Silverlight - Setting DataContext in XAML rather than in constructor? - silverlight

Question

How can I set the DataContext on my Grid in XAML, instead of in the constructor?
Here is how I do it in the constructor (LayoutRoot is the XAML Grid defined in the XAML):
this.LayoutRoot.DataContext = this.HPVM;
I would prefer to do it right in the XAML, but I do not know how to reference the HPVM object in XAML. HPVM is a public property on the USerControl class.
It works fine as listed above, but again, I just want to know how to properties of the UserControl class in XAML, rather than always having to do it in code.
Here is all the relevant code:
<UserControl x:Class="SilverlightApplication1.SLHolePattern" x:Name="HolePatternsControl"
xmlns="http://schemas.microsoft.com/client/2007"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:sys="clr-namespace:System;assembly=mscorlib"
xmlns:controls="clr-namespace:Microsoft.Windows.Controls;assembly=Microsoft.Windows.Controls"
xmlns:local="clr-namespace:SilverlightApplication1"
xmlns:GeoPatterns="clr-namespace:GeoPatterns"
Height="700">
<UserControl.Resources>
...
And here is my constructor where the DataContext is currently set:
namespace SilverlightApplication1
{
public partial class SLHolePattern : UserControl, INotifyPropertyChanged
{
public HolePatternsViewModel HPVM;
public SLHolePattern()
{
InitializeComponent();
this.HPVM=new HolePatternsViewModel();
this.LayoutRoot.DataContext = this.HPVM;
...more code here
}
It all works fine, but I just want to learn how to set the DataContext in XAML, not in code.

Answer 1

The answer Chris gave works just fine.
I have tested and it worked for me.
You can instantiate your class in XAML (within the UserControl.Resources) and
then bind the datacontext to a static resource.
Follow code:
<UserControl ...>
<UserControl.Resources>
<myNS:MyClass x:Name="TheContext" x:Key="TheContext"></myNS:MyClass>
</UserControl.Resources>
<Grid x:Name="LayoutRoot" Background="White" DataContext="{StaticResource TheContext}" >
<TextBlock Text="{Binding Path=Field1}">
</TextBlock>
</Grid>
</UserControl>

Answer 2

The following monstrosity works in Silverlight 4
<UserControl
DataContext="{Binding HPVM, RelativeSource={RelativeSource Self}}">

Answer 3

<UserControl.DataContext>
<vm:ThisUCViewModel />
</UserControl.DataContext>

Answer 4

try something like this.....
<Grid DataContext="{Binding Path=HPVM}">
</Grid>
where HPVM is a public member of this--> your form etc.
Create the instance of your class in the xaml, by adding something like this to your resources section.... (don't forget to add your xmlns namespace)
<my:bogart x:Key="franken"/>
then, bind the data context to the static resource you just added....
<Grid x:Name="LayoutRoot" Background="White" DataContext="{StaticResource franken}">
<TextBox Background="Red" Foreground="White" Text="{Binding Path=sum}" />
</Grid>

Answer 5

In Silverlight 4, I was able to get this working by doing the following:
Give the Page/UserControl an x:Name="myPage"
In your control binding use normal Element bidning syntax. In my case I want to bind to an observable collection of objects in my code behind for my ItemsSource property:
<ComboBox
ItemsSource={Binding ElementName=myPage, Path=MyObservableObjectList, Mode=TwoWay}
I haven't tried this with DataContext but know you can do element to element binding for DataContext as I do this for Grids whose context is based on the selected item of some other drop down on the page.

Answer 6

This is not possible (It is possible in WPF with {Binding RelativeSource={RelativeSource Self}}, but Silverlight is more limited.
You have to do it through code.

Answer 7

<UserControl.Resources>
<ResourceDictionary>
<vm:YourModelx:Key="myModel"/>
</ResourceDictionary>
</UserControl.Resources>
<UserControl.DataContext>
<Binding Source="{StaticResource myModel}"/>
</UserControl.DataContext>