storing an array as a linked list in C - c

Question

I'm working in C and am having some trouble. I need to store an array of chars (string) across a linked list. In other words, convert a string to a linked list. Basically, one character per node. For example string, dog\0, rather then storing a null character in the last node it would just point to a null pointer to signify the end of the string…… d->o->g->NULL
An suggestions would be great, thank you
int main(){
char *string;
string = malloc(sizeof(char)*100);
strcpy(string,"cheese");
node *list = NULL;
list = createNode(string[0]);
int i;
for(i=1;i<strlen(string);i++){
// this is where I'm stuck, the first char 'c'is in,
// I'm guessing i wanna loop through and
// store each char in a new node ?
}
return 0;
}
node *createNode(char data){
node *ptr = malloc(sizeof(node));
if (ptr == NULL)
{
return NULL;
}
ptr->data = data;
ptr->next = NULL;
return ptr;
}

Answer 1

Here is how to do this in C:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
struct node {
node *next;
char data;
};
node *createNode(char data, node *parent) {
node *ptr=(node*)malloc(sizeof(node));
if(ptr==NULL) {
fprintf(stderr, "Memory allocation error.\n");
exit(1);
}
if(parent!=NULL) parent->next=ptr;
ptr->data=data;
ptr->next=NULL;
return ptr;
}
int main() {
char str[]="cheese";
// Store the string to the list
node *first=NULL, *cur=NULL;
for(int i=0, len=strlen(str); i<len; i++) {
cur=createNode(str[i],cur);
if(first==NULL) first=cur;
}
// Now print it out
cur=first;
while(cur!=NULL) {
printf("%c\n", cur->data);
cur=cur->next;
}
_getwch();
return 0;
}

Answer 2

If C++ is OK then here is a working sample:
#include <iostream>
#include <list>
using namespace std;
int main() {
char str[]="cheese", chr;
// Store the string in the list
std::list<char> clist;
for (int i=0, len=strlen(str); i<len; i++)
clist.push_back(str[i]);
clist.push_back('\0');
// Display the list
do {
chr=clist.front();
cout<<chr<<endl;
clist.pop_front();
} while(chr);
_getwch();
return 0;
}