Combining a set of expressions - c

I am trying to perform a sequence of operations on a 2D array (where dimensions are equal on both sides), where the sequence of operations is random. For each operation, it is a function which represents a transformation of a point to another point, which is represented as an expression. Is it possible to combine different expressions together without knowing their run time values?
For instance, to transform a point 1000 times, 1000 function calls would need to be done. However, since the same transformation would be applied to all points, is it possible to generalize these 1000 calls into a single call for the sake of this transformation?
The following is a simplified example of what I am trying to achieve.
int MoveRightIndex(int offset, int index)
{
return index + offset;
}
int MoveLeftIndex(int offset, int index)
{
return index - offset;
}
int MultIndex(int mult, int index)
{
return index*mult;
}
int main()
{
int index = 0;
index = MoveRightIndex(5, index); // index + 5
index = MultIndex(3, index); // index * 3
index = MoveLeftIndex(2, index); // index - 2
printf("index is: %i\n", index);
// Is there a way to generalize this "net" operation for the next point without calling the same functions again?
//e.g. I know now for the next index the transformation is (index + 5)*3 -2 -> 3*index + 13
//How can I apply 3*index + 13 to index2 without doing the above 3 function calls?
}

You could write a function to do the composition at compile time:
static inline int composite(int roffset, int mult, int loffset, int index)
{
return MoveLeftIndex(loffset, MultIndex(mult, MoveRightIndex(roffset, index)));
}
and, the compiler may be able to do an astonishingly good job of optimizing that. You'd invoke:
index = composite(5, 3, 2, index);
to get the job done 'all at once'. This gives you no runtime flexibility, though.
An alternative is to define a structure defining operations and an array of the structure that can be initialized (with care) at runtime, along the lines of:
typedef int (*Transformer)(int value, int index);
typedef struct
{
const char *t_name;
Transformer t_func;
int t_value;
} TransformStep;
static TransformStep steps[] =
{
{ "MoveRightIndex", NULL, 5 },
{ "MultIndex", NULL, 3 },
{ "MoveLeftIndex", NULL, 2 },
};
enum { NUM_STEPS = sizeof(steps) / sizeof(steps[0]) };
typedef struct
{
const char *t_name;
Transformer t_func;
} NameToPointerMapping;
/* If the list of mappings gets big, sort the array and use search */
static const NameToPointerMapping mappings[] =
{
{ "MoveLeftIndex", MoveLeftIndex },
{ "MoveRightIndex", MoveRightIndex },
{ "MultIndex", MultIndex },
};
enum { NUM_MAPPINGS = sizeof(mappings) / sizeof(mappings[0]) };
static int MapFunctionNamesToPointers(size_t nsteps, TransformSteps *steps)
{
if (nsteps == 0 || steps == NULL)
return -1;
for (size_t i = 0; i < nsteps; i++)
{
if (steps[i].t_func == NULL)
{
for (size_t j = 0; j < NUM_MAPPINGS; j++)
{
if (strcmp(steps[i].t_name, mappings[j].t_name) == 0)
{
steps[i].t_func = mappings[j].t_func;
break;
}
}
if (steps[i].t_func == NULL)
{
…report error - named transformer not found…
return -1;
}
}
}
return 0;
}
static int ApplyTransform(size_t nsteps, TransformStep *steps, int *pindex)
{
if (nsteps == 0 || steps == NULL)
return -1; // Report error
if (steps[0].t_func == NULL && MapFunctionNamesToPointers(nsteps, steps) != 0)
return -1; // Report error
int index = *pindex;
for (size_t i = 0; i < nsteps; i++)
index = (*steps[i].t_func(steps[i].t_value, index);
*pindex = index;
return 0; // Report success
}
No compiler has been consulted about the accuracy of the conceptual code above.
There's nothing to stop you from creating the array dynamically with the function names and the values read from a file or standard input, and then mapping the names accordingly. The first time an array is used, the function names are mapped to the corresponding function pointers. Thereafter, the code simply cycles through the series of function calls.
There are endless optimizations and refactorings that could be applied, but the basic idea is that function names are mapped to corresponding function pointers, and then the array of transformation steps can be applied to the
data. One change would be to do the mapping outside the ApplyTransform() function; another would be to factor the linear search into another small, separate (inline?) function and use that. The list continues. With care, you could build the list of functions and their pointers dynamically so that you can load shared libraries containing new transformations.
This design forces you to have one 'value' per function call. There are ways to allow multiple values instead, but that's rapidly getting more complex.

Related

C trying to fix infinite loop

I have a function that gets an index value, puts it in an array. Then generates a new new random index using rand + srand(key). And it checks if the newly generated index is in array already, it will will keep on generating new index and checking until a unique value is generated.
The problem is that it works fine for small keys, but at longer keys it gets stuck in an infinite loop and can never find a unique value. Here's my code:
int getNewIndex(PPM *im, int index, int *visitedPixels, int *visitedPixelsIndex) {
int i = 0;
if(*visitedPixelsIndex == im->height) {
perror("Cannot encode anymore: pixels limit reached");
exit(1);
}
visitedPixels[*visitedPixelsIndex] = index;
(*visitedPixelsIndex)++;
// If index is already in the list, generate a new number and check again.
while (i < *visitedPixelsIndex) {
if(index == visitedPixels[i]) {
index = rand() % im->height;
i = 0;
} else {
i++;
}
}
return index;
}
EDIT: im->height which is the image height is about 400-600 in average.
As far as I can see the code will generate an infinite loop when you insert the last free index into the array.
Assume that:
1) im->height is 500 so that valid index is in the range [0 .. 499]
2) You have already inserted 499 values, i.e. *visitedPixelsIndex is 499
So when the function is called this condition *visitedPixelsIndex == im->height will be false so you don't exit but continue on and you insert value number 500 in the array.
Then you do (*visitedPixelsIndex)++; so that *visitedPixelsIndex becomes 500.
After that you enter the while loop trying to find a new unused index. However - since you have already used all 500 valid index values, you'll never find an unused index.
In other words - an infinite loop
Maybe you should do:
(*visitedPixelsIndex)++;
if(*visitedPixelsIndex == im->height) {
perror("Cannot encode anymore: pixels limit reached");
exit(1);
}
I also think you should generate a new index before the while loop.
However, in general I think your code would be more clear if you split the current function into two functions. Like
int isPresent(int index, int *visitedPixels, int N)
{
for(int i = 0; i<N; ++i)
{
if (index == visitedPixels[i]) return 1;
}
return 0;
}
int getNewIndex(PPM *im, int index, int *visitedPixels, int *visitedPixelsIndex)
{
visitedPixels[*visitedPixelsIndex] = index;
(*visitedPixelsIndex)++;
if (*visitedPixelsIndex == im->height) {
perror("Cannot encode anymore: pixels limit reached");
exit(1);
}
do
{
index = rand() % im->height;
} while(isPresent(index, visitedPixels, *visitedPixelsIndex));
return index;
}

Recovering elements of large array with multiple index ranges

This is a tricky problem that I have been thinking about for a long time and have yet to see a satisfactory answer anywhere. Lets say I have a large int array of size 10000. I can simply declare it in the following manner:
int main()
{
int foo[10000];
int i;
int n;
n = sizeof(foo) / sizeof(int);
for (i = 0; i < n; i++)
{
printf("Index %d is %d\n",i,foo[i] );
}
return 0;
}
It is pretty clear that each index in the array will hold a random assortment of numbers before I formally initialize them:
Index 0 is 0
Index 1 is 0
Index 2 is 0
Index 3 is 0
.
.
.
Index 6087 is 0
Index 6088 is 1377050464
Index 6089 is 32767
Index 6090 is 1680893034
.
.
.
Index 9996 is 0
Index 9997 is 0
Index 9998 is 0
Index 9999 is 0
Then lets say that I initialize select index ranges of my array with values that hold a specific value for the program as a whole and must be preserved, with the goal of passing in those values for subsequent operation to some function:
//Call this block 1
foo[0] = 0;
foo[1] = 7;
foo[2] = 99;
foo[3] = 0;
//Call this block 2
foo[9996] = 0;
foo[9997] = 444;
foo[9998] = 2;
foo[9999] = 0;
for (i = 0; i < (What goes here?); i++)
{
//I must pass in only those values initialized to select indices of foo[] (Blocks 1 and 2 uncorrupted)
//How to recover those values to pass into foo_func()?
foo_func(foo[]);
}
Some of those values that I initialized foo[] with overlap with pre-existing values in the array before formally initializing the array myself. How can I pass in just the indices of the array elements that I initialized, given that there are multiple index ranges? I just can't figure this out. Thanks for any and all help!
EDIT:
I should also mention that the array itself will be read from a .txt file. I just showed the initialization in the code for illustrative purposes.
There's a number of ways you can quickly zero out the memory in the array, either while initializing or after.
For an array on the stack, initialize it with zeros. {0} is shorthand for that.
int foo[10000] = {0};
For an array on the heap, use calloc to allocate memory and initialize it with 0's.
int *foo = calloc(10000, sizeof(int));
If the array already exists, use memset to quickly overwrite all the array's memory with zeros.
memset(foo, 0, sizeof(int) * 10000);
Now all elements are zero. You can set individual elements to whatever you like one by one. For example...
int main() {
int foo[10] = {0};
foo[1] = 7;
foo[2] = 99;
foo[7] = 444;
foo[8] = 2;
for( int i = 0; i < 10; i++ ) {
printf("%d - %d\n", i, foo[i]);
}
}
That will print...
0 - 0
1 - 7
2 - 99
3 - 0
4 - 0
5 - 0
6 - 0
7 - 444
8 - 2
9 - 0
As a side note, using only a few elements of a large array is a waste of memory. Instead, use a hash table, or if you need ordering, some type of tree. These can be difficult to implement correctly, but a library such as GLib can provide you with good implementations.
Introduction
I'm making a strong assumption on your problem, and it is sparsness (a majority of the elements in your array will remain zero).
Under this assumption I would build the array as a list. I'm including a sample code, that it is not complete and it is not intended to
be---you should do your own homework :)
The core object is a struct with a pointer to a begin element and the size:
typedef struct vector {
size_t size;
vector_element_t * begin;
} vector_t;
each element of the vector has its own index and value and a pointer to the next element in a list:
typedef struct vector_element vector_element_t;
struct vector_element {
int value;
size_t index;
vector_element_t *next;
};
on this basis we can build a dynamical vector as a list, by dropping a constraint on the ordering (it is not needed, you can modify this code
to maintain the ordering), using some simple custom methods:
vector_t * vector_init(); // Initialize an empty array
void vector_destroy(vector_t* v); // Destroy the content and the array itself
int vector_get(vector_t *v, size_t index); // Get an element from the array, by searching the index
size_t vector_set(vector_t *v, size_t index, int value); // Set an element at the index
void vector_delete(vector_t *v, size_t index); // Delete an element from the vector
void vector_each(vector_t *v, int(*f)(size_t index, int value)); // Executes a callback for each element of the list
// This last function may be the response to your question
Test it online
The main example
This is a main that uses all this methods and prints in console:
int callback(size_t index, int value) {
printf("Vector[%lu] = %d\n", index, value);
return value;
}
int main() {
vector_t * vec = vector_init();
vector_set(vec, 10, 5);
vector_set(vec, 23, 9);
vector_set(vec, 1000, 3);
printf("vector_get(vec, %d) = %d\n", 1000, vector_get(vec, 1000)); // This should print 3
printf("vector_get(vec, %d) = %d\n", 1, vector_get(vec, 1)); // this should print 0
printf("size(vec) = %lu\n", vec->size); // this should print 3 (the size of initialized elements)
vector_each(vec, callback); // Calling the callback on each element of the
// array that is initialized, as you asked.
vector_delete(vec, 23);
printf("size(vec) = %lu\n", vec->size);
vector_each(vec, callback); // Calling the callback on each element of the array
vector_destroy(vec);
return 0;
}
And the output:
vector_get(vec, 1000) = 3
vector_get(vec, 1) = 0
size(vec) = 3
Vector[10] = 5
Vector[23] = 9
Vector[1000] = 3
size(vec) = 3
Vector[10] = 5
Vector[1000] = 3
The callback with the function vector_each is something you really should look at.
Implementations
I'm giving you some trivial implementations for the functions in the introdution. They are not complete,
and some checks on pointers should be introduced. I'm leaving that to you. As it is, this code is not for production and under some circumstances can also overflow.
The particular part is the search of a specific element in the vector. Every time you tranverse the list,
and this is convenient only and only if you have sparsity (the majority of your index will always return zero).
In this implementation, if you access an index that is not enlisted, you get as a result 0. If you don't want this
you should define an error callback.
Initialization and destruction
When we initialize, we allocate the memory for our vector, but with no elements inside, thus begin points to NULL. When we destroy the vector we have not only to free the vector, but also each element contained.
vector_t * vector_init() {
vector_t * v = (vector_t*)malloc(sizeof(vector_t));
if (v) {
v->begin = NULL;
v->size = 0;
return v;
}
return NULL;
}
void vector_destroy(vector_t *v) {
if (v) {
vector_element_t * curr = v->begin;
if (curr) {
vector_element_t * next = curr->next;
while (next) {
curr = curr->next;
next = next->next;
if (curr)
free(curr);
}
if (next)
free(next);
}
free(v);
}
}
The get and set methods
In get you can see how the list works (and the same concept
is used also in set and delete): we start from the begin, and
we cross the list until we reach an element with an index equal
to the one requested. If we cannot find it we simply return 0.
If we need to "raise some sort of signal" when the value is
not found, it is easy to implement an "error callback".
As long as sparsness holds, searching in the whole array for an index is a good compromise in terms of memory requirements, and efficiency may be not an issue.
int vector_get(vector_t *v, size_t index) {
vector_element_t * el = v->begin;
while (el != NULL) {
if (el->index == index)
return el->value;
el = el->next;
}
return 0;
}
// Gosh, this set function is really a mess... I hope you can understand it...
// -.-'
size_t vector_set(vector_t *v, size_t index, int value) {
vector_element_t * el = v->begin;
// Case 1: Initialize the first element of the array
if (el == NULL) {
el = (vector_element_t *)malloc(sizeof(vector_element_t));
if (el != NULL) {
v->begin = el;
v->size += 1;
el->index = index;
el->value = value;
el->next = NULL;
return v->size;
} else {
return 0;
}
}
// Case 2: Search for the element in the array
while (el != NULL) {
if (el->index == index) {
el->value = value;
return v->size;
}
// Case 3: if there is no element with that index creates a new element
if (el->next == NULL) {
el->next = (vector_element_t *)malloc(sizeof(vector_element_t));
if (el->next != NULL) {
v->size += 1;
el->next->index = index;
el->next->value = value;
el->next->next = NULL;
return v->size;
}
return 0;
}
el = el->next;
}
}
Deleting an element
With this approach it is possible to delete an element quite easily, connecting
curr->next to curr->next->next. We must though free the previous curr->next...
void vector_delete(vector_t * v, size_t index) {
vector_element_t *curr = v->begin;
vector_element_t *next = curr->next;
while (next != NULL) {
if (next->index == index) {
curr->next = next->next;
free(next);
return;
} else {
curr = next;
next = next->next;
}
}
}
An iteration function
I think this is the answer to the last part of your question,
instead passing a sequence of indexes, you pass a callback to the vector.
The callback gets and sets value in a specific index. If you want to
operate only on some specific indexes, you may include a check in the
callback itself. If you need to pass more data to the callback, check
the very last section.
void vector_each(vector_t * v, int (*f)(size_t index, int value)) {
vector_element_t *el = v->begin;
while (el) {
el->value = f(el->index, el->value);
el = el->next;
}
}
Error callback
You may want to raise some out of bounds error or something else. One solution is to enrich your list with function pointer that represent a callback that should be called when your user sk for an undefined element:
typedef struct vector {
size_t size;
vector_element_t *begin;
void (*error_undefined)(vector *v, size_t index);
} vector_t
and maybe at the end of your vector_get function you may want to do something like:
int vector_get(vector_t *v, size_t index) {
// [ . . .]
// you know at index the element is undefined:
if (v->error_undefined)
v->error_undefined(v, index);
else {
// Do something to clean up the user mess... or simply
return 0;
}
}
usually it is nice to add also an helper function to set the callback...
Passing user data to "each" callback
If you want to pass more data to the user callback, you may add a void* as last argument:
void vector_each(vector_t * v, void * user_data, int (*f)(size_t index, int value, void * user_data));
void vector_each(vector_t * v, void * user_data, int (*f)(size_t index, int value, void * user_data)) {
[...]
el->value = f(el->index, el->value, user_data);
[...]
}
if the user do not need it, he can pass a wonderful NULL.

cocos2dx : Change Array to Vector

I need to change Array to Vector as it is being depracted in cocos2dx.
Earlier it was running but after deprecation its giving error.
As I am quite new to cocos2dx I am not able to resolve this issue.
Here is my code:
int BaseScene::generateRandom()
{
//int rn = arc4random()%6+1;
int rn = rand() % 6 + 1;
Array * balls = (Array*)this->getChildren();
Array * ballsTypeLeft = Array::create();
// if(balls->count() <= 7)
{
for (int j=0; j<balls->count(); j++)
{
Node * a = (Node*)balls->objectAtIndex(j);
if(a->getTag() >= Tag_Ball_Start)
{
Ball * currentBall = (Ball*)balls->objectAtIndex(j);
bool alreadyHas = false;
for(int k=0;k<ballsTypeLeft->count();k++)
{
if(strcmp(((String*)ballsTypeLeft->objectAtIndex(k))->getCString(), (String::createWithFormat("%d",currentBall->type))->getCString()) == 0)
{
alreadyHas = true;
}
}
if(alreadyHas)
{
}
else
{
ballsTypeLeft->addObject(String::createWithFormat("%d",currentBall->type));
}
}
}
}
// CCLog("%d",ballsTypeLeft->count());
if(ballsTypeLeft->count() <=2)
{
// int tmp = arc4random()%ballsTypeLeft->count();
int tmp = rand() % ballsTypeLeft->count();
return ((String*)ballsTypeLeft->objectAtIndex(tmp))->intValue();
}
return rn;
}
How can I make this method working?
Please convert this method using Vector.
Thanks
To change cocos2d::Array to cocos2d::Vector, you must first understand it. cocos2d::Vector is implemented to mimick std::vector. std::vector is part of the STL in c++. cocos2d::Vector is built specifically to handle cocos2d::Ref. Whenever you add a Ref type to Vector it automatically retained and then released on cleanup.
Now to change Array to Vector in your code:
Store children this way:
Vector <Node*> balls = this->getChildren();
Access ball at index i this way:
Ball* ball = (Ball*)balls.at (i);
Add elements to vector this way:
balls.pushBack (myNewBall);
EDIT -
From what I understand, you want to get a random ball from the scene/layer. You can perform this by simply returning the Ball object:
Ball* BaseScene::generateRandom()
{
Vector <Node*> nodeList = this->getChildren();
Vector <Ball*> ballList;
for (int i = 0; i<nodeList.size(); i++)
{
if (ball->getTag() >= Tag_Ball_Start)
{
Ball * ball = (Ball*)nodeList.at(i);
ballList.pushBack(ball);
}
}
if (ballList.size() > 0)
{
return ballList[rand() % ballList.size()];
}
return nullptr;
}
If there is no ball it will return NULL which you can check when you call the function. The code you have linked below seems to make use of Arrays outside the function. You need to make the changes to accommodate that. I suggest studying the documentation for Vector.

Need help understanding logic of function

monthly->maxTemperature = yearData[i].high;
monthly->minTemperature = yearData[i].low;
I just can't seem to understand the logic of what the iterations will look like or how to access the proper elements in the array of data to get the proper data for each month.... without corrupting data. Thanks!
You're on the right track:
void stats(int mth, const struct Data yearData[], int size, struct Monthly* monthStats)
{
// These are used to calc averages
int highSum = 0;
int lowSum = 0;
int days = 0;
// Initialize data
monthly->maxTemperature = INT_MIN;
monthly->minTemperature = INT_MAX;
monthly->totalPrecip = 0;
for (int i = 0; i < size; ++i) {
// Only use data from given month
if (yearData[i].month == mth) {
days += 1;
if (yearData[i].high > monthly->maxTemperature) monthly->maxTemperature = yearData[i].high;
if (yearData[i].low < monthly->minTemperature) monthly->minTemperature = yearData[i].low;
highSum += yearData[i].high;
lowSum + yearData[i].low;
monthly->totalPrecip += yearData[i].precip;
}
}
if (0 != days) {
monthly->avgHigh = highSum / days;
monthly->avgLow = lowSum / days;
}
}
Before working on the assignment it's a good idea to examine the API that you need to implement for clues. First thing to notice is that the reason the struct Monthly is passed to your function by pointer is so that you could set the result into it. This is different from the reason for passing struct Data as a pointer*, which is to pass an array using the only mechanism for passing arrays available in C. const qualifier is a strong indication that you must not be trying to modify anything off of the yearData, only the monthStats.
This tells you what to do with the min, max, average, and total that you are going to find in your function: these need to be assigned to fields of monthStats, like this:
monthStats->maxTemperature = maxTemperature;
monthStats->minTemperature = minTemperature;
...
where maxTemperature, minTemperature, and so on are local variables that you declare before entering the for loop.
As far as the for loop goes, your problem is that you ignore the mth variable completely. You need to use its value to decide if an element of yearData should be considered for your computations or not. The simplest way is to add an if to your for loop:
int maxTemperature = INT_MIN; // you need to include <limits.h>
int minTemperature = INT_MAX; // to get definitions of INT_MIN and INT_MAX
for(int i = 0; i<size; ++i) {
if (yearData[i].month < mth) continue;
if (yearData[i].month > mth) break;
... // Do your computations here
}
* Even though it looks like an array, it is still passed as a pointer

Arduino - Optimising existing method for iterating through an array

Is there a more efficient and cleaner way of doing what the following method is already doing?
void sendCode(prog_uint16_t inArray[], int nLimit) {
unsigned int arr[nLimit];
unsigned int c;
int index = 0;
while ((c = pgm_read_word(inArray++))) {
arr[index] = c;
index++;
}
for (int i = 0; i < nLimit; i=i+2) {
delayMicroseconds(arr[i]);
pulseIR(arr[i+1]);
}
}
This is in reference to an existing question I had answered.
Arduino - Iterate through C array efficiently
There should be no need for the local arr array variable. If you do away with that you should both save temporary stack space and speed up execution by removing the need to copy data.
void sendCode(const prog_uint16_t inArray[]) {
unsigned int c;
for (int i = 0; c = pgm_read_word(inArray++); i++) {
if (i % 2 == 0) { // Even array elements are delays
delayMicroseconds(c);
} else { // Odd array elements are pulse lengths
pulseIR(c);
}
}
}
This code assumes that the maximum integer stored in an int is greater than the maximum size of inArray (this seems reasonable as the original code essentially makes the same assumption by using an int for nLimit).

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