Input Char in Doubly Linkedlist C - c

Question

This is my code:
struct Node{
int data;
char nim[12];
struct Node *next, *prev;
};
struct Node *head, *tail;
void init(){
head = NULL;
tail = NULL;
}
int isEmpty(struct Node *h){
if(h==NULL)
return 1;
else
return 0;
}
void addData(char *nimI){
struct Node *baru;
baru = malloc(sizeof *baru);
baru->nim = malloc(12 * sizeof(char));
strcpy(baru->nim, nimI);
baru->next = NULL;
baru->prev = NULL;
if(isEmpty(head)==1){
head=baru;
tail=baru;
}else{
tail->next=baru;
baru->prev=tail;
tail = baru;
}
printList(head);
}
int main()
{
char nimI[12];
printf("NIM : ");
scanf("%[^\n]#", &nimI);
fflush(stdin);
addData(nimI);
}
I want to input char in my doubly linked list, but it's error.
error :
assigment to expression with array type (error in baru->nim = malloc(12 * sizeof(char));)

Answer 1

You don't need to allocate the memory of an array, so it's worthless to write:
baru->nim = malloc(sizeof(char) * 12);
This statement is only possible when char[12] -> *char. Thanks to #kalyum, but honestly, I figured out this myself just a few moments ago.
Here's the minimal version of the program:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
struct Node {
int data;
char *nim; // Changed num[12] -> *num
};
void addData(char *nimI) {
struct Node *baru = malloc(sizeof *baru);
baru->nim = malloc(sizeof(char) * 12); // Now this will work
strcpy(baru->nim, nimI); // Copying nimI into baru->nim pointer
printf("%s\n", baru->nim); // Displaying the result
}
int main(void) {
char nimI[12] = "Hello there";
// Passing nimI[] (equivalent to *nimI when passed)
addData(nimI);
return 0;
}
This outputs:
Hello there