Working on Drupal, I have a page with a form made with "Webform" module, containing several fields (text fields and sliders) and a "Submit" button.
When the user enters the information and presses the "Submit" button, another page is loaded with custom code into it.
The new page is devided into 2 parts - the first one contains new information(based on the user input from the previous page); the second one contains (block) the same form, used in the previous page.
Is there a way to load the values, filled in the form from the first page into the new page?
First of all you would need to make a custom module, with the help of
hook_form_alter
You would need to store the previous form's information in cookies with prefix
Drupal_visitor_
and then display it in the new page like:
$form['submitted']['FirstName']['#default_value'] =
$_COOKIE[$firstname];
Thanks
Related
I have created a referral link in my angular project which has carry a referral id when I copy that link and search on browser I want that referral number in the input field of the form on that page. Can anyone tell me the solution
i had with save this referal link in variable and display in interpolation but in form field referal link is not showing
I have a button in the table in the first page. When I click on the button, I want to save the panel Id and display on the next page. How can I call the data in angular? I'm desperately seeking for help since I'm stuck in there for almost a week now.
These are the images for my problem.
enter image description here
So this one is the first page, where there are buttons in each row.
After clicking Assign, it should show readonly data of ship name and panel name.
enter image description here
Regarding your issue, you should get the panel_id from params in the URL.
E.g.
In the routing of the assigning page, you just set the path:
{
path: 'assigning/:id',
component: <YourComponent>
}
So you can get the panel_id by using ActivatedRoute.
On click event of "Assign" button, you can pass the value to the ts component. In the ts file you can pass it via URL route as a parameter to the next page or store it in localStorage and read from the next page.
<button (click)="passValue(value)">Assign</button>
How can i save the textfields and checkboxes to the DB without reloading the page?
Just to click on the button and then its in the DB. Nothing more. I don't get it. This means when I have a textfield where I type in a content -> then click the button, the content from the textfield should be in the DB and should do nothing more (not reloading the page, or go to top for example).
I don't get it.
EDIT:
When I have a a <div> tag with the id="testid" in the standard create.gsp:
def create() {
def mytestInstance = new Mytest(params)
}
and the <g:remoteLink> which should save this part looks like:
<g:remoteLink class="button" name="myForm" update="testid"
url="[controller:'mytest', action: 'create']" value="....." />
That does not work because the page is refreshing or something like this and the things are not stored in the DB, plus they are not in the textfields any more.
Use <g:formRemote> or <g:submitToRemote> to do the form submission with an Ajax call.
You should be able to use the formRemote tag to send the data to a controller via Ajax
Edit
As it says on that page;
This tag also requires the use of either the <g:javascript/>(link) or <g:setProvider/>(link) tags. See the AJAX section of the user guide to find out more.
Have you done that?
I have a Grid for which I have a column formatted to a link. Once I click on a link that is being generated, this link will take me to a page for which the url looks like ?page=details&id=10. This works fine, so far.
On this details page I have another grid which displays child records, by adding the condition to the model of the grid addCondition("parent_id", "=", $_GET["id"]). This works well as well, my child records are being displayed based on the master record id that is being passed.
Now if I add a quickSearch on the grid from the details page, once I try to search, the id is not being passed in the url, so now my condition will be addCondition("parent_id", "=", null) because $_GET["id"] is null. The url that is being generated for the refresh is ?page=details&submit=agile_details_mvcgrid_quicksearch.
So the grid will display no results.
How can I fix this? I could put the value in the session, but it's really a good solution.
Please add the following at the top of your page:
$this->api->stickyGET('id');
This will preserve value of $_GET['id'] form that point on.
I have a problem here.
I bind a store on the pagingtoolbar which has more than one page. For example I change current page to the page 2, then I change the store content which has only one page by a search form . The grid loads the collect data, but the input item still shows that it's in page 2, where I want it to show 1 after I call the search event.
I don't want to use store.loadPage(1) because this will cause one more exchange between the server, can anyone helps me?
Try this:
grid.store.currentPage = 1;
grid.down('pagingtoolbar').onLoad();