I have a SQL query like
SET THIS_YEAR_END = '2022-11-01';
SET THIS_YEAR_START = DATEADD(DAY, -4*7+1, $THIS_YEAR_END);
SET LAST_YEAR_END = '2021-11-02';
SET LAST_YEAR_START = DATEADD(DAY, -4*7+1, $LAST_YEAR_END);
select end_date from (
select * from data
where DATE>= DATEADD(DAY, -27 * 7, $LAST_YEAR_START))
AND END_DATE BETWEEN CUST.END_DATE - 26 * 7 AND CUST.END_DATE - 7
I'm confused with this dateadd function in SQL. Can anyone please explain what exactly it's doing?
Here is the docs: https://docs.snowflake.com/en/sql-reference/functions/dateadd.html
Basically DATEADD is adding a specified value to a certain date. The first parameter is indicating the units of time that you want to add (e.g. DAY or MONTH), the second parameter specifies the number of units (e.g. number of days or number of months) and the third paramter is the date, to which you want to add something.
In your example in line 2 you are reducing THIS_YEAR_END by -4*7+1 (=-27) days.
Related
I've been working on some SQL code to measure efficiency in real-time for some production data. Here's a quick background:
Operators will enter in data for specific sub assemblies. This data looks something like this:
ID PO W/S Status Operator TotalTime Date
60129515_2000_6_S025 107294 S025 Completed A 38 05/08/2020
60129515_2000_7_S025 107294 S025 Completed A 46 05/08/2020
60129515_2000_8_S025 107294 S025 Completed A 55 05/08/2020
60129515_2025_6_S020 107295 S020 Completed B 58 05/08/2020
60129515_2025_7_S020 107295 S020 Completed B 47 05/08/2020
60129515_2025_8_S020 107295 S020 Completed B 45 05/08/2020
60129515_2000_1_S090 107294 S090 Completed C 33 05/08/2020
60129515_2000_2_S090 107294 S090 Completed C 34 05/08/2020
60129515_2000_3_S090 107294 S090 Completed C 21 05/08/2020
The relevant columns are the Operator, TotalTime and Date (note that the date is stored as varchar(50) because it plays nicer with Microsoft PowerApps that way).
What I need to do is:
Aggregate the sum of "TotalTime" grouped by Operator
Calculate the time elapsed based on a condition:
If between 7AM and 4PM, calculate the time elapsed since 7AM of the current day
If after 4PM, return the total time between 7AM and 4PM of the current day
Divide the SUM(TotalTime) by the TimeElapsed (AKA the first list item / second list item) in order to get a rough estimate of labor hours worked vs. hours passed in the day.
This calculation would change every time the query was ran. This will allow the Microsoft PowerApp that is pulling this query to refresh the efficiency measure in real time. I've taken a stab at it already - see below:
SELECT
md.Operator,
CASE
WHEN DATEADD(HOUR, -5, GETUTCDATE()) > CONVERT(DATETIME, CONVERT(DATE, DATEADD(HOUR, -5, GETUTCDATE()))) + '7:00' AND GETDATE() < CONVERT(DATETIME, CONVERT(DATE, DATEADD(HOUR, -5, GETUTCDATE()))) + '15:45'
THEN (SUM(isNull(md.TotalTime, 0)) + SUM(isNull(md.DelTime, 0))) * 1.0 / DATEDIFF(MINUTE, CONVERT(DATETIME, CONVERT(DATE, DATEADD(HOUR, -5, GETUTCDATE()))) + '7:00' , DATEADD(HOUR, -5, GETUTCDATE())) * 100.0
ELSE (SUM(isNull(md.TotalTime, 0)) + SUM(isNull(md.DelTime, 0))) / 420 * 100.0
END AS OpEfficiency
FROM
[Master Data] AS md
WHERE
md.[Date] = CONVERT(varchar(50), DATEADD(HOUR, -5, GETUTCDATE()), 101)
GROUP BY
md.Operator
Note: the DelTime is a different column regarding delay times. I am also converting back from UTC time to avoid any time zone issues when transferring to PowerApps.
However, this is horribly inefficient. I am assuming it is because the Date needs to be converted to datetime every single time. Would it work better if I had a calculated column that already had the date converted? Or is there a better way to calculate time elapsed since a certain time?
Thanks in advance.
There are a few things you can do to increase efficiency considerably. First, you want to make sure SQL can do a simple comparison when selecting rows, so you'll start by calculating a string to match your date on since your [Date] field is a string not a date.
Second, calculate the minutes in your shift (either 540 for a full shift or scaled down to 0 at 7 AM exactly) ahead of time so you aren't calculating minutes in each row.
Third, when summing for operators, use a simple sum on the minutes and calculate efficiency from that sum and your pre-calculated shift so far minutes.
One note - I'm casting the minutes-so-far as FLOAT in my example, maybe not the best type but it's clearer than other decimal types like DECIMAL(18,6) or whatever. Pick something that will show the scale you want.
My example uses a Common Table Expression to generate that date string and minutes-so-far FLOAT, that's nice because it fits in a direct query, view, function, or stored procedure, but you could DECLARE variables instead if you wanted to.
By filtering with an INNER JOIN on the [Date] string against the pre-calculated TargetDate string, I make sure the data set is pared down to the fewest records before doing any math on anything. You'll definitely want to INDEX [Date] to keep this fast as your table fills up.
All these together should give a pretty fast query, good luck
with cteNow as ( --Calculate once, up front - date as string, minutes elapsed as FLOAT (or any non-integer)
SELECT CASE WHEN 60*DATEPART(HOUR, GETUTCDATE())+DATEPART(MINUTE, GETUTCDATE()) > 60*21
--4PM in UTC-5, expressed in minutes
THEN CONVERT(float,(16-7)*60) --minutes in (4 PM-7 AM) * 60 minutes/hour
ELSE --Assume nobody is running this at 6 AM, so ELSE = between 7 and 4
CONVERT(float,60*DATEPART(HOUR, GETUTCDATE()) + DATEPART(MINUTE, GETUTCDATE()) - ((7+5)*60))
--Minutes since midnight minus minutes from midnight to 7 AM, shifted by
--UTS offset of 5 hours
END as MinutesToday --Minutes in today's shift so far
, FORMAT(DATEADD(HOUR,-5,GETUTCDATE()),'MM/dd/yyyy') as TargetDate --Date to search for
--as a string so no conversion in every row comparison. Also, index [Date] column
)
SELECT md.Operator, SUM(md.TotalTime) as TotalTime, SUM(md.TotalTime) / MinutesToday as Efficiency
FROM [Master Data] AS md INNER JOIN cteNow as N on N.TargetDate = md.[Date]
GROUP BY md.Operator, MinutesToday
BTW, you didn't make allowances for lunch or running before 7 AM, so I also ignored those. I think both could be addressed in cteNOW without adding much complexity.
I am comparing two dates in SQL Server and need following information in precise manner:
Input:
Start Date = 12/28/2015
End Date = 12/25/2020
Result returned (each piece in different column):
Days = 1825 (includes start/end date in calculation)
Years = 4
Months = 11
Days = 28
How many days in Start Month = 31 days (Because it is December)
Occupancy in Start Month = (because December has 31 days, it would be 4/31) = .12903225806
How many days in End Month = 31 days (Because it is December)
Occupancy in End Month = (because December has 31 days, it would be 25/31) = .8064516129
For 1-3, you can check https://www.w3schools.com/sql/func_sqlserver_datediff.asp. It's fairly simple, you can just use datediff and specify the unit of interest.
For 4, you can simply do day(Start Date) to get the date.
For 5 and 7, you can use:
SELECT DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,#myDate)+1,0)
to get the end of month date of the given date and use day() to get the day part of the datetime object.
For 6 and 8, it's just simple math, you get number of month in that month from 5 and 7, and then, if Start Date, then (day(eom(Start Date)) - day(Start Date) + 1) / day(eom(date) and if End Date, then day(End Date) / day(eom(End Date)).
I didn't give you the full code as I don't have SQL server running besides me. Hope it helps.
We assume that the week starts from Mon and ends at Sunday.
While trying to comparing with last year, how can we get the right dates?
For example, if i want to compare this week (10/23/2017 to 10/29/2017) with year same week (10/24/2016 to 10/30/2016)
I am setting 2 parameters in SSRS BeginDate and BeginDateLastYear . The value of BeginDate = 10/23/2017
How can i assume the value for BeginDateLastYear as a value precisely to the Monday of same week number in last year ( IN this case it should be 10/24/2016) ?
Currently i am trying to set the value of StartDate in last year like
BeginDateLastYear =DATEADD(DateInterval.Year,-1,Parameters!BeginDate.Value)
Also i tried to use
=DATEADD(DateInterval.Week,-52,Parameters!BeginDate.Value) , but not very sure will this work precisely to same week start date of last year
In reporting services you can use the following expression for BeginDateLastYear
= DATEADD(
DateInterval.WeekOfYear,
IIF(
DATEPART(DateInterval.WeekOfYear,DATEADD(DateInterval.WeekOfYear, -52 , Parameters!BeginDate.Value))<> DATEPART(DateInterval.WeekOfYear, Parameters!BeginDate.Value) ,
-53,
-52
) ,
Parameters!BeginDate.Value
)
Code logic:
If by going back 52 weeks the two week numbers do not match go back 53 weeks, else go back 52 weeks
In case you want to implement it in SQL without using the second parameter (SSRS has some issues on cascading parameters)
SET #BeginDateLastYear =
DATEADD(
wk,
CASE WHEN DATEPART(wk,DATEADD(wk, -52 , #BeginDate))<> DATEPART(wk,#BeginDate)
THEN -53
ELSE -52 END,
#BeginDate
)
I get an time difference value of 5.5 which should subtract 5 hours and 30 minutes from current date time .
select Dateadd(HH, -5.5,GETUTCDATE()),GETUTCDATE()
In output it only subtracts 5 hours .
I always get an value in form of this offset 5.5 or 13.5 likewise depending on the timezone..
Is this possible ???
I always get an value in form of this offset 5.5 or 13.5 likewise depending on the timezone..
Then you can multiply the value by 60 and use minute datepart
select Dateadd(MINUTE, -5.5 * 60,GETUTCDATE())
time arithmetic always works in whole units - use -330 minutes instead
select Dateadd(MINUTE, -330,GETUTCDATE()),GETUTCDATE()
the input to the function is intended to be an integer (whole number) - you may be finding that -5.5 is truncating off the decimal part
Yes this can be done. First, you need to convert your decimal offset into minutes. Then you can use DATEADD as before.
DECLARE #Offset DECIMAL(18, 2) = 5.5;
DECLARE #Mins INT = 60 * #Offset;
-- Offsetting by decimal time values.
SELECT
DATEADD(MINUTE, #Mins, GETDATE())
;
I am trying to sum INTERVAL. E.g.
SELECT SUM(TIMESTAMP1 - TIMESTAMP2) FROM DUAL
Is it possible to write a query that would work both on Oracle and SQL Server? If so, how?
Edit: changed DATE to INTERVAL
I'm afraid you're going to be out of luck with a solution which works in both Oracle and MSSQL. Date arithmetic is something which is very different on the various flavours of DBMS.
Anyway, in Oracle we can use dates in straightforward arithmetic. And we have a function NUMTODSINTERVAL which turns a number into a DAY TO SECOND INTERVAL. So let's put them together.
Simple test data, two rows with pairs of dates rough twelve hours apart:
SQL> alter session set nls_date_format = 'dd-mon-yyyy hh24:mi:ss'
2 /
Session altered.
SQL> select * from t42
2 /
D1 D2
-------------------- --------------------
27-jul-2010 12:10:26 27-jul-2010 00:00:00
28-jul-2010 12:10:39 28-jul-2010 00:00:00
SQL>
Simple SQL query to find the sum of elapsed time:
SQL> select numtodsinterval(sum(d1-d2), 'DAY')
2 from t42
3 /
NUMTODSINTERVAL(SUM(D1-D2),'DAY')
-----------------------------------------------------
+000000001 00:21:04.999999999
SQL>
Just over a day, which is what we would expect.
"Edit: changed DATE to INTERVAL"
Working with TIMESTAMP columns is a little more labourious, but we can still work the same trick.
In the following sample. T42T is the same as T42 only the columns have TIMESTAMP rather than DATE for their datatype. The query extracts the various components of the DS INTERVAL and converts them into seconds, which are then summed and converted back into an INTERVAL:
SQL> select numtodsinterval(
2 sum(
3 extract (day from (t1-t2)) * 86400
4 + extract (hour from (t1-t2)) * 3600
5 + extract (minute from (t1-t2)) * 600
6 + extract (second from (t1-t2))
7 ), 'SECOND')
8 from t42t
9 /
NUMTODSINTERVAL(SUM(EXTRACT(DAYFROM(T1-T2))*86400+EXTRACT(HOURFROM(T1-T2))*
---------------------------------------------------------------------------
+000000001 03:21:05.000000000
SQL>
At least this result is in round seconds!
Ok, after a bit of hell, with the help of the stackoverflowers' answers I've found the solution that fits my needs.
SELECT
SUM(CAST((DATE1 + 0) - (DATE2 + 0) AS FLOAT) AS SUM_TURNAROUND
FROM MY_BEAUTIFUL_TABLE
GROUP BY YOUR_CHOSEN_COLUMN
This returns a float (which is totally fine for me) that represents days both on Oracle ant SQL Server.
The reason I added zero to both DATEs is because in my case date columns on Oracle DB are of TIMESTAMP type and on SQL Server are of DATETIME type (which is obviously weird). So adding zero to TIMESTAMP on Oracle works just like casting to date and it does not have any effect on SQL Server DATETIME type.
Thank you guys! You were really helpful.
You can't sum two datetimes. It wouldn't make sense - i.e. what does 15:00:00 plus 23:59:00 equal? Some time the next day? etc
But you can add a time increment by using a function like Dateadd() in SQL Server.
In SQL Server as long as your individual timespans are all less than 24 hours you can do something like
WITH TIMES AS
(
SELECT CAST('01:01:00' AS DATETIME) AS TimeSpan
UNION ALL
SELECT '00:02:00'
UNION ALL
SELECT '23:02:00'
UNION ALL
SELECT '17:02:00'
--UNION ALL SELECT '24:02:00' /*This line would fail!*/
),
SummedTimes As
(
SELECT cast(SUM(CAST(TimeSpan AS FLOAT)) as datetime) AS [Summed] FROM TIMES
)
SELECT
FLOOR(CAST(Summed AS FLOAT)) AS D,
DATEPART(HOUR,[Summed]) AS H,
DATEPART(MINUTE,[Summed]) AS M,
DATEPART(SECOND,[Summed]) AS S
FROM SummedTimes
Gives
D H M S
----------- ----------- ----------- -----------
1 17 7 0
If you wanted to handle timespans greater than 24 hours I think you'd need to look at CLR integration and the TimeSpan structure. Definitely not portable!
Edit: SQL Server 2008 has a DateTimeOffset datatype that might help but that doesn't allow either SUMming or being cast to float
I also do not think this is possible. Go with custom solutions that calculates the date value according to your preferences.
You can also use this:
select
EXTRACT (DAY FROM call_end_Date - call_start_Date)*86400 +
EXTRACT (HOUR FROM call_end_Date - call_start_Date)*3600 +
EXTRACT (MINUTE FROM call_end_Date - call_start_Date)*60 +
extract (second FROM call_end_Date - call_start_Date) as interval
from table;
You Can write you own aggregate function :-). Please read carefully http://docs.oracle.com/cd/B19306_01/appdev.102/b14289/dciaggfns.htm
You must create object type and its body by template, and next aggregate function what using this object:
create or replace type Sum_Interval_Obj as object
(
-- Object for creating and support custom aggregate function
duration interval day to second, -- In this property You sum all interval
-- Object Init
static function ODCIAggregateInitialize(
actx IN OUT Sum_Interval_Obj
) return number,
-- Iterate getting values from dataset
member function ODCIAggregateIterate(
self IN OUT Sum_Interval_Obj,
ad_interval IN interval day to second
) return number,
-- Merge parallel summed data
member function ODCIAggregateMerge(
self IN OUT Sum_Interval_Obj,
ctx2 IN Sum_Interval_Obj
) return number,
-- End of query, returning summary result
member function ODCIAggregateTerminate
(
self IN Sum_Interval_Obj,
returnValue OUT interval day to second,
flags IN number
) return number
)
/
create or replace type body Sum_Interval_Obj is
-- Object Init
static function ODCIAggregateInitialize(
actx IN OUT Sum_Interval_Obj
) return number
is
begin
actx := Sum_Interval_Obj(numtodsinterval(0,'SECOND'));
return ODCIConst.Success;
end ODCIAggregateInitialize;
-- Iterate getting values from dataset
member function ODCIAggregateIterate(
self IN OUT Sum_Interval_Obj,
ad_interval IN interval day to second
) return number
is
begin
self.duration := self.duration + ad_interval;
return ODCIConst.Success;
exception
when others then
return ODCIConst.Error;
end ODCIAggregateIterate;
-- Merge parallel calculated intervals
member function ODCIAggregateMerge(
self IN OUT Sum_Interval_Obj,
ctx2 IN Sum_Interval_Obj
) return number
is
begin
self.duration := self.duration + ctx2.duration; -- Add two intervals
-- return = All Ok!
return ODCIConst.Success;
exception
when others then
return ODCIConst.Error;
end ODCIAggregateMerge;
-- End of query, returning summary result
member function ODCIAggregateTerminate(
self IN Sum_Interval_Obj,
returnValue OUT interval day to second,
flags IN number
) return number
is
begin
-- return = All Ok, too!
returnValue := self.duration;
return ODCIConst.Success;
end ODCIAggregateTerminate;
end;
/
-- You own new aggregate function:
CREATE OR REPLACE FUNCTION Sum_Interval(
a_Interval interval day to second
) RETURN interval day to second
PARALLEL_ENABLE AGGREGATE USING Sum_Interval_Obj;
/
Last, check your function:
select sum_interval(duration)
from (select numtodsinterval(1,'SECOND') as duration from dual union all
select numtodsinterval(1,'MINUTE') as duration from dual union all
select numtodsinterval(1,'HOUR') as duration from dual union all
select numtodsinterval(1,'DAY') as duration from dual);
Finally You can create SUM function, if you want.