I get an time difference value of 5.5 which should subtract 5 hours and 30 minutes from current date time .
select Dateadd(HH, -5.5,GETUTCDATE()),GETUTCDATE()
In output it only subtracts 5 hours .
I always get an value in form of this offset 5.5 or 13.5 likewise depending on the timezone..
Is this possible ???
I always get an value in form of this offset 5.5 or 13.5 likewise depending on the timezone..
Then you can multiply the value by 60 and use minute datepart
select Dateadd(MINUTE, -5.5 * 60,GETUTCDATE())
time arithmetic always works in whole units - use -330 minutes instead
select Dateadd(MINUTE, -330,GETUTCDATE()),GETUTCDATE()
the input to the function is intended to be an integer (whole number) - you may be finding that -5.5 is truncating off the decimal part
Yes this can be done. First, you need to convert your decimal offset into minutes. Then you can use DATEADD as before.
DECLARE #Offset DECIMAL(18, 2) = 5.5;
DECLARE #Mins INT = 60 * #Offset;
-- Offsetting by decimal time values.
SELECT
DATEADD(MINUTE, #Mins, GETDATE())
;
Related
I have a SQL query like
SET THIS_YEAR_END = '2022-11-01';
SET THIS_YEAR_START = DATEADD(DAY, -4*7+1, $THIS_YEAR_END);
SET LAST_YEAR_END = '2021-11-02';
SET LAST_YEAR_START = DATEADD(DAY, -4*7+1, $LAST_YEAR_END);
select end_date from (
select * from data
where DATE>= DATEADD(DAY, -27 * 7, $LAST_YEAR_START))
AND END_DATE BETWEEN CUST.END_DATE - 26 * 7 AND CUST.END_DATE - 7
I'm confused with this dateadd function in SQL. Can anyone please explain what exactly it's doing?
Here is the docs: https://docs.snowflake.com/en/sql-reference/functions/dateadd.html
Basically DATEADD is adding a specified value to a certain date. The first parameter is indicating the units of time that you want to add (e.g. DAY or MONTH), the second parameter specifies the number of units (e.g. number of days or number of months) and the third paramter is the date, to which you want to add something.
In your example in line 2 you are reducing THIS_YEAR_END by -4*7+1 (=-27) days.
Is there a way to convert a value in H.M format in the a field like (1.2 means 1 hour 20 min) to 80 minutes?
i tried to use a function func_Split to split the Hours and minutes but got stuck on how to add the hours to minutes and bring the result to the select query.
A handy function you can use for this is parsename
declare #value decimal(4,2)=1.2
select ParseName(#value,2)*60 + ParseName(#value,1)
An alternative method would be with some arithmetic on the integer and decimal place values:
SELECT (CONVERT(int,YourColumn) * 60) + ((YourColumn % 1) * 100)
FROM dbo.YourTable;
SELECT LTRIM(DATEDIFF(MINUTE, 0, TimeSpent))
FROM yourtable
I've been working on some SQL code to measure efficiency in real-time for some production data. Here's a quick background:
Operators will enter in data for specific sub assemblies. This data looks something like this:
ID PO W/S Status Operator TotalTime Date
60129515_2000_6_S025 107294 S025 Completed A 38 05/08/2020
60129515_2000_7_S025 107294 S025 Completed A 46 05/08/2020
60129515_2000_8_S025 107294 S025 Completed A 55 05/08/2020
60129515_2025_6_S020 107295 S020 Completed B 58 05/08/2020
60129515_2025_7_S020 107295 S020 Completed B 47 05/08/2020
60129515_2025_8_S020 107295 S020 Completed B 45 05/08/2020
60129515_2000_1_S090 107294 S090 Completed C 33 05/08/2020
60129515_2000_2_S090 107294 S090 Completed C 34 05/08/2020
60129515_2000_3_S090 107294 S090 Completed C 21 05/08/2020
The relevant columns are the Operator, TotalTime and Date (note that the date is stored as varchar(50) because it plays nicer with Microsoft PowerApps that way).
What I need to do is:
Aggregate the sum of "TotalTime" grouped by Operator
Calculate the time elapsed based on a condition:
If between 7AM and 4PM, calculate the time elapsed since 7AM of the current day
If after 4PM, return the total time between 7AM and 4PM of the current day
Divide the SUM(TotalTime) by the TimeElapsed (AKA the first list item / second list item) in order to get a rough estimate of labor hours worked vs. hours passed in the day.
This calculation would change every time the query was ran. This will allow the Microsoft PowerApp that is pulling this query to refresh the efficiency measure in real time. I've taken a stab at it already - see below:
SELECT
md.Operator,
CASE
WHEN DATEADD(HOUR, -5, GETUTCDATE()) > CONVERT(DATETIME, CONVERT(DATE, DATEADD(HOUR, -5, GETUTCDATE()))) + '7:00' AND GETDATE() < CONVERT(DATETIME, CONVERT(DATE, DATEADD(HOUR, -5, GETUTCDATE()))) + '15:45'
THEN (SUM(isNull(md.TotalTime, 0)) + SUM(isNull(md.DelTime, 0))) * 1.0 / DATEDIFF(MINUTE, CONVERT(DATETIME, CONVERT(DATE, DATEADD(HOUR, -5, GETUTCDATE()))) + '7:00' , DATEADD(HOUR, -5, GETUTCDATE())) * 100.0
ELSE (SUM(isNull(md.TotalTime, 0)) + SUM(isNull(md.DelTime, 0))) / 420 * 100.0
END AS OpEfficiency
FROM
[Master Data] AS md
WHERE
md.[Date] = CONVERT(varchar(50), DATEADD(HOUR, -5, GETUTCDATE()), 101)
GROUP BY
md.Operator
Note: the DelTime is a different column regarding delay times. I am also converting back from UTC time to avoid any time zone issues when transferring to PowerApps.
However, this is horribly inefficient. I am assuming it is because the Date needs to be converted to datetime every single time. Would it work better if I had a calculated column that already had the date converted? Or is there a better way to calculate time elapsed since a certain time?
Thanks in advance.
There are a few things you can do to increase efficiency considerably. First, you want to make sure SQL can do a simple comparison when selecting rows, so you'll start by calculating a string to match your date on since your [Date] field is a string not a date.
Second, calculate the minutes in your shift (either 540 for a full shift or scaled down to 0 at 7 AM exactly) ahead of time so you aren't calculating minutes in each row.
Third, when summing for operators, use a simple sum on the minutes and calculate efficiency from that sum and your pre-calculated shift so far minutes.
One note - I'm casting the minutes-so-far as FLOAT in my example, maybe not the best type but it's clearer than other decimal types like DECIMAL(18,6) or whatever. Pick something that will show the scale you want.
My example uses a Common Table Expression to generate that date string and minutes-so-far FLOAT, that's nice because it fits in a direct query, view, function, or stored procedure, but you could DECLARE variables instead if you wanted to.
By filtering with an INNER JOIN on the [Date] string against the pre-calculated TargetDate string, I make sure the data set is pared down to the fewest records before doing any math on anything. You'll definitely want to INDEX [Date] to keep this fast as your table fills up.
All these together should give a pretty fast query, good luck
with cteNow as ( --Calculate once, up front - date as string, minutes elapsed as FLOAT (or any non-integer)
SELECT CASE WHEN 60*DATEPART(HOUR, GETUTCDATE())+DATEPART(MINUTE, GETUTCDATE()) > 60*21
--4PM in UTC-5, expressed in minutes
THEN CONVERT(float,(16-7)*60) --minutes in (4 PM-7 AM) * 60 minutes/hour
ELSE --Assume nobody is running this at 6 AM, so ELSE = between 7 and 4
CONVERT(float,60*DATEPART(HOUR, GETUTCDATE()) + DATEPART(MINUTE, GETUTCDATE()) - ((7+5)*60))
--Minutes since midnight minus minutes from midnight to 7 AM, shifted by
--UTS offset of 5 hours
END as MinutesToday --Minutes in today's shift so far
, FORMAT(DATEADD(HOUR,-5,GETUTCDATE()),'MM/dd/yyyy') as TargetDate --Date to search for
--as a string so no conversion in every row comparison. Also, index [Date] column
)
SELECT md.Operator, SUM(md.TotalTime) as TotalTime, SUM(md.TotalTime) / MinutesToday as Efficiency
FROM [Master Data] AS md INNER JOIN cteNow as N on N.TargetDate = md.[Date]
GROUP BY md.Operator, MinutesToday
BTW, you didn't make allowances for lunch or running before 7 AM, so I also ignored those. I think both could be addressed in cteNOW without adding much complexity.
Basically I am trying to calculate the progress of the current quarter, represented as a percentage. Currently I have:
(DATEPART(dd,#AsOf)/91) * 100
We are using 91 days as a fixed solution for the quarter. They necessity for 100% accuracy is not required.
#AsOf is being passed in as a DATETIME type.
I have tried multiple ways and I receive 0. I assume it is because I am using INT instead of DECIMAL but I tried that and I still get 0.
You should just be able to force it to be a decimal by adding a decimal point, like 91.0 and 100.0 to avoid integer division issues:
DECLARE #date DATETIME
set #date = getdate();
select DATEPART(dd,#date) TheDay,
(DATEPART(dd,#date)/91.0) DivBy91,
(DATEPART(dd,#date)/91.0) * 100.0 Result
Result:
TheDay DivBy91 Result
19 0.208791 20,8791000
If an integer dividend is divided by an integer divisor, the result is an integer that has any fractional part of the result truncated.
What integer division will do is produce 0 in column 2, which is what is causing your result to be 0.
I am using SQL Server 2016 and I'm trying to convert military time to standard time. The military time is a 4 digit integer and I'm trying to get the standard time format (00:00 am/pm).
I ran a simple CASE statement that made it standard but without ':' and 'am/pm'.
CASE
WHEN SA_BEGTIME between 0 and 1259 then SA_BEGTIME
WHEN SA_BEGTIME between 1300 and 2400 then SA_BEGTIME - 1200
ELSE ''
END as Time
Results
How do I convert it so that it is in the right format: '00:00 am/pm'
Thank you!
You can split it into parts with integer division and modulo, cast it to a VARCHAR and then you can convert it to a TIME:
declare #x int = 109
select cast(cast(#x / 100 as varchar(2)) + ':' + cast(#x % 100 as varchar(2)) as time)
Or you can use the new TIMEFROMPARTS() function (SQL Server 2012+):
declare #x int = 109
select TIMEFROMPARTS(#x / 100,#x % 100, 0, 0, 0)
You can then format it however you'd like.
Assuming your data is stored as an integer, and also assuming there is not invalid time stored (i.e. values above 2400 or below 0) you can use the following:
declare #TheTime int = 900
select right(convert(varchar(20),
cast(stuff(right('0000' + convert(varchar(4),#TheTime),4),3,0,':')
as datetime),100),7)
-------
9:00AM
Sorry for the density of the solution. This is what I did:
Convert #TheTime to varchar(4)
Add a string of zeros at the front
Take the rightmost 4 characters from this new string
Stuff a colon sign in the middle of this new string
Cast the string as datetime
Convert back to string using 100 as the style indicator to get AM/PM
Get the right most 7 characters of the string.
I am sure there are more elegant ways, but this one works for me quite well.
I'm using the solution that #BaconBits provided but I had to make a tweak because 2400 was a valid representation but it failed with that code. Here's the tweaked solution:
declare #x int = 2400
select TIMEFROMPARTS((#x / 100) % 24,#x % 100, 0, 0, 0)
I needed to convert a datetime field where the time was military to just the time in AM/PM format. This worked beautifully.
Left(convert(varchar(20), cast(MyDateField as time),100),7)
You can use convert to get n appropriate presentation of time.
declare #mt varchar(4) = '1500'
select convert(varchar, cast(left(#mt, 2) + ':' + right(#mt, 2) as time), 0)