ClearCase: Find files having exactly one specific label and not more - clearcase

Question

I'd like to find files in ClearCase that are labeled with a specific label but that do not have any other labels set.
For example, if I have files labeled like this:
file1 LBL_A, LBL_B
file2 LBL_A
I'd like to have a query that gives me just file2 and not file1.
Is there a way to do this with cleartool find? If this is not possible to do with a single query, I'd also be happy for any ideas how to do this in several steps (I'll be calling cleartool from a perl script, so it will be easy to save lists of files temporarily and run further commands on them).
Thanks a lot in advance!
Jan

Answer 1

Assuming LBL_A is the (only) label you want running
cleartool find /some/dir -version 'lbtype(LBL_A)' -print | xargs cleartool describe -fmt "%n: %l"
should give
file1: (LBL_A, LBL_B)
file2: (LBL_A)
as output which you then can check in your perl script or filter through sed -n 's/\(.*\): (LBL_A)/\1/p' (assuming no colons in filenames).
Update: As VonC correctly points out, the command above will fail for files with spaces in. To handle that run as:
cleartool find ... -print | tr '\012' '\000' | xargs -0 cleartool ....
which will translate newlines into ascii null and then have xargs use that as delimiter.

Answer 2

You can do this directly without having to pipe:
cleartool find . -ver "lbtype(LBL_A) && !lbtype(LBL_B)" -print

Answer 3

hlovdal's answer illustrates that, in this case, you have to find more elements than you need, and then filter them (despite all the ClearCase find features).
Note:
cleartool find . -type f -element 'lbtype_sub(LBL_A)' -print
could give you directly the elements (and not the version which may not be interesting in this case). You can find the version with -version and a format directive as explained below.
With the help of fmt_ccase, you can tailor the output to get precisely what your perl script will need to go on:
cleartool find . -type f -element 'lbtype_sub(LBL_A)' -exec 'cleartool describe -fmt "%En %Cl\n" \"$CLEARCASE_XPN\"' | grep -v ","
-fmt "%En %l\n" will display the full path of the element (instead of the version: /a/b/myFile##/main/myVersion) => /a/b/myFile'. the '\n` ensure one result per line.
-version and -fmt "%n %l\n" would display the version
\"$CLEARCASE_XPN\": the double quotes arount the extended path of the version found ensure a file with spaces in its name will still work.
grep -v ",": if there is any comma, that means "more than one label"
%Cl: avoid displaying the all list of labels. Anyway, if there are more than one, you are not interested!
So, for finding the exact version:
cleartool find . -type f -version 'lbtype_sub(LBL_A)' -exec 'cleartool describe -fmt "%n %Cl\n" \"$CLEARCASE_XPN\"' | grep -v ","|awk '{sub(/ \(.*/,"");print}'
Note:
The above works with unix syntax. The windows syntax would be:
cleartool find . -type f -element "lbtype(LBL_A)" -exec "cleartool describe -fmt \"%n %Cl\n\" \"%CLEARCASE_XPN%\"" | grep -v "," | gawk "{gsub(/ \(.*,"");print}"
, which would list the version of files with only one (correct) label.
awk '{sub(/ \(.*/,"");print}' will transform "myFile##/main/myVersion (LBL_A)" into "myFile##/main/myVersion"