How to delete all sub array - arrays

Question

In my MongoDB database, I have a collection 'produits' with documents like this
{
"_id": {
"$oid": "6048e97b4a5f000096007505"
},
"modeles": [
{
"id": "OppoA3",
"pieces": [
{
"id": "OppoA3avn"
},
{
"id": "OppoA3bat"
}]
]
},
{
"id": "OppoA1",
"pieces": [
{
"id": "OppoA1avn",
},
{
"id": "OppoA1batt",
}
]
}
]
}
How can I delete all modeles.pieces from all my documents.
I managed to delete with a filter on modeles.id but with that code but not on all the collection
db.produits.update(
{marque_id:'OPPO', 'modeles.id':'RENOZ'},
{$set:
{
'modeles.$.pieces': []
}
}
, { multi : true }
)
I would like all documents like this finally
{
"_id": {
"$oid": "6048e97b4a5f000096007505"
},
"modeles": [
{
"id": "OppoA3",
"pieces": []
},
{
"id": "OppoA1",
"pieces": []
}
]
}
Thank you for your help.

Answer 1

I have done a javascript loop like this, but i think it's not best practice
async removePieces(){
var doc
try {
doc = await produitModel.find()
for (var produit of doc) {
for (var modele of produit.modeles) {
const filter = {'marque_id': produit.marque_id, 'modeles.id': modele.id}
const set = {
$set: {
'modeles.$.pieces': []
}
}
await db.collection('produits').updateOne(filter, set)
}
}
console.log('removePieces() ==> Terminé')
} catch(err) {
console.log(err)
}
}

Answer 2

db.produits.update({
modeles: {//This is because your second document will create failure otherwise
$exists: true
}
},
{
$set: {
"modeles.$.pieces": []
}
},
{
multi: true
})