What is the suffix used for long long constants - c

If i want to use something like below in a C code:
if(num < 0x100000000LL)
I want the comparison to happen on a long long constant, but suffix LL doesn't work in MSVC6.0 , but it works in MS Visual Studio 2005.
How can i get it working in MSVC 6.0?
-Ajit

AFAIK, long long isn't supported in MSVC 6.0.
For example, have a look at this discussion thread. Perhaps, __int64 works instead. Anyway, I wouldn't know which other suffix to use.
EDIT: __int64 seems to work and for the supporting functions, it seems that no suffix is needed at all. Have a look here, for example. There's also some workaround at the end of this page.

The long long type was standardized in the 1999 ISO C Standard, and is expected to be standardized in C++ this year or next (whenever the standard is finalized). Like all of these standard features, there have been early adopters and late adopters. Language standards committees are usually reluctant to include things that haven't been tried before.
Visual C 6.0 was released in 1998, and therefore predates any standard with long long in it.

I don't have a copy of VC 6.0 to check, but does i64 work? (e.g. 12i64)

Related

What is wrong with printf("%llx")?

I have this piece of code that is challenging all my knowledge of C.
Here I have :
int main(void){
unsigned long long int massage ;
scanf("%llX", &massage); //input: 0x1234567890abcdef
printf("%llX", massage);
return 0;
}
On my "64bit - Corei5 - Fedora - GCC" it prints out exactly what I fed it. but on my buddy's system (32bit, MS XP, MinGW) it prints 90ABCDEF. I don't understand why. does anyone know?
BTW: sizeof(unsigned long long int) on his system is 8.
The issue is a discrepancy between what the compiler believes (as reflected in sizeof: sizeof(unsigned long long int) is evaluated at compile-time) and what the run-time library believes (as reflected in printf: the printf function is called at run-time, so that's when its format-specifiers take effect).
According to "C99" in the MinGW documentation:
GCC does not include a C runtime library. This is supplied by the platform. The MinGW port of GCC uses Microsoft's original (old) Visual C runtime, MSVCRT, which was targeted by Microsoft Visual Studio 6 (released in 1998).
[…]
Because MinGW relies on MSVCRT, it has many of the same limitations and quirks with compatibility as Visual Studio 6. You should assume that MinGW applications cannot rely on C99 behaviour, only on C89. For example, the newer format characters in printf like %a and %ll are not supported, although there exists a workaround for %ll.
(The workaround that it mentions is to use I64 instead of ll: so, %I64X. Annoyingly, at least on my system, GCC will issue a warning when it sees that in a literal format-string, because it assumes it'll have a better run-time library.)
The Windows C library uses "%I64d", not "%lld", to print arguments of
type "long long".
Ref: http://gcc.gnu.org/ml/gcc-patches/2004-11/msg01966.html

Should I use ANSI C (C89)?

It's 2012. I'm writing some code in C. Should I be still be using C89? Are there still compilers that do not support C99?
I don't mind using /* */ instead of //.
I'm not sure about C89 forbids mixing declarations and code. I'm kind of leaning towards the idea that it's actually more readable to have all the declarations in one place, and if it isn't, the function is too long.
VLAs look useful but I haven't needed them yet.
Should I stick with C89 if I don't have a compelling reason not to? Are there other things I haven't considered?
Unless you know that you cannot use a C99-compatible compiler (the Visual Studio C compiler is the most prominent candidate) there is no good reason for not using the nice things C99 gives you.
However, even if you need to support that compiler you can use some C99 features - just not all of them.
One feature of C99 that is incredibly handy is being able to do for(int i = ...) instead of having to declare your loop variable on top of the function - especially since C actually has a block scope. That's the kind of declaration where having it on top really doesn't improve the readability.
There is a reason (or many) why C89 was superseded by C99. If you know for sure that no C99 compiler is available for your particular piece of work (unlikely unless you are stuck with Visual Studio which never supported C officially anyway), then you need to stay with C89 but otherwise you should certainly put yourself in a position where you can benefit from the last 20+ years of improvement. There is nothing inherently slower about C99.
Perhaps you should even consider looking at the newest C11 standard. There has been some important fixes for dealing with Unicode that any C programmer could benefit from (other changes in the standard are absolutely minimal)...
Good code is a mixture of performance, scalability, readability, and maintainability.
In my opinion, C99 makes code easier to read and maintain. Very, very few compilers don't support C99, so I say go with it. Use the tools you have available, unless you are certain you will need to compile your project with a compiler that requires the earlier standard.
Check out these links to learn more about the advantages to C99:
http://www.kuro5hin.org/?op=displaystory;sid=2001/2/23/194544/139
http://en.wikipedia.org/wiki/C99#Design
Note that C99 also supports library functions such as snprintf, which are very useful, and have better floating point support. Also, I find macros to be extremely helpful, especially when working with math-intensive applications (like cryptographic algorithms)
I disagree with Paul R's "bottom line" comment. There are multiple cases where C89 is advantageous for portability.
Targeting embedded systems, which may or may not have compilers supporting C99:
https://groups.google.com/forum/#!topic/comp.arch.embedded/WNvhw3T_9pI%5B1-25%5D
Targeting the TinyCC compiler, as might be required in a restricted environment where installing a gigantic toolchain is either impractical or not allowed. (TCC is no longer being developed, and Bellard's last statement as to ISOC99 support was that it was "heading towards" full compliance.)
Supporting dynamic compilation via libtcc (see above).
Targeting MSVC, as others have noted.
For source-compatibility with projects that may be required by their company to use the C89 standard. This is especially relevant if you're writing an open source library, and want to maximize its application in some industry.
As cegfault noted, some of the C99 features as listed on Wikipedia can be very useful, but none I would consider indispensable if your priority is portability, or any of the above reasons apply.
It appears Microsoft hasn't budged on C99 compliance. SimonRev from Beijer Electronics commented on a related MSDN thread in November 2016:
In broad strokes, the only parts of the C99 compiler that were
implemented are those parts that they needed to keep the C++ compiler
up to date.
Microsoft has done basically nothing to the C compiler since VC6, and
they haven't made much secret that C++ is their vision of the future
of native code, not C.
In conclusion, if you want portability for embedded or restricted systems, dynamic compilation, MSVC, or compatibility with proprietary source code, I would say C89 is advantageous.

trying to use '#include <stdbool.h>' in VS 2010

I'm trying to use the stdbool.h library file in a C program. When I try to compile, however, an error message appears saying intellisense cannot open source file stdbool.h.
Can anyone please advise how I would get visual studio to recognise this? Is this header file even valid? I'm reading a book on learning C programming.
typedef int bool;
#define false 0
#define true 1
works just fine. The Windows headers do the same thing. There's absolutely no reason to fret about the "wasted" memory expended by storing a two-bit value in an int.
As Alexandre mentioned in a comment, Microsoft's C compiler (bundled with Visual Studio) doesn't support C99 and likely isn't going to. It's unfortunate, because stdbool.h and many other far more useful features are supported in C99, but not in Visual Studio. It's stuck in the past, supporting only the older standard known as C89. I'm surprised you haven't run into a problem trying to define variables somewhere other than the beginning of a block. That bites me every time I write C code in VS.
One possible workaround is to configure Visual Studio to compile the code as C++. Then almost everything you read in the C99 book will work without the compiler choking. In C++, the type bool is built in (although it is a 1-byte type in C++ mode, rather than a 4-byte type like in C mode). To make this change, you can edit your project's compilation settings within the IDE, or you can simply rename the file to have a cpp extension (rather than c). VS will automatically set the compilation mode accordingly.
Modern versions of Visual Studio (2013 and later) offer improved support for C99, but it is still not complete. Honestly, the better solution if you're trying to learn C (and therefore C99 nowadays) is to just pick up a different compiler. MinGW is a good option if you're running on Windows. Lots of people like the Code::Blocks IDE
Create your own file to replace stdbool.h that looks like this:
#pragma once
#define false 0
#define true 1
#define bool int
In Visual Studio 2010 I had an issue using typedef int bool; as suggested elsewhere. IntelliSense complained about an "invalid combination of type specifiers." It seems that the name "bool" is still special, even though it's not defined.
Just as a warning, on x64 platforms, VS2017 (I'm not sure about previous versions) defines bool as a value of 1 byte on C++ (e.g. a char). So this
typedef int bool;
could be really dangerous if you use it as an int (4 bytes) in C files and as a native bool in C++ (1 byte) (e.g. a struct in a .h might have different sizes depending if you compile it with C or C++).

Which version of C is more appropriate for students to learn- C89/90 or C99?

I'm looking into learning C basics and syntax before beginning Systems Programming next month. When doing some reading, I came across the C89/99 standards. According to Wikipedia,
C99 introduced several new features,
including inline functions, several
new data types (including long long
int and a complex type to represent
complex numbers), variable-length
arrays, support for variadic macros
(macros of variable arity) and support
for one-line comments beginning with
//, as in BCPL or C++. Many of these
had already been implemented as
extensions in several C compilers.
C99 is for the most part backward
compatible with C90, but is stricter
in some ways; in particular, a
declaration that lacks a type
specifier no longer has int
implicitly assumed. A standard macro
STDC_VERSION is defined with value 199901L to indicate that C99 support
is available. GCC, Sun Studio and
other compilers now support many or
all of the new features of C99.
I borrowed a copy of K&R, 2nd Edition, and it uses the C89 standard. For a student, does the use of C89 invalidate some subjects covered in K&R, and if so, what should I look out for?
There is no reason to learn C89 or C90 over C99- it's been very literally superseded. It's easy to find C99 compilers and there's no reason whatsoever to learn an earlier standard.
This doesn't mean that your professor won't force C89 upon you. From the various questions posted here marked homework, I get the feeling that many, many C (and, unfortunately, C++) courses haven't moved on since C89.
From the perspective of a starting student, the chances are that you won't really notice the difference- there's plenty of C that's both C99 and C89/90 to be covered.
Use the C99 standard, it's newer and has more features. Particularly useful may be the bool type in <stdbool.h> and the int32_t etc. family of types; the latter prevents a lot of unportable code that relies on ints having a certain size. AFAIK, it doesn't invalidate K&R, though some example programs may be written in a slightly different style now.
Note that some compilers still don't support C99 properly. I believe that GCC still requires the use of a -std=c99 flag to enable it; many Unix/Linux systems have a c99 command that wraps GCC and enables C99.
The same goes for many university professors. I surprised mine by handing in a program that used bool in my freshman year. He'd never heard of that type in C :)
While I generally agree with the others, it is worth noting that K&R is such a good book that it might be worth learning C from it and then updating your knowledge as you read about the C99 standard.
If you are at student level you probably won't even notice the differences.
Yes, it's a bit odd that you can get a loud consensus that K&R is a great C book, and also a loud consensus that C99 is the correct/current/best version of C. The two positions are incompatible - even if K&R is the best book available to learn "C meaning C99", that just implies the rest are rubbish, or are also hopelessly outdated.
I would advise learning and using C99, but keeping an eye to C89 as you do so. If you use a compiler that has both C89 and C99 compliant modes, then you can write a few bits of C89 just to get an idea of the differences. Then if you ever need to write some code intended to be portable to places that C99 doesn't go, you'll know what to do. If you never have to write any such code, then you've wasted perhaps a day.
Writing C89 properly is actually surprisingly difficult, because getting hold of a copy of the C89 standard is difficult. So, C99 if you can, C89 if for some odd reason you have to, and have some awareness what the difference is. Maybe use K&R to cover the very basics, but get a look at some idiomatic C99 as soon as possible.
As for specific issues to be aware of when reading K&R: there's a list of major changes in the foreword of the standard (http://www.open-std.org/jtc1/sc22/wg14/www/docs/n1256.pdf), although the details aren't laid out there. A lot of them are new features added to C99, so it's not that K&R is wrong, it just may not always use the best tools for a given job. Some of them are quite fiddly things where you should probably consult the standard if you need the details anyway. The rest are things removed from C89, that usually a C99 compiler will tell you about as and when you try to use them.
As a student, that doesn't influence you so much. But if possible, you should find a new C book which covers C99
The term "C89" describes two very different languages:
The language that programmers in 1989 thought the Committee was describing in places where the Standard was ambiguous, and which supported features that were common in pre-existing implementations.
The language that the Committee has since decided that it wanted to have described, which threw compatibility with existing functionality out the
window.
C99 "clarifies" ambiguous parts of the standard by saying that they meant
to have the Standard interpreted in a way that would have broken a substantial
fraction of existing code and made it impossible to perform many tasks as
efficiently as they had been performed in C before 1989.
The right language to program in, for many applications, would be the superset of pre-Standard C, C89, C99, and C11. It's important, however, that anyone programming in that language be clear that they're using that language rather than a shrinking subset which favors speed over reliability.
While I think it's beneficial to know which features are more recent and less likely to be supported by obscure (or intentionally-broken, like MSVC) compilers, there are a few C99 features that you should absolutely use:
snprintf: This is the definitive function for safe and clean string assembly in C. If your compiler is missing it, you can either replace the whole printf subsystem (probably a good idea since most implementations with missing snprintf are also full of (often intentional) bugs in printf behavior), or wrap tmpfile/fprintf/fread/fclose.
stdint.h: If you need fixed-size types (16/32/64-bit), use the standard names int16_t, uint16_t, int32_t, etc. Do not invent your own, and absolutely don't use system-specific ones like INT64 or u32. It just makes your code ugly and hard to integrate and reuse. If your compiler is missing stdint.h, just drop in your own to define the types in terms of the correct-for-your-platform types.
Specifically uint64_t, in place of int foo[2]; or struct { int lo, int hi; } foo; or other hideous legacy hacks to work with 64-bit numbers. Any sane compiler even without C99 support has its own 64-bit types you can use to define int64_t and uint64_t.

Is C99 backward compatible with C89?

I'm used to old-style C and and have just recently started to explore c99 features. I've just one question: Will my program compile successfully if I use c99 in my program, the c99 flag with gcc and link it with prior c99 libraries?
So, should I stick to old C89 or evolve?
I believe that they are compatible in that respect. That is as long as the stuff that you are compiling against doesn't step on any of the new goodies. For instance, if the old code contains enum bool { false, true }; then you are in trouble. As a similar dinosaur, I am slowly embracing the wonderful new world of C99. After all, it has only been out there lurking for about 10 years now ;)
You should evolve. Thanks for listening :-)
Actually, I'll expand on that.
You're right that C99 has been around for quite a while. You should (in my opinion) be using that standard for anything other than legacy code (where you just fix bugs rather than add new features). It's probably not worth it for legacy code but you should (as with all business decisions) do your own cost/benefit analysis.
I'm already ensuring my new code is compatible with C1x - while I'm not using any of the new features yet, I try to make sure it won't break.
As to what code to look out for, the authors of the standards take backward compatibility very seriously. Their job was not ever to design a new language, it was to codify existing practices.
The phase they're in at the moment allows them some more latitude in updating the language but they still follow the Hippocratic oath in terms of their output: "first of all, do no harm".
Generally, if your code is broken with a new standard, the compiler is forced to tell you. So simply compiling your code base will be an excellent start. However, if you read the C99 rationale document, you'll see the phrase "quiet change" appear - this is what you need to watch out for.
These are behavioral changes in the compiler that you don't need to be informed about and may be the source of much angst and gnashing of teeth if your application starts acting strange. Don't worry about the "quiet change in c89" bits - if they were a problerm, you would have already been bitten by them.
That document, by the way, is an excellent read to understand why the actual standard says what it says.
Some C89 features are not valid C99
Arguably, those features exist only for historical reasons, and should not be used in modern C89 code, but they do exist.
The C99 N1256 standard draft foreword paragraph 5 compares C99 to older revisions, and is a good place to start searching for those incompatibilities, even though it has by far more extensions than restrictions.
Implicit int return and variable types
Mentioned by Lutz in a comment, e.g. the following are valid C89:
static i;
f() { return 1; }
but not C99, in which you have to write:
static int i;
int f() { return 1; }
This also precludes calling functions without prototypes in C99: Are prototypes required for all functions in C89, C90 or C99?
n1256 says:
remove implicit int
Return without expression for non void function
Valid C89, invalid C99:
int f() { return; }
I think in C89 it returns an implementation defined value. n1256 says:
return without expression not permitted in function that returns a value
Integer division with negative operand
C89: rounds to an implementation defined direction
C99: rounds to 0
So if your compiler rounded to -inf, and you relied on that implementation defined behavior, your compiler is now forced to break your code on C99.
https://stackoverflow.com/a/3604984/895245
n1256 says:
reliable integer division
Windows compatibility
One major practical concern is being able to compile in Windows, since Microsoft does not intend to implement C99 fully too soon.
This is for example why libgit2 limits allowed C99 features.
Respectfully: Try it and find out. :-)
Though, keep in mind that even if you need to fix a few minior compiling differences, moving up is probably worth it.
If you don't violate the explicit C99 features,a c90 code will work fine c99 flag with another prior c99 libraries.
But there are some dos based libraries in C89 like ,, that will certainly not work.
C99 is much flexible so feel free to migrate :-)
The calling conventions between C libraries hasn't changed in ages, and in fact, I'm not sure it ever has.
Operating systems at this point rely heavily on the C calling conventions since the C APIs tend to be the glue between the pieces of the OS.
So, basically the answer is "Yes, the binaries will be backwards compatible. No, naturally, code using C99 features can't later be compiled with a non-C99 compiler."
It's intended to be backwards compatible. It formalizes extensions that many vendors have already implemented. It's possible, maybe even probable, that a well written program won't have any issues when compiling with C99.
In my experience, recompiling some modules and not others to save time... wastes a lot of time. Usually there is some easily overlooked detail that needs the new compiler to make it all compatible.
There are a few parts of the C89 Standard which are ambiguously written, and depending upon how one interprets the rule about types of pointers and the objects they're accessing, the Standard may be viewed as describing one of two very different languages--one of which is semantically much more powerful and consequently usable in a wider range of fields, and one of which allows more opportunities for compiler-based optimization. The C99 Standard "clarified" the rule to make clear that it makes no effort to mandate compatibility with the former language, even though it was overwhelmingly favored in many fields; it also treats as undefined some things that were defined in C89 but only because the C89 rules weren't written precisely enough to forbid them (e.g. the use of memcpy for type punning in cases where the destination has heap duration).
C99 may thus be compatible with the language that its authors thought was described by C89, but is not compatible with the language that was processed by most C89 compilers throughout the 1990s.

Resources