I like using webhooks, and I think they work amazing, but what I can't figure out is giving a webhook a certain name for just one message.
You can do it by setting username in the JSON you send to Discord. The full documentation is available here: https://discord.com/developers/docs/resources/webhook#execute-webhook-jsonform-params
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I've looked all over and I can't find a solution.
I'm using discord js using non-slash commands.
How could I make it so you have a message from the bot and if someone types in the channel the bot's message will get deleted and resent
I want to do this in a sense of a server request channel so you need to add the channel you want the command to run and what you want it to say:
e.g:
Stickied Message
Name:
Request Needed:
Approved By:
how could I program that? Thanks :) <3
I ahve googled online and can't see anything relating to this topic - maybe I'm not searching the right things?
Tried Discord.js V13 | Sticky Message but did not work
I'm using Discord.js to write a bot with a number of helpful commands, however I can't seem to find anywhere on either Discord's API docs or Discord.js' docs that lists an example of the json structure for a slash command's role and channel options. I have the commands registering properly, but don't know what sort of data those interactions give me.
TL;DR: what data is returned when I call the following:
interaction.options.getChannel("channelOptionName")
//and
interaction.options.getRole("roleOptionName")
I'm not able to run any code in any reasonable amount of time, so I'm not able to just console.log it and go from there.
Thanks in advance!
İ'm Getting this error i try use example bot some user but getting this error when type help
AttributeError: 'Message' object has no attribute 'guild'
Please help also getting this error
also so much error getting more on hastebin https://hastebin.com/ipalesajus.sql
Message documentation.
Based on the documentation stated, there is no guild property in Message. I believe what you are looking for is the server property instead.
(Instead of Message.guild, use Message.server)
Note that it might return a None if the message was in a DM, etc.
Based on that, the example bot is probably suited for older versions of Discord.py instead. You might have to make a few edits to the bot to match up with the newest version.
Also, make sure that you downloaded the library/API the example bot used too.
I'm working on a custom Discord bot using their api. Sending HTTP requests work but the bot doesn't actually show itself as online.
Other bots such as Dynobot are able to show themselves as online, am I missing something or is it just a case of how many requests are sent?
Wait, are you working directly with the API, as in sending HTTP requests?
If so...there really is no need to do this. Instead, use a library to code your Discord bot. Here is a list of official libraries for the Discord API. Personally I recommend Discord.js, although I have heard that Discord.py and Discord.NET are also good.
If you want to keep using the API directly, which I do not recommend at all, I believe you can call /api/login. Have you tried that yet?
I hope this helped! :)
I've got an app that's sending email from AppEngine, but each email looks like it's a unique message. Instead I want related emails to be threaded in my email client. Is there a specific header/format I need to use?
These emails are not necessarily in response to another email, so I don't have a Message-ID to plug into References. I've tried using a natural key in References and In-Reply-To to no avail.
I was able to thread a list of emails just by using the In-Reply-To header with your format <msg-identifier#host>.
Supposedly, msg-identifier is the identifier to the message you're replying to, but as you're not replying to any message but sending all of them out of thin air, creating a new ID and using it in all the emails you send will also do the trick.
I got this working by using both References and In-Reply-To with the format <identifier#systemname>. Maybe it'll work with less; I made several changes at once. If someone chimes in with that kind of detail I'll happily accept their answer instead of mine.