array of structs in c-user input - c

I am new to programming in general and to C in particular.
I am trying to write a program that uses an array of structs, but I am experiencing problems if that struct contains strings.
Somehow the compiler crashes after the user has given the last input.
The struct below is just a simplified version containing only one item, because the problem seems to be reading strings into the array.
Any help is much appreciated, thanks in advance.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct
{
char* name;
}student;
int main()
{
int size;
printf("enter number of entries\n");
scanf("%d" , &size);
student* all=malloc(size*sizeof(student));
int i;
for(i=0;i<size;i++)
{
printf("enter name\n");
scanf("%s" , all[i].name);
}
return 0;
}

Before taking input scanf("%s" , all[i].name); , you need to allocate memory to all[i].name .
An example-
for(i=0;i<size;i++)
{
all[i].name=malloc(20*sizeof(*(all[i].name)));
if(all[i].name!=NULL){
printf("enter name\n");
scanf("%19s" , all[i].name);
}
}
//use these strings
for(i=0;i<size;i++){
free(all[i].name); //free the allocated memory
}
free(all);
Or in your structure instead of char * ,declare name as a char array (if you don't want to use dynamic allocation)-
typedef struct{
char name[20]; //give any desired size
}student;
/* no need to free in this case */

No memory is allocated for the students names (char* name), so when trying to scanf to that pointer, invalid memory is accessed and the program crashes.
The easiest way is to declare name as an array: char name[28];
The return value of malloc() needs to be checked too, in case there was problem allocating the memory for the students, which would return a NULL pointer. At the end, the allocated memory needs to be freed with free().
For example:
#include <stdio.h>
#include <stdlib.h>
typedef struct {
char name[28];
unsigned int age;
} student;
int main()
{
size_t size = 0;
printf("\nEnter number of entries: ");
scanf("%zu", &size);
// add some check for size
student* students = (student*)malloc(size * sizeof(student));
if (students == NULL) {
printf("\nProblem with allocating memory:\n"
" - size: %zu\n"
" - total size needed: %zu\n",
size, size * sizeof(student));
return 0;
}
for (size_t i = 0; i < size; ++i) {
printf("Enter name: ");
scanf("%27s", students[i].name);
printf(" Enter age: ");
scanf("%u", &students[i].age);
}
printf("\nList of students:\n");
for (size_t i = 0; i < size; ++i) {
printf("%s (%u)\n", students[i].name, students[i].age);
}
free(students); // free the allocated memory
return 0;
}

Related

How do I insert char* to array of structures?

the task is to dynamically allocate memory for the array of structures and then fill them from keyboard. I was able to dynamically allocate and fill amount of pages for each of the struct instance in array, but when I try to add char* to it by doing something like:
strcpy(myArray[i]->author, authorName);
But every time I get segmentation error, so what am I doing wrong?
Is it possible that problem is actually in memory allocation?
Here is the code
#include <stdlib.h>
#include <string.h>
struct Book {
char* author;
char* title;
int pages;
int pubYear;
int copies;
};
void allocList(struct Book **myArray, int booksAmount);
void fillKeyboard(struct Book **myArray, int booksAmount);
int main(void) {
struct Book *booksList = NULL;
int booksAmount = 3;
allocList(&booksList, booksAmount);
fillKeyboard(&booksList, booksAmount);
return 0;
}
void allocList(struct Book **myArray, int booksAmount) {
*myArray = (struct Book*) malloc(sizeof(struct Book) * 100);
printf("memory for %d books was allocated \n", booksAmount);
}
void fillKeyboard(struct Book **myArray, int booksAmount) {
int i = 0;
char* authorName = "author name";
while (booksAmount--) {
printf("book number %d \n", i + 1);
printf("enter amount of pages: ");
scanf("%d", &(*myArray)[i].pages);
printf("\nenter author: ");
strcpy(myArray[i]->author, authorName);
printf("%s is \n", authorName);
i++;
printf("\n");
}
}
Thank you.
myArray[i].author is a string.
so (in C) an array of char.
as an array you need to allocate it with a malloc
myArray[i].author=malloc(sizeof(char) * 100);
your while loop should look like this:
while (booksAmount--) {
myArray[i].author=malloc(sizeof(char) * 100);
printf("book number %d \n", i + 1);
printf("enter amount of pages: ");
scanf("%d", &(myArray)[i].pages);
printf("\nenter author: ");
strcpy(myArray[i].author, authorName);
printf("%s is \n", authorName);
i++;
printf("\n");
}
keep in mind that 100 is a "magic number" so if the author name is longer than 100 character it's not going to work
edit: same thing with the title, you need to allocate the needed memory in your array's element
If you care about memory, you should not create an array of 100 books. A good way to avoid such allocations is linked lists, so your program will always allocate just the needed memory. Your Book struct would look like this:
struct Book {
char* author;
char* title;
int pages;
int pubYear;
int copies;
struct Book *next;
};
The program will certainly be a bit more complex, but the result is a clean memory usage, and a truly dynamic program.

Trying to input a strcture, first time works great, second time crashes

Hi I'm inputting a structure of a family with children with those two structures:
typedef struct person {
int id;
char* firstName;
int age;
}person;
typedef struct family {
char* lastName;
person father, mother;
person* children;
int numChildren;
}family;
EDIT: this is the edited function and it still crashes :
int initializeHouse(family **pdata)
{
char temp[SIZE];
int size, i, j;
printf("enter the number of families\n");
scanf("%d", &size);
*pdata = (family*)malloc(sizeof( family)*size);
for (i = 0; i<size; i++)
{
printf("Please enter the last name\n");
scanf("%s", temp);
(*pdata)[i].lastName = (char*)malloc(sizeof(char)* (strlen(temp) + 1));
strcpy(pdata[i]->lastName, temp);
printf("Enter the fathers first name\n");
scanf("%s", temp);
initPerson(temp, &pdata[i]->father.firstName);
printf("enter the fathers ID\n");
scanf("%d", &pdata[i]->father.id);
printf("Enter the fathers age\n");
scanf("%d", &pdata[i]->father.age);
printf("Enter the mothers first name\n");
scanf("%s", temp);
initPerson(temp, &pdata[i]->mother.firstName);
printf("enter the mothers ID\n");
scanf("%d", &pdata[i]->mother.id);
printf("Enter the mothers age\n");
scanf("%d", &pdata[i]->mother.age);
printf("enter the number of children");
scanf("%d", &pdata[i]->numChildren);
(*pdata)[i].children= (person*)malloc(sizeof(person)*(pdata[i]->numChildren));
for (j = 0; j<pdata[i]->numChildren; j++)
{
printf("enter the kids name\n");
scanf("%s", temp);
initPerson(temp, &pdata[i]->children[j].firstName);
printf("enter the kids ID\n");
scanf("%d", &pdata[i]->children[j].id);
printf("Enter the kids age\n");
scanf("%d", &pdata[i]->children[j].age);
}
}
return size;
}
void initPerson(char* str, char** fam)
{
*fam = (char*)malloc(sizeof(char)*(strlen(str) + 1));
strcpy(*fam, str);
}
EDIT: I changed the code and it still doesn't work, and it requires me to write some description so here it is ..
int main() {
int size;
family *a = NULL;
size=initializeHouse(&a);
}
declares a pointer to a family structure. When you pass it's address
size = initializeHouse(&a);
the function gets it as a family**
Okay, we're all on the same page to this point. When you allocate the target of that pointer
*pdata = malloc(sizeof(family) * size);
then *pdata points to an allocated array of structs, not pointers to those structs. Each struct is accessed by (*pdata)[i], which means -> dereference the double pointer pdata to get the address of the first element in the array, then access the array element with a subscript.
So your assignment should be
(*pdata)[i].lastName = malloc(sizeof(char)* (strlen(temp) + 1));
You use the dot . operator to access the members, because the result of the subscript access is a struct, not a pointer to a struct.
This little example using (*pdata)[i]. doesn't crash.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define SIZE 40
typedef struct person {
int id;
char* firstName;
int age;
}person;
typedef struct family {
char* lastName;
person father, mother;
person* children;
int numChildren;
}family;
int initializeHouse(family **pdata)
{
char temp[SIZE];
int size, i, j;
printf("enter the number of families\n");
scanf("%d", &size);
*pdata = malloc(sizeof(family)*size);
for (i = 0; i<size; i++)
{
printf("Please enter the last name\n");
scanf("%39s", temp);
(*pdata)[i].lastName = malloc(sizeof(char)* (strlen(temp) + 1));
strcpy ( (*pdata)[i].lastName, temp);
}
return size;
}
int main ( void) {
int size;
family *a;
size=initializeHouse(&a);
}
It's important that you understand the memory layout.
family *fam;
family **pdata = &fam;
*pdata = (family*)malloc(sizeof(family)*size);
You have essentialy this: fam is a uninitialized pointer of type family.
pdata is a double pointer initialized with the address of fam. The malloc
call allocates space for size family-objects. By doing *pdata = malloc(...)
you are initializing fam.
This is the basic memory layout you have. base is the address returned by
malloc. slf is the size of struct family object, fpl is the size of a
pointer to a struct family object.
base = address returned by malloc
sfl = sizeof(struct family)
fpl = sizeof(struct family*)
base + 0 base + slf base + 2 * slf
+-----------------+------------------+------------------+
|struct family | struct family | struct family |
+-----------------+------------------+------------------+
base + 0 base + fpl base + 2*fpl base + 3*fpl base + 4*fpl
+------------+------------+------------+------------+-----------+
| pdata[0] | pdata[1] | pdata[2] | pdata[3] | pdata[4] |
+------------+------------+------------+------------+-----------+
The first row shows the memory in terms on struct family objects, the second
row shows you the same memory in terms on pointers (to struct family object).
This is very important distinction, because pdata[i] returns you a
pointer, not the object.
Remember pdata is a double pointer, pdata[i] is the equivalent to pdata + i,
that is the ith pointer begining at base.
Because the size of an struct family is defintitely different that the size of
a pointer, you see that the block don't align, that means
base + slf != base + fpl.
In the first iteration you are lucky, because pdata[0] and (*pdata)[0] are
the same. But pdata[1] and *(pdata)[1] are not the same. So doing
pdata[1]->lastname (instead of (*pdata)[1].lastname) you are accessing at a
wrong location in you allocated memory.
The easiest way to fix you code would be to change the pdata[i] in (*pdata)[i] as shown
in user3121023's answer.
edit
I see that user3121023 has retracted his answer. Basically it did:
printf("enter the fathers ID\n");
scanf("%d", &((*pdata)[i].father.id));
in the loop.
Fixing the pointers may have solved your problem. But the program has a lot of duplicate code and rewriting as follows would help you test a small portion and debug the program easily.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define SIZE 100
typedef struct person {
int id;
char *firstName;
int age;
} person;
typedef struct family {
char *lastName;
person father, mother;
person *children;
int numChildren;
} family;
void input_string(const char *prompt, char **where) {
char temp[SIZE];
printf("%s\n", prompt);
scanf("%s", temp);
*where = malloc(sizeof(char) * (strlen(temp) + 1));
strcpy(*where, temp);
}
void input_int(const char *prompt, int *where) {
printf("%s\n", prompt);
scanf("%d", where);
}
void input_person(const char *name, person *person) {
char prompt[SIZE];
sprintf(prompt, "Enter the %s's first name", name);
input_string(prompt, &person->firstName);
sprintf(prompt, "Enter the %s's ID", name);
input_int(prompt, &person->id);
sprintf(prompt, "Enter the %s's age", name);
input_int(prompt, &person->age);
}
void input_family(family *fam) {
input_string("Please enter the last name", &fam->lastName);
input_person("father", &fam->father);
input_person("mother", &fam->mother);
input_int("Please enter the number of children", &fam->numChildren);
fam->children = malloc(sizeof(person) * (fam->numChildren));
for (int i = 0; i < fam->numChildren; i++) {
input_person("kid", &(fam->children)[i]);
}
}
int initializeHouse(family **families) {
int size;
input_int("Please enter the number of families", &size);
*families = malloc(sizeof(family) * size);
for (int i = 0; i < size; i++) {
input_family(&(*families)[i]);
}
return size;
}
int main() {
int size = 0;
family *a;
size = initializeHouse(&a);
printf("Successfully inputted %d families", size);
return 0;
}

Why am I getting garbage value after displaying the data

I am getting garbage value when I display the records.
I have to create a database of students in C using array of structures and without pointers.
Is there any other way of doing this?
How to use array of structures?
#include <stdio.h>
struct student {
char first_name[10],last_name[10];
int roll;
char address[20];
float marks;
};
void accept(struct student);
void display(struct student);
void main() {
struct student S[10];
int n, i;
printf("Enter the number of records to enter : ");
scanf("%d", &n);
for (i = 0; i < n; i++) {
accept(S[i]);
}
for (i = 0; i < n; i++) {
display(S[i]);
}
}
void accept(struct student S) {
scanf("%s", S.first_name);
scanf("%s", S.last_name);
scanf("%d", &S.roll);
scanf("%s", S.address);
scanf("%f", &S.marks);
}
void display(struct student S) {
printf("\n%s", S.first_name);
printf("\n%s", S.last_name);
printf("\n%d", S.roll);
printf("\n%s", S.address);
}
Everything in C is pass-by-value. Which means you are modifying variable copy in stack frame, while real variable passed as parameter remains untouched.
You have to pass an pointer to variable which you want to modify in function.
// Function declaration
void accept(struct student *);
// Call
accept(&S[i]);
// Usage in function via dereference operator
scanf("%s",S->first_name);
If you would like to enter unknown amount of records, you should use VLA (since c99) or dynamically allocate structures.
VLA
scanf("%d",&n);
struct student S[n];
Dynamic callocation
scanf("%d",&n);
struct student * S = malloc(sizeof(struct student) * n);
Because in your case, if user input more that 9 records you are touching outside of bounds, which has undefined behavior.
There are multiple issues in your code:
The standard prototype for main without arguments is int main(void)
You should allocate the array dynamically with calloc.
you should pass structure pointers to the accept and display functions instead of passing structures by value. Passing the destination structure by value is incorrect as the accept function cannot modify the structure in the main function, which remains uninitialized and causes garbage to be displayed. Note that it is actually undefined behavior to access uninitialized data so the program could behave in even worse ways.
You should provide scanf() with the maximum number of arguments to store into character arrays to avoid potential buffer overflows.
you should verify the return values of scanf() to avoid undefined behavior on invalid input.
you could use the %[^\n] scan set to allow embedded spaces in the address field.
Here is a modified version:
#include <stdio.h>
#include <stdlib.h>
struct student {
char first_name[10], last_name[10];
int roll;
char address[20];
float marks;
};
void accept(struct student *sp);
void display(const struct student *sp);
int main(void) {
struct student *S;
int n, i, j;
printf("Enter the number of records to enter : ");
if (scanf("%d", &n) != 1)
return 1;
S = calloc(sizeof(*S), n);
if (S == NULL) {
return 1;
}
for (i = 0; i < n; i++) {
accept(&S[i]);
}
for (i = 0; i < n; i++) {
display(&S[i]);
}
free(S);
return 0;
}
void accept(struct student *sp) {
if (scanf("%9s%9s&d %19[^\n]%f",
sp->first_name, sp->last_name, &sp->roll,
sp->address, &sp->marks) != 5) {
printf("missing input\n");
exit(1);
}
}
void display(const struct student *sp) {
printf("%s\n", sp->first_name);
printf("%s\n", sp->last_name);
printf("%d\n", sp->roll);
printf("%s\n", sp->address);
printf("%f\n", sp->marks);
printf("\n");
}

Program with array of structs crashes

I have an array with multiple structs. When i ask the user to enter data the first time everything works but when i ask again for the next position in the array the program crashes. If this method doesn't work souldn't the program crash in the beginning? Is something wrong with malloc?
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
struct student {
char name[50];
int semester;
};
struct prof {
char name[50];
char course[50];
};
struct student_or_prof {
int flag;
int size;
int head;
union {
struct student student;
struct prof prof;
}
}exp1;
struct student_or_prof *stack;
void init(int n)
{
stack = malloc(n);
}
int push(struct student_or_prof **pinx,int *head,int n)
{
char name[50];
printf("\nn= %d\n",n);
printf("\nhead= %d\n",*head);
if(*head==n)
{
printf("Stack is full.\n");
return 1;
}
char x;
printf("Student or Professor? [s/p] ");
getchar() != '\n';
scanf("%c",&x);
if(x=='s')
{
getchar() != '\n';
pinx[*head]->flag = 0;
printf("\n\nGive student's name: ");
fgets(pinx[*head]->student.name,sizeof(pinx[*head]->student.name),stdin);
printf("\nGive student's semester: ");
scanf("%d",&(pinx[*head]->student.semester));
printf("\nName = %s\tSemester = %d",pinx[*head]->student.name,pinx[*head]->student.semester);
}
else if(x=='p')
{
getchar() != '\n';
pinx[*head]->flag = 1;
printf("\n\nGive professor's name: ");
fgets(pinx[*head]->prof.name,sizeof(pinx[*head]->prof.name),stdin);
printf("\nGive course: ");
fgets(pinx[*head]->prof.course,sizeof(pinx[*head]->prof.course),stdin);
printf("\nName = %s\tCourse = %s\n",pinx[*head]->prof.name,pinx[*head]->prof.course);
}
(*head)++;
printf("\nhead= %d\n",*head);
}
int main()
{
int n,i;
printf("Give size: ");
scanf("%d",&n);
init(n);
for(i=0;i<n;i++)
push(&stack,&exp1.head,n);
return 0;
}
You need to malloc the structure not n
malloc(sizeof(struct student_or_prof)*n)
EDIT:
And your code crashes again because pinx is a double pointer, so this operation is not valid:
pinx[*head]->flag = 0;
this is equivalent to:
*(pinx + *head)->flag = 0;
Since you are not changing what stack points to, you are better off using a single pointer instead of a double pointer.
So instead you should change your push API:
int push(struct student_or_prof *pinx,int *head,int n)
and call it like:
push(stack,&exp1.head,n);
malloc allocates the given number of bytes.
You have to multiply n with the size of your struct, to allocate enough memory.
pinx does not point to an array, so pinx[*head] is going to access invalid memory unless *head is zero.
I think you meant (*pinx)[*head] , which accesses the N-th element of the array you allocated via malloc. For example (*pinx)[*head].prof.name etc.
BTW, your head number doesn't seem to be used at all, except for exp1.head, maybe it'd be better to remove head from the struct, and just have a single variable head?

dynamic array of structs in C

I am trying to learn about structs, pointers, and dynamic arrays in C. I don't understand how to create a dynamic array of structs using pointers. My code doesn't work, and I don't know what's wrong with it. I have seen several examples of dynamic arrays, but non with structs. Any help would be appreciated. Please give some explanation, not just code snippets as I do want to understand not just solve this problem.
#include<stdio.h>
#include<stdlib.h>
#include <string.h>
struct *struct_array;
int i,m,n,p;
struct data
{
char inputA[20];
char inputB[20];
};
struct data get_data()
{
struct data thisdata;
printf("Please enter input A\n");
scanf("%s", thisdata.inputA);
printf("Please enter input B\n");
scanf("%s", thisdata.inputB);
return thisdata;
}
void Output(struct data struct_array, int n)
{
int index = 0;
for(i = 0; i<n ;i++)
{
printf("%s ", struct_array[i].inputA);
printf("%s ", struct_array[i].inputB);
}
}
void resizeArray(int n)
{
struct_array = (int*)realloc(n*sizeof(int));
}
void mainMenu()
{
printf("Please select from the following options:\n");
printf("1: Add new students to database\n");
printf("2: Display current student database contents\n");
printf("3: exit the program\n");
scanf("%d", &p);
if(p == 1)
{
printf("Please enter the number of students to register:\n");
scanf("%d", &n);
resizeArray(n);
for(i = n; i<n ;i++)
{
struct_array[i] = get_data();
}
}
else if(p == 2)
{
Output(struct_array, n);
}
else
{
free(struct_array);
exit(0);
}
}
int main()
{
struct_array = (int*)realloc(2*sizeof(int));
mainMenu();
}
You have several errors in your source code:
struct *struct_array; (l. 5)
What does it mean? Did you want to write struct data *struct_array?
printf("%s ", struct_array[i].inputA); (l.32 & l. 33)
The argument struct_array masks the global declaration, and it is not an array. Why did you add this argument?
struct_array = (int *)realloc(n * sizeof(int)); (l. 39)
You have forgotten an argument. Did you want to use malloc instead? Besides, the cast is not necessary (and incorrect!).
Unless you are using an hosted environnment and C99/C11, you should return a value from main.
Your variable index is not used. Why did you declare it?
for(i = n; i < n; i++) (l. 53)
You won't have any iteration here...
The following code works as expected.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
/* TODO: Avoid global variables. */
struct data *struct_array;
struct data {
char inputA[20];
char inputB[20];
};
/*
* TODO: Try to avoid passing your structure (40 bytes + padding)
* without pointer.
*/
struct data get_data(void)
{
struct data thisdata;
printf("Please enter input A\n");
/* TODO: Avoid using `scanf` for human inputs. */
scanf("%s", thisdata.inputA);
printf("Please enter input B\n");
scanf("%s", thisdata.inputB);
return thisdata;
}
void Output(size_t n)
{
size_t i;
for (i = 0; i < n; i++) {
printf("%s ", struct_array[i].inputA);
printf("%s ", struct_array[i].inputB);
}
}
void resizeArray(size_t n)
{
/* TODO: Handle reallocations errors. */
struct_array = realloc(struct_array, n * sizeof *struct_array);
}
void mainMenu(void)
{
size_t i, n;
int p;
/* TODO: Use a loop ? */
printf("Please select from the following options:\n");
printf("1: Add new students to database\n");
printf("2: Display current student database contents\n");
printf("3: exit the program\n");
scanf("%d", &p);
switch (p) {
case 1:
printf("Please enter the number of students to register:\n");
scanf("%u", &n);
resizeArray(n);
for (i = 0; i < n; i++)
struct_array[i] = get_data();
break;
case 2:
Output(n);
break;
}
}
int main(void)
{
struct_array = malloc(2 * sizeof(int));
mainMenu();
free(struct_array);
return 0;
}
Your definition
struct *struct_array;
is erroneous. You must use the name of your type, the data.
struct data *struct_array;
This way you can allocate the array
struct_array = malloc(MaxNumElements * sizeof(struct data));
and later you should free the memory
free(struct_array);
EDIT: Type definition must occur before the var declaration.
struct data ....
struct data* your_variable;
P.S. If you do not want to type struct keyword each time you use the data type, use the typedef:
typedef struct data_s
{
char inputA[20];
char inputB[20];
} data;
Do you know how to use typedef?
I would suggest it, makes your code easier to understand and you won't have to be typing the word struct a thousand times. Also you could treat the new type similar to the primitive types (ints, chars, etc), just don't forget to use the dot (.) to access the individual fields you might want.
You could type for instance:
typedef struct{
char inputA[20];
char inputB[20];
} data;
Now you could declare variables like this:
data data_variable;
data *pointer_to_data;
And to you could allocate memory as follows:
pointer_to_data = (data*) malloc(sizeof(data)* N);
where N is the amount of struct data you want to allocate. Same works for realloc.
struct_array = (int*)realloc(2*sizeof(int));
By the above statement you are trying to assign address of an int to a pointer of type struct data.
You need to use:
struct_array = (struct data*)realloc(2*sizeof(struct data));

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