Instant_Instal\" to the device and launches the application.
You can get the package name programmatically by :
packageManager.getPackageArchiveInfo(apkFilePath, 0)?.packageName
you can instal Package_Name_Viewer.apk on your emulator and next you can see package name of all instaled app on your emulator.
I also tried the de-compilation thing, it works but recently I found the easiest way:
Download and install Appium from Appium website
Open Appium->Android setting, choose the target apk file. And then you get everything you want, the package info, activity info.
As I don't was able to find the package name in the .apk file with editor (like suggested above), I have checked the functions in the App "ES Datei Explorer" / "ES File Explorer" (free version) that I had installed already.
In this tool, the package name is showed properly.
As I think a good file explorer should not be missing on a phone, I suggest to use this tool (if you already have installed the apk on an mobile and have to know the package name).
If you want to read the package name of a typical APK file in your app, there's an easy way to analyze the PackageInfo:
fun getAPKPackageName(apkFile: File?): String? {
if (apkFile == null || !apkFile.isFile || !apkFile.exists()) return null
val apkFilePath = apkFile.absolutePath
if (apkFilePath.isNullOrEmpty()) return null
val packageManager = App.context.packageManager ?: return null
val packageInfo = packageManager.getPackageArchiveInfo(apkFilePath, 0) ?: return null
return packageInfo.packageName
}

How to get package changes before update in zypper

does a counterpart for apt-listchanges functionality from debian/ubuntu exists for zypper?
at the moment I have to do following manually for each updated package: 1) install with zypper, 2) check the changes with rpm -q --changelog PACKAGE_NAME and it is far away from the convenient way it is done by apt-listchanges. And most important for me, how to get changes before the installation (with possibility to abort)?
not with zypper but if you can download both rpms (old and new versions), you may use pkgdiff to check the differences.
I couldn't find a way to see changes made to an individual package without downloading it. OpenSUSE collects packages in "patches" since bugs often need changes to several packages. To see what's in a patch:
Get the name/ID of the available patches with zypper list-patches
Get the info about a patch set using zypper info -t patch $ID where $ID is the ID from the output of the previous command.
If you want to look at a certain package, you can use zypper download to download it without installing. After that, you can use rpm -q --changelog -p $PATH to see the changelog of the downloaded file at $PATH.
(I don't know what apt-listchanges outputs)
The main problem is to get output that is easily parsable from zypper. This isn't perfect, but it may get you on the way:
First get the plain names of the patches from zypper output, omitting header and trailer lines:
zypper -t lp | awk -F'|' '/^---/ { OK=1; next } OK && NF == 7 { gsub(" ", "", $2); print $2 }'
For example you could get:
openSUSE-2018-172
openSUSE-2018-175
openSUSE-2018-176
openSUSE-2018-178
Then feed that output into zypper again, like this:
zypper patch-info $(zypper -t lp | awk -F'|' '/^---/ { OK=1; next } OK && NF == 7 { gsub(" ", "", $2); print $2 }')
Output would include information like this (truncated for brevity):
Summary : Security update for ffmpeg
Description :
This update for ffmpeg fixes the following issues:
Updated ffmpeg to new bugfix release 3.4.2
* Fix integer overflows, multiplication overflows, undefined
shifts, and verify buffer lengths.

Display ASCII graph of Cleartool ls commands

In git it is possible to show an ASCII graph of the log with git log --graph which outputs a commandline graph something like:
* 040cc7c (HEAD, master) Mannual is NOT built by default
* a29ceb7 Removed offensive binary file that was compiled on my machine
| * 901c7dd (cvc3) cvc3 now configured before building
| * d9e8b5e More sane Yices SMT solver caller
| | * 5b98a10 (nullvars) All uninitialized variables get zero inits
| |/
| * 1cad874 CFLAGS for cvc3 to work succesfully
|/
* d642f88 Option -aliasstat, by default stats are suppressed
Is this also possible with ClearCase / ClearTool when using the lsstream or lsvtree commands, without the need to open a GUI?
Since I couldn't find anything that suited me, I created my own python script with this ability. It is still a little rough, but works for me.
For anyone interested, it is available here as a github gist
With command line, you have cleartool lsvtree.
If you want the history to focus on the branch you currently are (instead of starting by default at /main), you need to use the -bra/nch branch-pname option.
Starts the version tree listing at the specified branch.
You can also use an extended name as the pname argument (for example, foo.c##\main\bug405) to start the listing at a particular branch.
But if you need additional information like the author, then you would need to fallback to cleartool lshistory: see "How to ask cleartool lsvtree to show the author's name"

Auto-Running a C Program on Raspberry PI

how can I make my C code to auto-run on my Raspberry PI? I have seen a tutorial so as to achieve that but I do not really know what I am still missing. My initialization script is shown as it follows:
#! /bin/sh
# /etc/init.d/my_settings
#
# Something that could run always can be written here
### BEGIN INIT INFO
# Provides: my_settings
# Required-Start: $remote_fs $syslog
# Required-Stop: $remote_fs $syslog
# Default-Start: 2 3 4 5
# Default-Stop: 0 1 6
# X-Interactive: true
# Short-Description: Script to start C program at boot time
# Description: Enable service provided by my_settings
### END INIT INFO
# Carry out different functions when asked to by the system
case "$1" in
start)
echo "Starting RPi Data Collector Program"
# run application you want to start
sudo /home/pi/Documents/C_Projects/cfor_RPi/charlie &
;;
stop)
echo "Killing RPi Data Collector Program"
# kills the application you want to stop
sudo killall charlie
;;
*)
echo "Usage: /etc/init.d/my_settings {start | stop}"
exit 1
;;
esac
exit 0
The problem is that my program does not run at boot time and I do not really know why. What would I be missing? Is this "killall" statement "killing" some useful process during execution time? I am making this code to run as a background application but I know that after a few seconds, when the RPi is initializing, it asks for an username and a password in order to initialize the session. Is it possible that my RPi is not executing this code because I am not providing the logging information? I do not have a monitor so that my program has to run once I plug my Rpi in. Thanks a lot in advance!!
You'll have to create links to that init script in the proper /etc/rcX.d folders. On raspbian this is done by:
sudo update-rc.d YOUR_INIT_SCRIPT_NAME defaults
You can read this debian how-to for further information. Also you should read more about run levels in Debian.
How scripts/services are run at startuptime, generally depends on the type of init system used. Off the top of my head, I'd distginguish the following 4 types:
Embedded style: A single shell script has all the commands to start the system. Usually the script is at one off the paths the kernel tries to start as init process.
BSD style
System V style: This uses /etc/inittab and latr scripts in /etc/rc*.d/ to start services one by one
systemd
Raspbian dervices from Debian, so I suppose System V style. You have to symlink your script to /etc/rc2.d like
ln -s /etc/init.d/your-script /etc/rc2.d/S08my-script
Not the structure of the link name: It says, it should be started when the run level is entered, and the '08' determines the position (do a ls /etc/rc2.d/ to see the other links).
More details: init(8).
update-rc.d(8) is the proper wway to create the symlinks on debian. See the manpage:
update-rc.d - install and remove System-V style init script links
I advice to read at least the man pages update-rc.d(8) and init(8).
http://www.akeric.com/blog/?p=1976
Here a tutorial on how to auto-loggin and start a script at boot.
If it still don t work, there s either a problem in your script or in your C program.

Using Cron with Cake Console on Ubuntu

I need this cron job to execute my shell just as it does when I run it on the command line.
I read through the one other question I found about this, but my console-based cron job still is not working. I want to post some code and what it outputs, maybe someone can tell me what's going on.
First off, this is on Cake 1.3. I am running on Ubuntu 9.10. I have tried the shell-script method described in the Cake Book.
I have NOT established any special user account for running the script. The cake console is on my PATH (for the ubuntu built-in user).
In another question I found, they report that the -app parameter isn't doing anything. This seems to be the case for me as well.
My shell works as it should when I run this from the command line:
./vendors/cakeshell subscription_reminder -cli /usr/bin -app /var/www/www.example.org/htdocs/app -console /var/www/www.example.org/htdocs/cake/console/cake
the output from this looks like:
Welcome to CakePHP v1.3.2 Console
---------------------------------------------------------------
App : app
Path: /var/www/www.directory.sdcweb.org/htdocs/app
---------------------------------------------------------------
I'm logging my cron-job output to a file and the output of that looks different, like this:
EDIT: i've noticed that this following code block is just the cake shell script that comes with CakePHP, if you open up cake/console/cake in a text editor you should find the following script.
################################################################################
#
# Bake is a shell script for running CakePHP bake script
# PHP versions 4 and 5
#
# CakePHP(tm) : Rapid Development Framework (http://cakephp.org)
# Copyright 2005-2010, Cake Software Foundation, Inc.
#
# Licensed under The MIT License
# Redistributions of files must retain the above copyright notice.
#
# #copyright Copyright 2005-2010, Cake Software Foundation, Inc.
# #link http://cakephp.org CakePHP(tm) Project
# #package cake
# #subpackage cake.cake.console
# #since CakePHP(tm) v 1.2.0.5012
# #license MIT License (http://www.opensource.org/licenses/mit-license.php)
#
################################################################################
LIB=${0/%cake/}
APP=`pwd`
exec php -q ${LIB}cake.php -working "${APP}" "$#"
exit;
My crontab looks like this:
41 20 * * * /var/www/www.example.org/htdocs/app/vendors/cakeshell subscription_reminder -cli /usr/bin -app /var/www/www.example.org/htdocs/app -console /var/www/www.example.org/htdocs/cake/console/cake >> /home/ubuntu/cron-log
First of all, your cronjob runs the script with a different cwd, which may affect behavior. Change it to
41 20 * * * cd /var/www/www.example.org/htdocs/app/; ./vendors/cakeshell ....
But maybe there's something else:
The "cakephp console", cakeshell, probably checks if it's stdin is connected to a tty. If not, it goes in some other, non-interactive mode.
The point is that some programs can talk to you in a terminal (a tty) and others can't.
Some can do both, depending on circumstances.
grep is typically non-interactive
vi, pico and nano are typically only used interactively:
$ vi > test3
Vim: Warning: Output is not to a terminal
$ echo bla | vi
Vim: Warning: Input is not from a terminal
$ vi < test3
Vim: Warning: Input is not from a terminal
bash can do both (non-interactive when running scripts, interactive when serving you in a terminal)
So there's at least the answer as to why the exact same command and environment, can give totally different output. Try to start it from the commandline as you did, but redirecting input from either a pipe or a file, and see what changes.
Well, after a bit more work on this I finally arrived at a crontab which does what I want. It looks like this:
35 01 * * * cd /var/www/www.example.org/htdocs/app; ../cake/console/cake subscription_reminder
Not only does it work, but it is also a lot more readable.
Does your cakeshell begin with
#!/bin/bash
As per the example on http://book.cakephp.org/view/1110/Running-Shells-as-cronjobs?

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