I have shapefiles in my jar which is deployed in OpenShift. I'm able to access these files from my local environment by using "File sourceFile = new ClassPathResource("src/main/resources/CountryBoundaries.shp).getFile();". However, in OpenShift, my service complains that it couldn't find it. I have tried InputStream but I get an error in my IDE because the file is not a text file. Below is my code:
File sourceFile = new ClassPathResource("src/main/resources/CountryBoundaries.shp").getFile();
FileDataStore store = FileDataStoreFinder.getDataStore(sourceFile);
featureSource = store.getFeatureSource();
GeometryDescriptor geomDesc = featureSource.getSchema().getGeometryDescriptor();
attrName = geomDesc.getLocalName();
What am I missing? I'll appreciate any help as I've been struggling with this for quite a while now. Thanks.
I found a solution by changing URL to URI and then doing a toURL(). See below:
URI sourceFile = new ClassPathResource("PoliticalSubdivisionBoundaries.shp").getURI();
FileDataStore store = FileDataStoreFinder.getDataStore(sourceFile.toURL());
featureSource = store.getFeatureSource();
GeometryDescriptor geomDesc = featureSource.getSchema().getGeometryDescriptor();
attrName = geomDesc.getLocalName();
Hope this helps someone in the future. Shapefiles are complex and cannot be accessed the usual way like using inputStream and such. Cheers!
Related
I am creating a C# UWP App, which creates files with broadFileSystemAccess capability.
Creating and writing to the file is no problem, but reading it fails with error message "Access to the path is denied even when I use storageFile.Path after writing it (so path is guaranteed to be correct and I can open the file in a text editor without problem).
Can anyone tell me, what I may can do to fix the problem?
Kind regards,
Wolfgang
Now I use following code to create a StorageFile, which can be read by my UWP app:
public static async Task<StorageFile> CreateStorageFileFromPath(string filepath)
{
string path = Path.GetDirectoryName(filepath);
string filename = Path.GetFileName(filepath);
var folder = await StorageFolder.GetFolderFromPathAsync(path);
return await folder.GetFileAsync(filename);
}
Kind regards,
Wolfgang
I am working on an application that stores files under /WEB-INF/someFolder/. But I dont find the right way to create files under this folder. I did this, but it is not working:
File newFile = new File("/WEB-INF/fileName.xml");
When I try to check the creation:
boolean isCreated = newFile.createNewFile();
I get :
java.io.IOException: No such file or directory
Please help me doing it in the right way.
Update:
I did this workaround, it is working but I dont see that it is performant solution.
ServletContext servletContext = getServletContext();
String path = servletContext.getRealPath("/WEB-INF/");
File newFile2 = new File(path+"/fileName.xml");
Any ideas?
You shall use ServletContext.getRealPath(String) and build the entire classpath manually
String webInfPath = getServletConfig().getServletContext().getRealPath("WEB-INF");
OR go step by step:
ServletConfig scfg= getServletConfig();
ServletContext scxt = scfg.getServletContext();
String webInfPath = sxct.getRealPath("WEB-INF");
And than use the webInfPath to create a File object inside WEB-INF
File newFile = new File(webInfPath + "/fileName.xml");
make sure you applaction have the permissions to write.
you can get the path ues like this:
String path=Thread.currentThread().getContextClassLoader().getResource("com/youpackage/");
Now you get the path which is your class folder path，so you can get the WEB-INF path.
ps: i remember when create file you must writer some content,otherwies it may not create.
I basically downloaded a file name custom.mp3 into my isolatedstorage and I can see it via isolatedstorage explorer....
The question here is... How can I access the particular custom.mp3 via URI?
So far I got this.. but I wonder why it is not working:
alarm.Sound = new Uri("isostore:/custom.mp3", UriKind.Absolute);
Your path is wrong. Nothing else is wrong with your code. Post the code you're using for saving the mp3 file in the first place, if you want further help.
For easier reading, the code to store the MP3 goes something like this..
string alarmfile = "custom.mp3";
isolatedStorageFileStream = new IsolatedStorageFileStream(alarmfile,FileMode.Create,isolatedStorageFile);
long songfilelength = (long) e.Result.Length;
byte[] songbyte = new byte[songfilelength];
e.Result.Read(songbyte, 0, songbyte.Length);
isolatedStorageFileStream.Write(songbyte, 0, songbyte.Length);
isolatedStorageFileStream.Flush();
Only files packaged in the XAML can be used as alarm sound:
Remarks
The Sound URI must point to a file packaged in the application’s .xap
file. Isolated storage is not supported. When the alarm is launched,
the sound is played quietly and then gradually increases in volume.
There is no way to modify this behavior.
From:
Alarm.Sound Property
Im writing WPF application and want to add ability to call jump list and open program configuration, app.config or log directory from it. Is it possible(cant find the way to do that..just JumpTasks with application path and JumpPath with path to file, and not just path to be opened via explorer)?
Found answer here. Seems that JumpList wasnt designed for opening anything but files or applications, associated with current program. So that when we see directories in explorer tasklist -it actually means: use explorer with parameters. By the way ill try to use it.
Update
made it with such code:
string explorerPath = #"%windir%\explorer.exe";
JumpTask path = new JumpTask
{
CustomCategory = "Paths",
Title = "Open program directory",
IconResourcePath = explorerPath,
ApplicationPath = explorerPath,
Arguments = #"/root," + AppDomain.CurrentDomain.BaseDirectory,
Description = AppDomain.CurrentDomain.BaseDirectory
};
Im leaving this answer here, because someone can have similar incomprehension.
i'm developing an application and i would load an image that isn't in the clientbin folder, but in a folder placed in my server. I would do something like this
BitmapImage bit = new BitmapImage();
string path = "c:/image.png";
bit.UriSource = new Uri(path, UriKind.Absolute);
identity.Source = bit;
but it doesn't function.Any idea?
Thanks
Try:
Image.Source = New Imaging.BitmapImage(New Uri("http://www.Pic.jpg", UriKind.Absolute))
You do not want to include it in your project or the .xap will get huge.
Silverlight applications run on the client, not on the server, so referencing the path as you had been trying to do, would really point to the path on client machine running the application. However, Silverlight does not have rights to read or write from or to the client's disk anyway, due to sercurity reasons. The Isolated Storage functionality is the exception to that.
Therefore, your option is to try the first answer given by Bill, or a WebService, which is more complex to implement.
ib.
To add to Bill's answer. You can also use server side resources using the following helper method which is derived from the location of the xap file.
public static string GetUrlForResource(string resourcePage)
{
var webUrl = Application.Current.Host.Source.ToString();
//Get ClientBin Directory
var stub = webUrl.Substring(0, webUrl.LastIndexOf("/"));
//Get application root.
stub = stub.Substring(0, stub.LastIndexOf("/") + 1);
//Append the application root to the resource page.
webUrl = stub + resourcePage;
return webUrl;
}
To use it like Bill's answer, use the following:
Image.Source = new Imaging.BitmapImage(new Uri(GetUrlForResource("images/myimage.png"), UriKind.Absolute));