Change values in a struct array - arrays

Question

Can someone explain me, please, why can't I insert values into a struct array.
Here's a piece of my code to help understand what I'm trying to accomplish.
I want to insert values inside an array which is formed by structs, whenever I try to insert values it gives me a segmentation error.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define TAM_TABELA 10
#define PRIMO 7
#define MAX_NOME 50
typedef struct {
char nome[MAX_NOME];
int telemovel;
} pessoa;
void insert(pessoa *grupo[]) {
char nome[MAX_NOME];
printf("\nInsert name:\n");
scanf("%s", nome);
int lenght = strnlen(nome, MAX_NOME);
printf("\nInsert phone:\n");
scanf("%d", &tel);
for (i = 0; i < TAM_TABELA; i++) {
if (grupo[i] == NULL) {
grupo[i]->telemovel = tel;
strcpy(grupo[i]->nome, nome);
break;
}
}
if (i == TAM_TABELA)
printf("\nO valor não pode ser inserido!\n");
}
void main() {
int opt;
pessoa p;
pessoa grupo[TAM_TABELA] = {NULL};
insert(grupo);
}

Answer 1

You need to pass the address of grupo to insert() function.
int main(void) { } is a valid C main() function prototype
size_t is a valid data type for lengths, iterate through arrays
Always check whether scanf() conversion was successful or not
Do not use "%s", use "%<WIDTH>s", to avoid buffer-overflow
for( i = 0; i < TAM_TABELA; i++) i was never defined
parameter of the function insert() should be pessoa ***grupo, in de-reference it later in your function like *grupo
Initialize your char [] using {}, which are stored on stack memory

Answer 2

for (i = 0; i < TAM_TABELA; i++) {
if (grupo[i] == NULL) {
grupo[i]->telemovel = tel;
strcpy(grupo[i]->nome, nome);
break;
}
}
Notice how you've checked that grupo[i] is NULL and then you try to access a struct member on that value that is NULL.
You possibly want to check that grupo[i] != NULL, which should make member access safe.