My final executable (this is in unix though) will be proj07.
proj07: /user/cse320/Projects/project07.driver.o proj07.support.o
gcc -Wall /user/cse320/Projects/project07.driver.o proj07.support.o
proj07.support.o: proj07.support.c
gcc -c proj07.support.c
This creates proj07.support.o but no proj07 exists after compilation. I don't get an error so my mistake must be simple but I can't seem to figure it out.
Here's the output:
gcc -c proj07.support.c
gcc -Wall /user/cse320/Projects/project07.driver.o proj07.support.o
Also I am to use a static driver to test my file which is why the path is like that
You probably do have an a.out executable. Add -o $# to your first gcc occurrence and you should be fine.
Related
I do not know gcc and c well. In my /home/pi/Desktop/intern/adis16227_generic directory I have following 5 files.
ADIS16227.c
ADIS16227.h
Communication.c
Communication.h
main.c
main.c
#include<stdio.h>
#include "Communication.h" // Communication definitions.
int main() {
printf("hello!!\n");
unsigned char status = 0;
status = SPI_Init(0, 1000000, 1, 1);
printf("%u", status);
return 0;
}
Run command:
$ sudo gcc -L /home/pi/Desktop/intern/adis16227_generic main.c -lCommunication
Error:
/usr/bin/ld: cannot find -lCommunication
collect2: error: ld returned 1 exit status
Question:
What I am missing here?
What do I need to run the code?
-l is for libraries, and you never built a library from your Communication.c. The simplest solution is just add Communication.c to your compiler command line.
For larger projects, compile each translation unit separately with the -c switch like this:
gcc -c -Wall -Wextra -pedantic -omain.o main.c
gcc -c -Wall -Wextra -pedantic -oCommunication.o Communication.c
and so on ... (as a suggestion, I added some common warning options here, they help you spot errors)
The resulting .o files are object code. That's already compiled machine code, but with meta-information needed for a linker to link it with other object code into a complete executable.
Then link them all with one command:
gcc -oprogram main.o Communication.o
If you actually want a library from -- say -- Communication.c and ADIS16227.c, you could compile both to object code:
gcc -c -Wall -Wextra -pedantic -oCommunication.o Communication.c
gcc -c -Wall -Wextra -pedantic --oADIS16227.o ADIS16227.c
and then use ar to create a static library from them:
ar rcs libCommunication.a Communication.o ADIS16227.o
Then your initial compiler command would work (with the -lCommunication switch).
Final piece of advice: Never compile as root. This is completely unnecessary. So remove your sudo here.
those options:
-L /home/pi/Desktop/intern/adis16227_generic -lCommunication
suggest that the linker should find libCommunication.a (or .so) in the /home/pi/Desktop/intern/adis16227_generic directory.
But there are only sources in this directory. The linker won't build the sources of your "Communication" library for you.
So you could build the library and link with it:
gcc -c ADIS16227.c Communication.c
ar r libCommunication.a ADIS16227.o Communication.o
but maybe the fastest & quickest way to achieve a successful build would be:
sudo gcc -o main *.c
so it compiles all the files of the directory into the executable called main
Of course, it makes compilation times longer, but maybe it's not noticeable.
First move into the /home/pi/Desktop/intern/adis16227_generic directory:
cd /home/pi/Desktop/intern/adis16227_generic
Then, compile the source:
gcc ADIS16227.c Communication.c main.c -I .
You can now run your compiled program (called by default a.out):
./a.out
You have to compile separatedly files and then compile main with related obj file.
gcc -c Communication.c Communication.h
gcc main.c Communication.o -o main
I have to turn off optimizations while compiling c code I wrote while using the gcc compiler on a linux. I have found that I can compile the code but I can only get the code to compile without the executable name specified (default to a.out).
So this works:
gcc -O0 Problem04b.c
But my problem is that I have to submit this assignment and I can't submit an executable called a.out because my instructor needs to know which problem it is. I realize I can probably just run
cp a.out Problem04b
then
rm a.out
but I want to know if there is a way I can just compile the code directly into the executable Problem04b. I've tried to run the command like this:
gcc -O0 Problem04b Problem04b.c
but I'm having no luck.
Thanks for your help.
It's the -o flag:
gcc -O0 -o Problem04b Problem04b.c
To specify the output file, you need to use the -o <filename> option with gcc.
Note : Please mind the lower case here
In your case, it should be
gcc -O0 -o Problem04b Problem04b.c
For reference: From gcc manual
-o file
Place output in file file. This applies to whatever sort of output is being produced, whether it be an executable file, an object file, an assembler file or preprocessed C code.
Actually, you also want to get warnings (that won't change the produced executable, but it is very helpful to you), so compile with
gcc -O0 -Wall -Wextra Problem04b.c -o Problem04b
The -Wall option asks for nearly all warnings, the -Wextra option asks for even more of them.
To run your thing (the ./ is useful because of possible PATH issues):
./Problem04b
Notice that -O0 is optional (since it is the default), you could remove it.
gcc -Wall -Wextra Problem04b.c -o Problem04b
If you want real optimization, e.g. for benchmarking, use e.g. -O1 or -O2 or -O3
You probably want to compile with debug information, then
gcc -g -Wall -Wextra Problem04b.c -o Problem04b
and of course you need to learn how to use the GDB debugger. So read some tutorial about that, then type
gdb ./Problem04b
You'll get a (gdb) prompt. Try help at that time.
You probably want to read the chapter about invoking GCC of the GCC documentation.
I am using Linux mint 16. I had a code that I change it a bit.
I use two following commands in terminal in order to run the code. The problem is that it does not give me any error but the changes are not applied, which means it runs the previous version of code.
gcc -std=c99 -c Code.c -o Code.o
./Code
gcc -std=c99 -c Code.c -o Code.o will put the compiled object file in Code.o, not ./Code as you expect it to be..
Also, -c tells do not run the linker. So effectively you end up with an object file which cannot be run.
gcc -std=c99 Code.c -o Code will produce what you need.
For a complete list of gcc flags either use man gcc or see http://linux.die.net/man/1/gcc
Try
gcc -std=c99 -c Code.c -o Code
./Code
I have Ubuntu 64 bit installed, and when I compile C files using the flags:
gcc -g -m32 -ansi -Wall -c -o *.o *.c
it compiles the files, but when I try to run them in the terminal, nothing happens.
So I decided to try to compile and run just one simple file without a makefile, with the following code:
#include <stdio.h>
int main()
{
printf("Hello World");
return 0;
}
The compilation succeeds but when I try to run the file I get nothing...
Note: I already tried to install lib32gcc1, libc6-i386, and g++-multilib.
How can I fix this problem?
Replace -o *.o by -o programname. The -o parameter receives the executable name of the program you're generating. And here is gcc manual:
http://gcc.gnu.org/onlinedocs/gcc-4.7.2/gcc/Overall-Options.html#Overall-Options
For a simple test, leave every option out:
> cat test.c
#include <stdio.h>
int main()
{
printf("Hello World\n");
return 0;
}
> gcc test.c
> ./a.out
Hello World
and see if that works.
Let us assume you (already) have two object files a.o and b.o, their corresponding source file a.c and b.c and some common header ch.h; then your (incorrect) command line
gcc -g -m32 -ansi -Wall -c -o *.o *
might be expanded as:
gcc -g -m32 -ansi -Wall -c -o a.o b.o a.c b.c ch.h a.o b.o
(actually, that would be even worse, e.g. if you have some Makefile or some backup files from your editors like a.c~, as remarked by William Pursell)
which would compile but not link, the files b.o a.c b.c ch.h a.o b.o which does not means much.
You should understand that the shell is expanding first the arguments before executing any gcc program (in a new process). To understand what is expanded, consider replacing gcc by echo (or by gcc -v which would show what is really happening)
Then, you should read the GCC documentation about invoking GCC
Actually, you need to spend several hours in reading, e.g. Advanced Bash Scripting Guide (which does have some mistakes perhaps) and Advanced Linux Programming. Several wikipedia pages could also be useful to read.
I'm new to makefiles, so I apologize in advance if this is a silly question. Also I removed most variables from my makefile because they weren't working properly (gnu make tells me that $(myvar) should be completely replaces by the value of myvar, however the output of make was showing me that this was not happening), so I apologize for the ugliness and the more than 80 character lines.
acolibobj = acoLibInit acoGlobalDefs
acolibinterface: $(acolibobj).o
acoLibInit.o:
gcc -fPIC -g -c -Wall -I/usr/include/dc1394 -o acoLibinit.o acoCommands/acoLibInterface/acoLibInit.c
acoGlobalDefs.o:
gcc -fPIC -g -c -Wall -I/usr/include/dc1394 -o acoGlobalDefs.o acoCommands/acoLibInterface/acoGlobalDefs.c
When I run this makefile I get:
gcc -fPIC -g -c -Wall -I/usr/include/dc1394 -o acoLibinit.o acoCommands/acoLibInterface/acoLibInit.c
cc acoLibInit.o -o acoLibInit
gcc: acoLibInit.o: No such file or directory
gcc: no input files
make: *** [acoLibInit] Error 1
So far as I can tell, what's happening is that make is trying to compile AND link, even though I explicitly added the -c flag. When I run "gcc -fPIC -g -c..." myself (from bash), I do not get any problems at all. Why does make go on to try "cc acoLibInit.o -o acolibInit"?
make is trying to build acoLibInit. It probably has built-in rule that specifies "whatever" can be produced by linking "whatever.o", which is why you get that cc line.
This line:
acolibinterface: $(acolibobj).o
expands to:
acolibinterface: acoLibInit acoGlobalDefs.o
(note the absence of .o on the first dependency). This is why it's trying to link acoLibInit.
Try this:
acolibinterface: $(addsuffix .o,$(acolibobj))
if you want only the .o files as dependencies for that target.
$(acolibobj).o expands to acoLibInit acoGlobalDefs.o. Thus, you're really saying:
acolibinterface: acoLibInit acoGlobalDefs.o
Simply define acolibobj = acoLibInit.o acoGlobalDefs.o and use acolibinterface: $(acolibobj).