I'm a little confused by these two terms: "Legacy Distinguished Name"(Legacy DN) and "Distingushed Name"(DN).
The first term Legacy DN seems only for Exchange, while the latter DN is only mentioned for Active Directory.
They are obviously not in same format:
DN is like: CN=Morgan Cheng, OU= SomeOrg, DC=SomeCom, DC=com
LegacyDN is like: /o=SomeDomain/ou=SomeGroup/cn=Recipients/cn=Morgan Cheng
I am still not clear what exactly the differce is. Are they two totally differnt stuff? or just same info represented in two different forms?
And, why is it called "Legacy"? If it is legacy, something must be new, right?
Hope some AD and Exchang experts can give me some inputs.
In Exchange 5.5, Exchange was assigning distinguished names to accounts and mailboxes (Obj-Dist-Name). When Active Directory came along, Exchange 2000 and later would use its distinguished names instead. In order to preserve backwards compatibility, migration from Exchange 5.5 to Exchange 2000 carried over the old DNs into the legacyExchangeDN attribute of ActiveDirectory.
Some applications continue to refer to Obj-Dist-Name. To preserve compatibility with these applications, later exchange versions synthesize a legacyExchangeDN value even for objects that have not been migrated from Exchange 5.5. The RUS automatically sets it to some value, apparently to the same value as the distinguishedName in your case.
The "new" way (since 2000) is to refer to objects by distinguished name, not Obj-Dist-Name.
Related
For authentication in Jitsi Meet, we would like to read out a Windows AD group with an ldap query. Unfortunately our ldap query does not work.
LDAP_URL=ldaps://server.domain.local:636/
LDAP_BASE=DC=domain,DC=local
LDAP_BINDDN=CN=bind_user,OU=Administrative Accounts,OU=Benutzer,DC=domain,DC=local
LDAP_BINDPW=*
LDAP_FILTER= (&(|objectclass=user))(|(memberof=CN=group,OU=Jitsi,OU=Sicherheit,OU=Gruppen,DC=domain,DC=local)
(primaryGroupID=4989))
The error must be due to the filter, it works with the filter LDAP_FILTER = (sAMAccountName =% u).
Can you tell me what is wrong with our query.
A few things stand out to me:
The | in front of objectClass should not be there.
You have two closing parentheses after the objectClass condition, but the second one should be moved to the end of the whole query.
Oddly, objectClass=user will actually end up including other objects than just user accounts (like computer accounts). If you want to filter to only user objects, you have to use both (objectClass=user)(objectCategory=person). But that would only matter if you have other types of objects as members of that group.
Maybe this is just an error with pasting into the question, but there is a line break before (primaryGroupID=
I've never used Jitsi, but it may or may not like the space after LDAP_FILTER=. The other examples I see online don't show a space there.
It should look like this:
LDAP_FILTER=(&(objectclass=user)(objectCategory=person)(|(memberof=CN=group,OU=Jitsi,OU=Sicherheit,OU=Gruppen,DC=domain,DC=local)(primaryGroupID=4989)))
That means: find all user objects that are either members of that group, or have a primary group ID of 4989.
I have a guid which Sysinternals tools named Sysmon left.
It looks like this.
3/18 C591B94E-4BDD-5AAE-0000-001073B13706
4/4 C591B94E-1BFA-5AC5-0000-0010E76F3903
4/29 C591B94E-A33F-5AE5-0000-001074CA4C26
5/2(different windows account) C591B94E-E23B-5AE9-0000-0010DD40EF32
5/2(on the virtual machine) A15730FB-E3DA-5AE9-0000-0010AB2C0800
It's generated when the process is created(Event id 1) in my computer on different days and different environment.
And I Found the uuid format (https://en.wikipedia.org/wiki/Universally_unique_identifier)
xxxxxxxx-xxxx-Mxxx-Nxxx-xxxxxxxxxxxx(M indicate the UUID version, and the one to three most significant bits of digit N indicate the UUID variant)
According to this, my 3/18 example is C591B94E-4BDD-5AAE-0000-001073B13706. It means M is 5, N is 0, In other words, UUID version is 5, variant is 0. It means It's SHA-1 Hash Value(Version 5) and Variant is 0.
I really wonder what the other number does mean. Because the sysmon's documents says that guid is helpful for correlation BUT they never explain what does this number mean.
I can guess the first group is related to PC information. because only when I chanaged the PC(5/2 on the virtual machine) the first group is changed(C591B94E -> A15730FB). So I thought It's related to Mac or IP address. But even if I changed the MAC and IP address, It stayed A15730FB or C591B94E.
I'm sure the second group is related to time.
But I can't figure out what does this exactly mean.
The GUID does not specifically mean anything in itself. Its purpose is to allow you to correlate and filter process events when Windows reuses process IDs (in this way you can think of it as a completely unique process ID).
From: https://learn.microsoft.com/en-us/sysinternals/downloads/sysmon
"Includes a process GUID in process create events to allow for correlation of events even when Windows reuses process IDs."
I am trying to get some user attributes from Active Directry using Windows LDAP API. I am using:
Active Directory Version: The one that comes with Windows Server 2012
LDAP version: 3
Wldap32.lib version: The one that comes with Windows 10 x64
Eg:
PCHAR myAttributes[4];
myAttributes[0] = "DistinguishedName";
myAttributes[1] = "DisplayName";
myAttributes[2] = "PasswordExpired";
myAttributes[3] = "mail";
ldap_search_s(
myLdapConnection, // Ldap connection
myDomain, // DN to start search
LDAP_SCOPE_SUBTREE, // Scope
myFilter, // Filter
myAttributes, // Retrieve list of attributes
0, // Get both attributes and values
&mySearchResult // [out] Search results
);
It returns DistinguishedName, DisplayName and mail attributes, but does not reuturn the PasswordExpired attribute.
I queried with some other attributes and it looks like it does not return attributes with boolean values as well as the EmailAddress attribute.
Why does it not return PasswordExpired attribute?
What about EmailAddress ?
Is there a difference between EmailAddress and mail ?
There is no PasswordExpired LDAP attribute in Active Directory. To build your query look at this URL for attribute names in standard Active Directory schema https://msdn.microsoft.com/en-us/library/ms675090(v=vs.85).aspx. To check if password for given account is expired you'll need to check userAccountControl attribute, which is actually value storing flags of different states of user account https://msdn.microsoft.com/en-us/library/ms680832(v=vs.85).aspx. There is IADsUser interface that will translate this all for you in case you don't have to stick just to LDAP https://msdn.microsoft.com/en-us/library/aa746343(v=vs.85).aspx
You will find current primary email address in mail attribute. There is no EmailAddress LDAP attribute, unless you meant E-mail-Addresses which is CN for the same schema attribute as mail, so no difference there.
See above. In general if you do not have compelling reason to stick just to C/LDAP I'd recommend you to use .Net Framework instead. Otherwise you have a lot of work ahead of you - not just interpreting bit flags like in case of password expiration but possibly also with different authentication methods, different structures capturing time and date, accounting for timezones, UTF, chasing referrals and other stuff you might need depending on complexity of what you want to achieve. You will be productive much faster in .Net Framework. See DirectoryServices https://msdn.microsoft.com/en-us/library/mt481534(v=vs.110).aspx namespace or Security namespace https://msdn.microsoft.com/en-us/library/mt481561(v=vs.110).aspx for details.
I'm trying to retrieve user information in Active Directory, but am finding some things to be poorly documented. For example, the LDAP connection strings I have seen contain some keywords that I don't know the meaning of. Here's a sample:
LDAP://ofmdcoly302.ofm.wa.lcl/ou=employees,dc=ofm,dc=wa
What are the keywords "ou" and "dc" supposed to signify? In our case "ou=employees" seems to identify a particular AD node. However when I try to do a .FindAll() on the above directory entry, I get "A referral was returned from the server". I guess that means it couldn't find what I was looking for, but it might be available somewhere else? In one place I read "A referral is AD's way of saying, 'this object probably exists in another domain'".
What are "ou" and "dc" supposed to mean? And if I had this A/D structure, how would I code the LDAP connetion string to retrieve information in the "AR" node:
ou and dc are not keywords, they are attributes, "organizational unit" and "domain component", respectively. Attributes are defined in the directory server schema. Attributes are gathered together into entries, of which the distinguished name is the primary key.
Taken in this context, ou and dc are "distinguished name components", together comprising a "distinguished name", which is the aforementioned primary key of an LDAP entry. ou=employees,dc=ofm,dc=wa is a distinguished name composed of the various relative distinguished name components.
This entry has two mistakes: it's not using root (dc=lcl), you also skipped one ou, should be ou=employees,ou=Users - OFMGOV,dc=ofm,dc=wa,dc=lcl
TBH if your really want to understand this notation I would suggest using ADSI Edit instead of ADUC that you probably use ATM - it will show you path the same way, so it will be easier to translate. It will also prevent you from shooting yourself in a foot with special containers like 'CN=Users' and 'CN=Computers':
For the OU you have highlighted it would most likely be:
ou=AR,ou=Citrix,ou=Users - OFMGOV,dc=ofm,dc=wa,dc=lcl
This is directly from a tutorial online, and I get a top down level design error, help?
employee(193,'Jones','John','173 Elm St.','Hoboken','NJ',
12345,1,'25 Jun 93',25500).
employee(181,'Doe','Betty','11 Spring St.','Paterson','NJ',
12354,3,'12 May 91',28500).
employee(198,'Smith','Al','2 Ace Ave.','Paterson','NJ',
12354,3,'12 Sep 93',27000).
Given these basic relations (also called extensional relations), we can define other relations using Prolog procedure definitions to give us answers to questions we might have about the data. For example, we can define a new relation containing the names of all employees making more than $28,000:
well_paid_emp(First,Last) :-
employee(_Num,Last,First,_Addr,_City,_St,_Zip,_Dept,_Date,Sal),
Sal > 28000.
It could be that you are using a Prolog system which shows a singleton warning for well_paid_emp/2.
Not all Prolog systems allow _<Capital><Rest> as singletons, i.e. variables that occur only once in a rule.