input string through scanf - c

Question

i wanted to ask is there way to input blank in string through scanf,
i am using this [^\n] to input what so ever excluding newline .is it correct ?but is creating lot of problem as it seems to be stored in the input buffer.what is the best way to input string .both gets and fgets are creating lot of problems,
while(strcmp(buf,"quit"))
{
scanf("%*[^\n]",buf);
n=send(connected,buf,strlen(buf),0);
if(n<0)
{
perror("send");
printf("error sending");
exit(1);
}
//printf("server has send\n");
n=recv(connected,buf,100,0);
if(n<0)
{
perror("recv");
printf("error recieving");
exit(1);
}
//printf("waiting to recieve something\n");
buf[n]='\0';
printf("client:%s\n",buf);
}
this is creating infinite loop the same thing is repeated again and again.

Answer 1

A far better way to read a line of input is
char line[128]; /* Or whatever. */
while(fgets(stdin, line, sizeof line) != NULL)
{
/* Filter out whitespace before checking tokens. */
}

Answer 2

If all you are having trouble with is empty lines, use strcmp("\n", buffer) == 0.
The regexp you posted won't work very well because C will translate the '\n' char in "%*[^\n]" to a literal newline. To have it work better you need to scape the slash: "%*[^\\n]".
However, it seems the trouble is also with the reading, i recommend you use a better function for that.
I have used the following code before to read sequential lines of arbitrary size from a file.
Couple of notes, though:
The returned buffer needs to be free()d after you are done with it
The code wastes a couple of bytes every iteration, but this is not really noticeable unless BUFFER_SIZE very small in comparision to the length of the lines.
The code, however, guarantees that one full line will be read from the FILE * and it will end in '\n'.
/*
* Initial size of the read buffer
*/
#define DEFAULT_BUFFER 1024
/*
* Standard boolean type definition
*/
typedef enum{ false = 0, true = 1 }bool;
/*
* Flags errors in pointer returning functions
*/
bool has_err = false;
/*
* Reads the next line of text from file and returns it.
* The line must be free()d afterwards.
*
* This function will segfault on binary data.
*/
char *readLine(FILE *file){
char *buffer = NULL;
char *tmp_buf = NULL;
bool line_read = false;
int iteration = 0;
int offset = 0;
if(file == NULL){
fprintf(stderr, "readLine: NULL file pointer passed!\n");
has_err = true;
return NULL;
}
while(!line_read){
if((tmp_buf = malloc(DEFAULT_BUFFER)) == NULL){
fprintf(stderr, "readLine: Unable to allocate temporary buffer!\n");
if(buffer != NULL)
free(buffer);
has_err = true;
return NULL;
}
if(fgets(tmp_buf, DEFAULT_BUFFER, file) == NULL){
free(tmp_buf);
break;
}
if(tmp_buf[strlen(tmp_buf) - 1] == '\n') /* we have an end of line */
line_read = true;
offset = DEFAULT_BUFFER * (iteration + 1);
if((buffer = realloc(buffer, offset)) == NULL){
fprintf(stderr, "readLine: Unable to reallocate buffer!\n");
free(tmp_buf);
has_err = true;
return NULL;
}
offset = DEFAULT_BUFFER * iteration - iteration;
if(memcpy(buffer + offset, tmp_buf, DEFAULT_BUFFER) == NULL){
fprintf(stderr, "readLine: Cannot copy to buffer\n");
free(tmp_buf);
if(buffer != NULL)
free(buffer);
has_err = true;
return NULL;
}
free(tmp_buf);
iteration++;
}
return buffer;
}

Answer 3

You can also use getline() if your development environment supports it

Answer 4

There are two problems with scanf("%*[^\n]",buf);:
The asterisk in the specifier causes value to be scanned, but not stored.
It scans up until the next newline character, but doesn't consume that character. That means every call after the first one will read nothing.

Answer 5

I think the scanf you're looking for is:
scanf("%[^\n]%*c", buf);
The %[^\n] gets your string, the %*c ignores the newline.
But, this is literally what you get if you google "how not to read a string in c"
Non-blocking input is something else entirely. You might google "cbreak mode." But, that's a unix-y terminal-y thing, and if you're on Windows, that probably doesn't make sense. X/Gtk/Qt will have other ways of doing that sort of thing.