i have put refferal id in form input feild which is present in url - angularjs

I have created a referral link in my angular project which has carry a referral id when I copy that link and search on browser I want that referral number in the input field of the form on that page. Can anyone tell me the solution
i had with save this referal link in variable and display in interpolation but in form field referal link is not showing

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register form select user then automatically show user header id
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view function work but how to get form data in before submit in template

Algolia Autocomplete and display in result page on enter key or submit

I am looking for a solution with Algolia in React. I have a search bar where I am using autocomplete feature to load the result of products . Now when i click on submit button or Enter key i want to redirect to new result page where i want to display all the products with the available filters. As i seen most places it is using instantSearch where result loads on typing. Im looking for separate result page with filters and apply filter within the result page.

unable to reset the af:query panel search fields after page navigation

I've created a search page using default Named Criteria. I'm able to search and reset the search fields while being on the page. If I navigate to another page without clearing the search fields, the previous values are getting stored in the fields and unable to clear the fields with the reset button.
<af:query id="qryId1" headerText="Search" disclosed="true"
value="#{bindings.ImplicitViewCriteriaQuery.queryDescriptor}"
model="#{bindings.ImplicitViewCriteriaQuery.queryModel}"
queryListener="#{bindings.ImplicitViewCriteriaQuery.processQuery}"
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Drupal Webform - How to load values from form, filled in a previous page

Working on Drupal, I have a page with a form made with "Webform" module, containing several fields (text fields and sliders) and a "Submit" button.
When the user enters the information and presses the "Submit" button, another page is loaded with custom code into it.
The new page is devided into 2 parts - the first one contains new information(based on the user input from the previous page); the second one contains (block) the same form, used in the previous page.
Is there a way to load the values, filled in the form from the first page into the new page?
First of all you would need to make a custom module, with the help of
hook_form_alter
You would need to store the previous form's information in cookies with prefix
Drupal_visitor_
and then display it in the new page like:
$form['submitted']['FirstName']['#default_value'] =
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Thanks

How can i have a link field in a content type display a default text when the field is empty

How can i have a link field in a content type display a default text when the field is empty.
For now i have a field as a link - and the link is set to have a static title. This Works fine.
But i'd like to display a default title if the field is empty with no link (but still rendered as a link/button).
It's not a view - so i can't use "rewrite output if empty".
I'm a newbee to drupal - so please help
This shows what I've got so far:
http://1fb72c32b5e90467b795f388746f7501b3ad8021.web9.temporaryurl.org/tmp/link2.PNG
When the link field is empty the button doesn't show. Instead of not showing when empty I'd like it to show someting like this as default:
http://1fb72c32b5e90467b795f388746f7501b3ad8021.web9.temporaryurl.org/tmp/link3.PNG (the button "Bestil på tlf...")
By simply using Link module, i don't think this is possible. But, follow below steps in your environment and i think you might achieve the goal:
Make custom template file for the page (i think, its product details page)
In that template file, check whether the link is empty or not
If link is not empty, show the link. If link is empty, show your custom HTML.

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