I have to turn off optimizations while compiling c code I wrote while using the gcc compiler on a linux. I have found that I can compile the code but I can only get the code to compile without the executable name specified (default to a.out).
So this works:
gcc -O0 Problem04b.c
But my problem is that I have to submit this assignment and I can't submit an executable called a.out because my instructor needs to know which problem it is. I realize I can probably just run
cp a.out Problem04b
then
rm a.out
but I want to know if there is a way I can just compile the code directly into the executable Problem04b. I've tried to run the command like this:
gcc -O0 Problem04b Problem04b.c
but I'm having no luck.
Thanks for your help.
It's the -o flag:
gcc -O0 -o Problem04b Problem04b.c
To specify the output file, you need to use the -o <filename> option with gcc.
Note : Please mind the lower case here
In your case, it should be
gcc -O0 -o Problem04b Problem04b.c
For reference: From gcc manual
-o file
Place output in file file. This applies to whatever sort of output is being produced, whether it be an executable file, an object file, an assembler file or preprocessed C code.
Actually, you also want to get warnings (that won't change the produced executable, but it is very helpful to you), so compile with
gcc -O0 -Wall -Wextra Problem04b.c -o Problem04b
The -Wall option asks for nearly all warnings, the -Wextra option asks for even more of them.
To run your thing (the ./ is useful because of possible PATH issues):
./Problem04b
Notice that -O0 is optional (since it is the default), you could remove it.
gcc -Wall -Wextra Problem04b.c -o Problem04b
If you want real optimization, e.g. for benchmarking, use e.g. -O1 or -O2 or -O3
You probably want to compile with debug information, then
gcc -g -Wall -Wextra Problem04b.c -o Problem04b
and of course you need to learn how to use the GDB debugger. So read some tutorial about that, then type
gdb ./Problem04b
You'll get a (gdb) prompt. Try help at that time.
You probably want to read the chapter about invoking GCC of the GCC documentation.
Related
I have reinstalled mingw in my system and downloaded the gcc compiler.
I was shocked after compiling the first file which was "subject.c" but the name of the compiled file which gcc returned was "a.exe". It should be "subject.exe" but do not know why this happened.
Can anyone please explain the reason behind this ?
expected:
gcc subject.c
ls
subject.c subject.exe
tried:
gcc subject.c
ls
subject.c a.exe
-o can be used to give the name of the output file.
For example,
gcc -Wall -Wextra -pedantic subject.c -o subject.exe
(Do enable your compiler's warnings!)
gcc names its output files, in the absence of other instructions, a.out or a.exe depending on system environment because that is what it's supposed to do.
To override this default behavior, you can use the -o flag which tells gcc that the next argument is the desired name for the output file. For instance:
gcc -o subject.exe subject.c
There is no automatic functionality built into gcc to strip a source file of its file extension and add .exe to the end but this can be done manually with Makefiles or other similar scripts, for instance you can write a Makefile with the following contents:
%.exe: %.c
gcc -o $# $<
Then a command like make subject.exe would be translated to gcc -o subject.exe subject.c, which may be what you're looking for.
There is functionality built into gcc to strip source files of their extensions during different parts of the compilation process, which may have been what confused you. For instance a call like gcc -c subject.c can be expected to produce an object file called subject.o, likewise gcc -S subject.c can be expected to produce an assembly language file called subject.s, however this does not apply to executable files not only for historical reasons, but because programs can be compiled from multiple source files and there is not always a clear way to choose a name for the executable output.
I wrote a code in C in Ubuntu which checks for balanced brackets in the input given.I compiled it using gcc compiler and I am getting the correct output.This is actually a part of an online course and they are asking me to use the compiler flag
gcc -pipe -O2 -std=c11 filename -lm
I don't think I understand what I am supposed to do so I tried compiling using this flag and my code is not compiling. My question is if my code compiles when I do
gcc filename.c
why isn't it compiling when I do
gcc -pipe -O2 -std=c11 filename -lm
The error message I am getting is :
cc1plus: warning: command line option ‘-std=c11’ is valid for C/ObjC but not for C++
The reason is the file ending. A capital C is interpreted as a C++ file. The solution is to just rename the file like this:
mv filename.C filename.c
My question is if my code compiles when I do gcc filename.C why isn't it compiling when I do gcc -pipe -O2 -std=c11 <filename> -lm
See above. But there are some situations where it would not solve everything. While C11 gives some extensions to previous versions, it's not 100% backwards compatible.
-std=c11 is a correct option
however you need at least gcc 4.7 or higher to have this option
By "<filename>" they mean to substitute in the name of the file you want to compile. Including the literal string "<filename>" will not work.
My C program uses string.h.. Initially I was not able to compile it. But then I used
$ gcc filename.c -E
Then it complied but I am not able to run it with both
./a.out
./filename
The -E option to gcc invokes only the preprocessor. If you want to compile you need to do this:
gcc -g -Wall -Wextra -o filename filename.c
The -o option specifies the name of the executable to create, the -W options enable the common compiler warnings, and -g includes debugging symbols so you can use tools such as gdb to step through the code line by line.
okay so I'm on OS and I use terminal to compile my c code. Whenever I make a file using nano or vim called "tst.c" (or whatever the name might be ) then I compile using (my teacher told me to use this everytime so I don't think this is the problem:
gcc -Wall -std=c99 -o tst.c ./tst.c
then it turns into binary I'm guessing. But when I try to edit it again, it has all these weird encryptions I'm guessing like:
��������H���__PAGEZERO��������������������������������������������������������ÿ��__TEXT����������������������������������������������������__text����������__TEXT����������`�����*�������`���������������Ä������������__stubs���������__TEXT����������ä������������ä��������������Ä�����������__stub_helper���__TEXT����������ê������������ê���������������Ä������������__cstring�������
So, question is, how do I revert so I can edit and not make a new file every time???????
You're overwriting your original source file with the compiled executable because of the -o option:
gcc -Wall -std=c99 -o tst.c ./tst.c
^^^^^^^^
You'll need to specify a different output file name in the -o option:
gcc -Wall -std=c99 -o tst tst.c
Otherwise, you can leave the -o option off entirely, and the compiled executable will be written to a file named a.out.
Eventually, you'll want to automate all of this with the make utility, but for now just be aware of how the -o option works.
the -o (name) flag means you are storing the output into whatever you used for name.. so if you add .c to the end of the name you'll see lots of interesting stuff. Man pages are pretty awesome when learning about what each flags do.
My final executable (this is in unix though) will be proj07.
proj07: /user/cse320/Projects/project07.driver.o proj07.support.o
gcc -Wall /user/cse320/Projects/project07.driver.o proj07.support.o
proj07.support.o: proj07.support.c
gcc -c proj07.support.c
This creates proj07.support.o but no proj07 exists after compilation. I don't get an error so my mistake must be simple but I can't seem to figure it out.
Here's the output:
gcc -c proj07.support.c
gcc -Wall /user/cse320/Projects/project07.driver.o proj07.support.o
Also I am to use a static driver to test my file which is why the path is like that
You probably do have an a.out executable. Add -o $# to your first gcc occurrence and you should be fine.