How to write a calculation query in SQL? - sql-server

Question

Using SQL Server 2000
My Query.
SELECT
(Format(IIf(CLng(OutTime) > 180000, CDate('18:00:00'), CDate(Format(OutTime, '00:00:00'))) - IIf(CLng(InTime) < 90000, CDate('09:00:00'), CDate(Format(InTime, '00:00:00'))), 'hh:nn:ss')) As WorkTime,
(Format(IIf(CLng(InTime) < 90000, CDate('09:00:00') - CDate(Format(InTime, '00:00:00')), 0) + IIf(CLng(OutTime) > 180000, CDate(Format(OutTime, '00:00:00')) - CDate('18:00:00'), 0), 'hh:nn:ss')) As OverTime
FROM table
Above query is Access Query, I want to write a same query in sql.
Condition.
I want to Calculate the time after 090000(HH:MM:SS) before 180000 comes in worktime, before
090000 after 180000 comes in overtime.
Intime, Outime data type is varchar in the database
Am new to SQL Server 2000
How to write a SQL query from the above same?

Answer 1

Here is literally translated query to TSQL 2000.
Although, it could be rewritten for better performance:
Select Convert(char(8),
case when DateAdd(Day,-DateDiff(Day, 0, OutTime), OutTime)>'18:00:00'
Then Cast('18:00:00' as datetime)
Else DateAdd(Day,-DateDiff(Day, 0, OutTime), OutTime)
End
-
Case when DateAdd(Day,-DateDiff(Day, 0, InTime), InTime) <'09:00:00'
Then Cast('09:00:00' as datetime)
Else DateAdd(Day,-DateDiff(Day, 0, InTime), InTime)
End,
8
) as WorkTime,
Convert(char(8),
Case when DateAdd(Day,-DateDiff(Day, 0, InTime), InTime) <'09:00:00'
Then Cast('09:00:00' as datetime) -
DateAdd(Day,-DateDiff(Day, 0, InTime), InTime)
Else Cast('00:00:00' as datetime)
End
+
case when DateAdd(Day,-DateDiff(Day, 0, OutTime), OutTime)>'18:00:00'
Then DateAdd(Day,-DateDiff(Day, 0, OutTime), OutTime) -
Cast('18:00:00' as datetime)
Else Cast('00:00:00' as datetime)
End,
8
) as OverTime
From Table
Added later:
If InTime and OutTime have time part only (Date part is Jan 1 1900) you can use directly InTime and OutTime. Otherwise you have to extract time part from datetime column, as:
DateAdd(Day,-DateDiff(Day, 0, OutTime), OutTime)
(this is the fastest way to get time part only)
Instead of:
DateAdd(Day,-DateDiff(Day, 0, OutTime), OutTime)>'18:00:00'
You can use
Datepart(hh,OutTime)>17
P.S. as your time is stored as string yoiu don't need to get time part only. You can cast them to datetime, or you can write also
cast(left(inTime,2) as int) < 9

Answer 2

As a starter take a look at this website which shows you how to convert Access SQL statements into T-SQL as used by SQL server.
http://weblogs.sqlteam.com/jeffs/archive/2007/03/30/Quick-Access-JET-SQL-to-T-SQL-Cheatsheet.aspx

Answer 3

I don't think there's a very easy and simple way to do this - most notably because of storing time values in VARCHAR - this is really making this tricky.....
Anyway, I used an approach with two functions - one dbo.GetSeconds that converts a string representation of a time value ('103500' -> 10:35:00 hours) to a number of seconds, and then a second one dbo.GetOvertime that detects if there is any overtime.
CREATE FUNCTION dbo.GetSeconds(#input varchar(20))
RETURNS int
AS BEGIN
DECLARE #Hour INT
DECLARE #Minute INT
DECLARE #Second INT
DECLARE #TotalSeconds INT
SET #Hour = CAST(SUBSTRING(#input, 0, LEN(#input)-3) AS INT)
SET #Minute = CAST(LEFT(RIGHT(#input, 4), 2) AS INT)
SET #Second = CAST(RIGHT(#input, 2) AS INT)
SET #TotalSeconds = #Hour * 3600 + #Minute * 60 + #Second
RETURN #TotalSeconds
END
CREATE FUNCTION dbo.GetOvertime(#fromSeconds INT, #toSeconds INT)
RETURNS int
AS BEGIN
DECLARE #Overtime INT
SET #Overtime = 0
IF #fromSeconds < 32400 -- 32400 seconds = 09:00 hours
SET #Overtime = #OverTime + (32400 - #fromSeconds)
IF #toSeconds > 64800 -- 64800 seconds = 18:00 hours
SET #Overtime = #OverTime + (#toSeconds - 64800)
RETURN #Overtime
END
With those two functions in place, I can fairly easily calculate what you're looking for:
SELECT
dbo.GetOvertime(dbo.GetSeconds(InTime), dbo.GetSeconds(OutTime)) 'Overtime',
(dbo.GetSeconds(OutTime) - dbo.GetSeconds(InTime) -
dbo.GetOvertime(dbo.GetSeconds(InTime), dbo.GetSeconds(OutTime))) 'Worktime',
FROM YourTable
It's a bit involved - as I said, if you'd be on SQL Server 2008 and using the TIME data type, things would be a whole lot easier!
Marc

Answer 4

You could use substring and dateadd to convert the '090000' to a real datetime field. Then you can use CASE and DATEDIFF to split work and overtime. The final formatting can be done with CONVERT. Here's an example:
select
case when outtime-intime > '9:00:00' then '09:00:00'
else convert(varchar(30), outtime-intime, 108)
end as WorkTime,
case when outtime-intime <= '9:00:00' then '00:00:00'
else convert(varchar(30), outtime-intime-'9:00:00', 108)
end as OverTime
from (
select
dateadd(hh,cast(substring('090000',1,2) as int),0) +
dateadd(mi,cast(substring('090000',3,2) as int),0) +
dateadd(ss,cast(substring('090000',5,2) as int),0) as InTime,
dateadd(hh,cast(substring('180500',1,2) as int),0) +
dateadd(mi,cast(substring('180500',3,2) as int),0) +
dateadd(ss,cast(substring('180500',5,2) as int),0) as OutTime
) vw
This will print:
09:00:00 00:05:00

Answer 5

Here is code for SQL server 2000. 2005+ could do it without subquery using cross join.
Select DateAdd(mi, (Case When bef<0 Then bef else 0 end + Case When aft<0 Then aft else 0 end), diff) as WorkTome,
DateAdd(mi, (Case When bef>0 Then bef else 0 end + Case When aft>0 Then aft else 0 end), 0) as OverTime
From (
Select outTime-inTime as diff,
DateDiff(mi,t.inTime,'09:00') as bef,
DateDiff(mi,'18:00',t.outTime) as aft
From Table t ) as a
If Your inTime and outTime columns hase date part too, the query is slightly different:
Select DateAdd(mi, (Case When bef<0 Then bef else 0 end + Case When aft<0 Then aft else 0 end), diff) as WorkTome,
DateAdd(mi, (Case When bef>0 Then bef else 0 end + Case When aft>0 Then aft else 0 end), 0) as OverTime
From (
Select outTime-inTime as diff,
DateDiff(mi, DateAdd(Day,-DateDiff(Day, 0, t.inTime), t.inTime),'09:00') as bef,
DateDiff(mi,'18:00',DateAdd(Day,-DateDiff(Day, 0, t.OutTime), t.OutTime)) as aft
From #t t ) as a

Answer 6

I missed type of inTime and outTime.
Here is the version for varchar
Missed that, but you just have to do Cast(inTime as datetime) .
Use the first of previous 2 queries:
Select DateAdd(mi, (Case When bef<0 Then bef else 0 end + Case When aft<0 Then aft else 0 end), diff) as WorkTome,
DateAdd(mi, (Case When bef>0 Then bef else 0 end + Case When aft>0 Then aft else 0 end), 0) as OverTime
From (
Select Cast(t.outTime as datetime)-Cast(t.inTime as datetime) as diff,
DateDiff(mi,Cast(t.outTime as datetime),'09:00') as bef,
DateDiff(mi,'18:00',Cast(t.outTime as datetime)) as aft
From Table t ) as a