Why am I getting garbage value after displaying the data - c

I am getting garbage value when I display the records.
I have to create a database of students in C using array of structures and without pointers.
Is there any other way of doing this?
How to use array of structures?
#include <stdio.h>
struct student {
char first_name[10],last_name[10];
int roll;
char address[20];
float marks;
};
void accept(struct student);
void display(struct student);
void main() {
struct student S[10];
int n, i;
printf("Enter the number of records to enter : ");
scanf("%d", &n);
for (i = 0; i < n; i++) {
accept(S[i]);
}
for (i = 0; i < n; i++) {
display(S[i]);
}
}
void accept(struct student S) {
scanf("%s", S.first_name);
scanf("%s", S.last_name);
scanf("%d", &S.roll);
scanf("%s", S.address);
scanf("%f", &S.marks);
}
void display(struct student S) {
printf("\n%s", S.first_name);
printf("\n%s", S.last_name);
printf("\n%d", S.roll);
printf("\n%s", S.address);
}

Everything in C is pass-by-value. Which means you are modifying variable copy in stack frame, while real variable passed as parameter remains untouched.
You have to pass an pointer to variable which you want to modify in function.
// Function declaration
void accept(struct student *);
// Call
accept(&S[i]);
// Usage in function via dereference operator
scanf("%s",S->first_name);
If you would like to enter unknown amount of records, you should use VLA (since c99) or dynamically allocate structures.
VLA
scanf("%d",&n);
struct student S[n];
Dynamic callocation
scanf("%d",&n);
struct student * S = malloc(sizeof(struct student) * n);
Because in your case, if user input more that 9 records you are touching outside of bounds, which has undefined behavior.

There are multiple issues in your code:
The standard prototype for main without arguments is int main(void)
You should allocate the array dynamically with calloc.
you should pass structure pointers to the accept and display functions instead of passing structures by value. Passing the destination structure by value is incorrect as the accept function cannot modify the structure in the main function, which remains uninitialized and causes garbage to be displayed. Note that it is actually undefined behavior to access uninitialized data so the program could behave in even worse ways.
You should provide scanf() with the maximum number of arguments to store into character arrays to avoid potential buffer overflows.
you should verify the return values of scanf() to avoid undefined behavior on invalid input.
you could use the %[^\n] scan set to allow embedded spaces in the address field.
Here is a modified version:
#include <stdio.h>
#include <stdlib.h>
struct student {
char first_name[10], last_name[10];
int roll;
char address[20];
float marks;
};
void accept(struct student *sp);
void display(const struct student *sp);
int main(void) {
struct student *S;
int n, i, j;
printf("Enter the number of records to enter : ");
if (scanf("%d", &n) != 1)
return 1;
S = calloc(sizeof(*S), n);
if (S == NULL) {
return 1;
}
for (i = 0; i < n; i++) {
accept(&S[i]);
}
for (i = 0; i < n; i++) {
display(&S[i]);
}
free(S);
return 0;
}
void accept(struct student *sp) {
if (scanf("%9s%9s&d %19[^\n]%f",
sp->first_name, sp->last_name, &sp->roll,
sp->address, &sp->marks) != 5) {
printf("missing input\n");
exit(1);
}
}
void display(const struct student *sp) {
printf("%s\n", sp->first_name);
printf("%s\n", sp->last_name);
printf("%d\n", sp->roll);
printf("%s\n", sp->address);
printf("%f\n", sp->marks);
printf("\n");
}

Related

array of structs in c-user input

I am new to programming in general and to C in particular.
I am trying to write a program that uses an array of structs, but I am experiencing problems if that struct contains strings.
Somehow the compiler crashes after the user has given the last input.
The struct below is just a simplified version containing only one item, because the problem seems to be reading strings into the array.
Any help is much appreciated, thanks in advance.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct
{
char* name;
}student;
int main()
{
int size;
printf("enter number of entries\n");
scanf("%d" , &size);
student* all=malloc(size*sizeof(student));
int i;
for(i=0;i<size;i++)
{
printf("enter name\n");
scanf("%s" , all[i].name);
}
return 0;
}
Before taking input scanf("%s" , all[i].name); , you need to allocate memory to all[i].name .
An example-
for(i=0;i<size;i++)
{
all[i].name=malloc(20*sizeof(*(all[i].name)));
if(all[i].name!=NULL){
printf("enter name\n");
scanf("%19s" , all[i].name);
}
}
//use these strings
for(i=0;i<size;i++){
free(all[i].name); //free the allocated memory
}
free(all);
Or in your structure instead of char * ,declare name as a char array (if you don't want to use dynamic allocation)-
typedef struct{
char name[20]; //give any desired size
}student;
/* no need to free in this case */
No memory is allocated for the students names (char* name), so when trying to scanf to that pointer, invalid memory is accessed and the program crashes.
The easiest way is to declare name as an array: char name[28];
The return value of malloc() needs to be checked too, in case there was problem allocating the memory for the students, which would return a NULL pointer. At the end, the allocated memory needs to be freed with free().
For example:
#include <stdio.h>
#include <stdlib.h>
typedef struct {
char name[28];
unsigned int age;
} student;
int main()
{
size_t size = 0;
printf("\nEnter number of entries: ");
scanf("%zu", &size);
// add some check for size
student* students = (student*)malloc(size * sizeof(student));
if (students == NULL) {
printf("\nProblem with allocating memory:\n"
" - size: %zu\n"
" - total size needed: %zu\n",
size, size * sizeof(student));
return 0;
}
for (size_t i = 0; i < size; ++i) {
printf("Enter name: ");
scanf("%27s", students[i].name);
printf(" Enter age: ");
scanf("%u", &students[i].age);
}
printf("\nList of students:\n");
for (size_t i = 0; i < size; ++i) {
printf("%s (%u)\n", students[i].name, students[i].age);
}
free(students); // free the allocated memory
return 0;
}

I cannot store integer in structure

I created a struct Book with the properties.I let the user to create the structure objects with for-loop.Like Books[i] Books1, Books2 etc...
The problem is that i cant store integer values in the structure.
The code is given below.
#include <stdlib.h>
#include <stdio.h>
struct Book {
int ID[];
char book_name[80];
char author_name[50];
int pblsh_date[];
};
struct Book *Books;
void Create();
int main() {
int count;
printf("How many books do you want to enter? ");
scanf("%d", &count);
Create(count);
//Show
printf("ID\t\tName\tAuthor\tPublish Year\n");
for (int i= 0; i < count; i++)
printf("%d\t%s\t%s\t%d\n", Books[i].ID, Books[i].book_name, Books[i].author_name, Books[i].pblsh_date);
if (Books) {
free(Books);
}
getchar();
return 0;
}
void Create(int count) {
Books = (struct Book*) malloc(count * sizeof(struct Book));
int i;
for (i = 0; i < count; i++) {
printf("%d. Book's ID: ", i+1);
scanf("%d", Books[i].ID);
printf("Book's name: ");
scanf("%s", Books[i].book_name);
printf("Author: ");
scanf("%s", Books[i].author_name);
printf("Publish Year: ");
scanf("%d", Books[i].pblsh_date);
}
}
The definition of the structure that you posted contains two empty arrays: int ID[]; and int pblsh_date[];. Since you did not specify a size and the compiler is not throwing an error, it is not allocating any storage for the array data: the arrays are zero-length and you are overwriting the data that follows them when you scanf into them.
Since you only want a single integer, the correct way to define the structure is
struct Book {
int ID;
char book_name[80];
char author_name[50];
int pblsh_date;
};
The only other change you need to make to your program is the arguments to scanf: scanf("%d", &(Books[i].ID)); and scanf("%d", &(Books[i].pblsh_date));. The reason is that scanf requires the address of the place you want to put the result. While scanf("%s", Books[i].book_name); works as is, you need to add the & operator to int variables. book_name is an array, which in C is treated as a pointer containing the address of the buffer you want to write to. ID is an int, so you need to get its address to know where to write to. Notice how you already did this in main with scanf("%d", &count);.

Program with array of structs crashes

I have an array with multiple structs. When i ask the user to enter data the first time everything works but when i ask again for the next position in the array the program crashes. If this method doesn't work souldn't the program crash in the beginning? Is something wrong with malloc?
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
struct student {
char name[50];
int semester;
};
struct prof {
char name[50];
char course[50];
};
struct student_or_prof {
int flag;
int size;
int head;
union {
struct student student;
struct prof prof;
}
}exp1;
struct student_or_prof *stack;
void init(int n)
{
stack = malloc(n);
}
int push(struct student_or_prof **pinx,int *head,int n)
{
char name[50];
printf("\nn= %d\n",n);
printf("\nhead= %d\n",*head);
if(*head==n)
{
printf("Stack is full.\n");
return 1;
}
char x;
printf("Student or Professor? [s/p] ");
getchar() != '\n';
scanf("%c",&x);
if(x=='s')
{
getchar() != '\n';
pinx[*head]->flag = 0;
printf("\n\nGive student's name: ");
fgets(pinx[*head]->student.name,sizeof(pinx[*head]->student.name),stdin);
printf("\nGive student's semester: ");
scanf("%d",&(pinx[*head]->student.semester));
printf("\nName = %s\tSemester = %d",pinx[*head]->student.name,pinx[*head]->student.semester);
}
else if(x=='p')
{
getchar() != '\n';
pinx[*head]->flag = 1;
printf("\n\nGive professor's name: ");
fgets(pinx[*head]->prof.name,sizeof(pinx[*head]->prof.name),stdin);
printf("\nGive course: ");
fgets(pinx[*head]->prof.course,sizeof(pinx[*head]->prof.course),stdin);
printf("\nName = %s\tCourse = %s\n",pinx[*head]->prof.name,pinx[*head]->prof.course);
}
(*head)++;
printf("\nhead= %d\n",*head);
}
int main()
{
int n,i;
printf("Give size: ");
scanf("%d",&n);
init(n);
for(i=0;i<n;i++)
push(&stack,&exp1.head,n);
return 0;
}
You need to malloc the structure not n
malloc(sizeof(struct student_or_prof)*n)
EDIT:
And your code crashes again because pinx is a double pointer, so this operation is not valid:
pinx[*head]->flag = 0;
this is equivalent to:
*(pinx + *head)->flag = 0;
Since you are not changing what stack points to, you are better off using a single pointer instead of a double pointer.
So instead you should change your push API:
int push(struct student_or_prof *pinx,int *head,int n)
and call it like:
push(stack,&exp1.head,n);
malloc allocates the given number of bytes.
You have to multiply n with the size of your struct, to allocate enough memory.
pinx does not point to an array, so pinx[*head] is going to access invalid memory unless *head is zero.
I think you meant (*pinx)[*head] , which accesses the N-th element of the array you allocated via malloc. For example (*pinx)[*head].prof.name etc.
BTW, your head number doesn't seem to be used at all, except for exp1.head, maybe it'd be better to remove head from the struct, and just have a single variable head?

Am I using structs in the wrong way?

I have come across this wierd and mysterous (at least to me) error that I am finding a very hard time finding. It gives me an error at the line where I call my function input(student_list1[MAX], &total_entries); where the compiler says:
incompatible type for agument 1 in 'input'
What am I doing wrong here? I sense it something very simple and stupid but I have gone through the code several times now without any avail.
#define MAX 10
#define NAME_LEN 15
struct person {
char name[NAME_LEN+1];
int age;
};
void input(struct person student_list1[MAX], int *total_entries);
int main(void)
{
struct person student_list1[MAX];
int total_entries=0, i;
input(student_list1[MAX], &total_entries);
for(i=0; i<total_entries; i++)
{
printf("Student 1:\tNamn: %s.\tAge: %s.\n", student_list1[i].name, student_list1[i].age);
}
return 0;
} //main end
void input(struct person student_list1[MAX], int *total_entries)
{
int done=0;
while(done!=1)
{
int i=0;
printf("Name of student: ");
fgets(student_list1[i].name, strlen(student_list1[i].name), stdin);
student_list1[i].name[strlen(student_list1[i].name)-1]=0;
if(student_list1[i].name==0) {
done=1;
}
else {
printf("Age of student: ");
scanf("%d", student_list1[i].age);
*total_entries++;
i++;
}
}
}
struct person student_list1[MAX] in the function argument is actually a pointer to struct person student_list1.
student_list1[MAX] you passed is a (out of bound) member of the array struct person student_list1[MAX]. Valid array index shoudl be between 0 to MAX - 1.
Change it to:
input(student_list1, &total_entries);
Note that here the array name student_list1 is automatically converted to a pointer to student_list1[0].
There are many things wrong with the code; this is my attempt at making it somewhat more robust:
#include <stdio.h>
#include <string.h>
#define MAX 10
#define NAME_LEN 15
// use a typedef to simplify code
typedef struct person {
char name[NAME_LEN];
int age;
} person_t;
// size qualifier on student_list is redundent and person_t* does the same
void input(person_t *student_list, int *total_entries);
int main(void)
{
person_t student_list[MAX];
int total_entries, i;
// pass array and not the non-existent 'student_list[MAX]' element
input(student_list, &total_entries);
for(i=0; i<total_entries; i++)
{
// age is an int, not a string so use %d
printf("Student 1:\tName: %s.\tAge: %d.\n", student_list[i].name, student_list[i].age);
}
return 0;
} //main end
void input(person_t *student_list, int *total_entries)
{
int done = 0, i = 0;
*total_entries = 0;
while (i < MAX) {
printf("Name of student: ");
// use NAME_LEN instead of strlen(list[i].name) because latter is
// probably not initialized at this stage
if (fgets(student_list[i].name, NAME_LEN, stdin) == NULL) {
return;
}
// detect zero-length string
if (student_list[i].name[0] == '\n') {
return;
}
printf("Age of student: ");
scanf("%d", &student_list[i].age);
// read the newline
fgetc(stdin);
*total_entries = ++i;
}
}
input(student_list1[MAX], &total_entries); shoud be input(student_list1, &total_entries);.
In C,
void input(struct person student_list1[MAX], int *total_entries);
equals
void input(struct person *student_list1, int *total_entries);

dynamic array of structs in C

I am trying to learn about structs, pointers, and dynamic arrays in C. I don't understand how to create a dynamic array of structs using pointers. My code doesn't work, and I don't know what's wrong with it. I have seen several examples of dynamic arrays, but non with structs. Any help would be appreciated. Please give some explanation, not just code snippets as I do want to understand not just solve this problem.
#include<stdio.h>
#include<stdlib.h>
#include <string.h>
struct *struct_array;
int i,m,n,p;
struct data
{
char inputA[20];
char inputB[20];
};
struct data get_data()
{
struct data thisdata;
printf("Please enter input A\n");
scanf("%s", thisdata.inputA);
printf("Please enter input B\n");
scanf("%s", thisdata.inputB);
return thisdata;
}
void Output(struct data struct_array, int n)
{
int index = 0;
for(i = 0; i<n ;i++)
{
printf("%s ", struct_array[i].inputA);
printf("%s ", struct_array[i].inputB);
}
}
void resizeArray(int n)
{
struct_array = (int*)realloc(n*sizeof(int));
}
void mainMenu()
{
printf("Please select from the following options:\n");
printf("1: Add new students to database\n");
printf("2: Display current student database contents\n");
printf("3: exit the program\n");
scanf("%d", &p);
if(p == 1)
{
printf("Please enter the number of students to register:\n");
scanf("%d", &n);
resizeArray(n);
for(i = n; i<n ;i++)
{
struct_array[i] = get_data();
}
}
else if(p == 2)
{
Output(struct_array, n);
}
else
{
free(struct_array);
exit(0);
}
}
int main()
{
struct_array = (int*)realloc(2*sizeof(int));
mainMenu();
}
You have several errors in your source code:
struct *struct_array; (l. 5)
What does it mean? Did you want to write struct data *struct_array?
printf("%s ", struct_array[i].inputA); (l.32 & l. 33)
The argument struct_array masks the global declaration, and it is not an array. Why did you add this argument?
struct_array = (int *)realloc(n * sizeof(int)); (l. 39)
You have forgotten an argument. Did you want to use malloc instead? Besides, the cast is not necessary (and incorrect!).
Unless you are using an hosted environnment and C99/C11, you should return a value from main.
Your variable index is not used. Why did you declare it?
for(i = n; i < n; i++) (l. 53)
You won't have any iteration here...
The following code works as expected.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
/* TODO: Avoid global variables. */
struct data *struct_array;
struct data {
char inputA[20];
char inputB[20];
};
/*
* TODO: Try to avoid passing your structure (40 bytes + padding)
* without pointer.
*/
struct data get_data(void)
{
struct data thisdata;
printf("Please enter input A\n");
/* TODO: Avoid using `scanf` for human inputs. */
scanf("%s", thisdata.inputA);
printf("Please enter input B\n");
scanf("%s", thisdata.inputB);
return thisdata;
}
void Output(size_t n)
{
size_t i;
for (i = 0; i < n; i++) {
printf("%s ", struct_array[i].inputA);
printf("%s ", struct_array[i].inputB);
}
}
void resizeArray(size_t n)
{
/* TODO: Handle reallocations errors. */
struct_array = realloc(struct_array, n * sizeof *struct_array);
}
void mainMenu(void)
{
size_t i, n;
int p;
/* TODO: Use a loop ? */
printf("Please select from the following options:\n");
printf("1: Add new students to database\n");
printf("2: Display current student database contents\n");
printf("3: exit the program\n");
scanf("%d", &p);
switch (p) {
case 1:
printf("Please enter the number of students to register:\n");
scanf("%u", &n);
resizeArray(n);
for (i = 0; i < n; i++)
struct_array[i] = get_data();
break;
case 2:
Output(n);
break;
}
}
int main(void)
{
struct_array = malloc(2 * sizeof(int));
mainMenu();
free(struct_array);
return 0;
}
Your definition
struct *struct_array;
is erroneous. You must use the name of your type, the data.
struct data *struct_array;
This way you can allocate the array
struct_array = malloc(MaxNumElements * sizeof(struct data));
and later you should free the memory
free(struct_array);
EDIT: Type definition must occur before the var declaration.
struct data ....
struct data* your_variable;
P.S. If you do not want to type struct keyword each time you use the data type, use the typedef:
typedef struct data_s
{
char inputA[20];
char inputB[20];
} data;
Do you know how to use typedef?
I would suggest it, makes your code easier to understand and you won't have to be typing the word struct a thousand times. Also you could treat the new type similar to the primitive types (ints, chars, etc), just don't forget to use the dot (.) to access the individual fields you might want.
You could type for instance:
typedef struct{
char inputA[20];
char inputB[20];
} data;
Now you could declare variables like this:
data data_variable;
data *pointer_to_data;
And to you could allocate memory as follows:
pointer_to_data = (data*) malloc(sizeof(data)* N);
where N is the amount of struct data you want to allocate. Same works for realloc.
struct_array = (int*)realloc(2*sizeof(int));
By the above statement you are trying to assign address of an int to a pointer of type struct data.
You need to use:
struct_array = (struct data*)realloc(2*sizeof(struct data));

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