I want to compile a C file that only has a function to assembly.
To compile, I'm running the following command
clang -c -m32 -O1 -S exemple.c
Everything works fine but I was wondering if there is any convention regarding the order of which compilation flags should appear.
Related
I am new to C and using GCC. How do I compile multiple C files and then run them? I have multiple miles and each has different functions and they are supposed to run through the main.c file. My friend showed me through Windows but I am having issues figuring out how to do it on Mac.
What I was told:
Compile both files individually first:
gcc -Wall -c .\main.c
gcc -Wall -c .\file.c
Then compile both together into an executable:
gcc -o program file.o main.o
Then run executable with .\program.exe
You should probably investigate makefiles, but this is quite easy. The following should do the trick.
gcc -o program file.c main.c
Feel free to add in whichever -W warning flags you want.
Note also that Macs do not use \ as a directory separator but rather /, and executable files do not typically end in .exe.
I wrote a code in C in Ubuntu which checks for balanced brackets in the input given.I compiled it using gcc compiler and I am getting the correct output.This is actually a part of an online course and they are asking me to use the compiler flag
gcc -pipe -O2 -std=c11 filename -lm
I don't think I understand what I am supposed to do so I tried compiling using this flag and my code is not compiling. My question is if my code compiles when I do
gcc filename.c
why isn't it compiling when I do
gcc -pipe -O2 -std=c11 filename -lm
The error message I am getting is :
cc1plus: warning: command line option ‘-std=c11’ is valid for C/ObjC but not for C++
The reason is the file ending. A capital C is interpreted as a C++ file. The solution is to just rename the file like this:
mv filename.C filename.c
My question is if my code compiles when I do gcc filename.C why isn't it compiling when I do gcc -pipe -O2 -std=c11 <filename> -lm
See above. But there are some situations where it would not solve everything. While C11 gives some extensions to previous versions, it's not 100% backwards compatible.
-std=c11 is a correct option
however you need at least gcc 4.7 or higher to have this option
By "<filename>" they mean to substitute in the name of the file you want to compile. Including the literal string "<filename>" will not work.
I have to turn off optimizations while compiling c code I wrote while using the gcc compiler on a linux. I have found that I can compile the code but I can only get the code to compile without the executable name specified (default to a.out).
So this works:
gcc -O0 Problem04b.c
But my problem is that I have to submit this assignment and I can't submit an executable called a.out because my instructor needs to know which problem it is. I realize I can probably just run
cp a.out Problem04b
then
rm a.out
but I want to know if there is a way I can just compile the code directly into the executable Problem04b. I've tried to run the command like this:
gcc -O0 Problem04b Problem04b.c
but I'm having no luck.
Thanks for your help.
It's the -o flag:
gcc -O0 -o Problem04b Problem04b.c
To specify the output file, you need to use the -o <filename> option with gcc.
Note : Please mind the lower case here
In your case, it should be
gcc -O0 -o Problem04b Problem04b.c
For reference: From gcc manual
-o file
Place output in file file. This applies to whatever sort of output is being produced, whether it be an executable file, an object file, an assembler file or preprocessed C code.
Actually, you also want to get warnings (that won't change the produced executable, but it is very helpful to you), so compile with
gcc -O0 -Wall -Wextra Problem04b.c -o Problem04b
The -Wall option asks for nearly all warnings, the -Wextra option asks for even more of them.
To run your thing (the ./ is useful because of possible PATH issues):
./Problem04b
Notice that -O0 is optional (since it is the default), you could remove it.
gcc -Wall -Wextra Problem04b.c -o Problem04b
If you want real optimization, e.g. for benchmarking, use e.g. -O1 or -O2 or -O3
You probably want to compile with debug information, then
gcc -g -Wall -Wextra Problem04b.c -o Problem04b
and of course you need to learn how to use the GDB debugger. So read some tutorial about that, then type
gdb ./Problem04b
You'll get a (gdb) prompt. Try help at that time.
You probably want to read the chapter about invoking GCC of the GCC documentation.
So my question is simple.
I want to compile a C project file in gcc compiler 4.4.8.
In windows cmd window I can type :
gcc -std=c99 -O2 -DCONTEST -s -static -lm name.c -o name.exe
In Code::Blocks how can I change the compiler default arguments with the above?
I wanted to build a c file and I geting errors like
error: 'for' loop initial declarations are only allowed in C99 mode|
Ok to put your preferred arguments to gnu compiler go to :
Settings -> Debugger -> Compiler settings -> Other Options
and paste there your arguments!
Example:
-std=c99 -O2 -DCONTEST -s -static -lm
My C compiler was working a second ago and making executables, but I started working on a new .c file and suddenly it won't work anymore. I haven't changed anything and I'm still using the same commands, Gitbash version, etc. The compiler is still able to catch errors, so gcc works, but after calling:
gcc -std=c99 my_file.c
there is no executable called my_file.exe. Help sites online suggest installing additional software to fix the error, but I'm hesitant to do so because everything was working fine earlier and I don't want to aggravate the problem with additional software.
Since you have not specified the name of the file to output, GCC will output a.exe.
If you desire output named something else, you must use the -o flag, for example:
gcc -std=c99 -o my_file.exe my_file.c
On Unix, that compiler command would generate an executable a.out. You may find that there is an executable with a default name — but I don't have Windows to check what that name is. Guesses might include a.exe, a_out.exe, aout.exe, etc.
To get my_file.exe:
gcc -std=c99 -o my_file.exe my_file.c
If you don't specify an output -o flag you will get a.exe by default (a.out on other platforms),
gcc -std=c99 my_file.c
If it is working, produces
a.exe
I think you wanted
gcc -std=c99 -o my_file.exe my_file.c