Queue of Strings in C - c

Question

I am trying to edit this program. Right now the users enters symbols and I want to make it work with Strings.
#include <stdio.h>
#include <stdlib.h>
struct Node
{
char data;
struct Node *next;
};
struct queue
{
struct Node *top;
struct Node *bottom;
}*q;
void Write(char x)
{
struct Node *ptr=malloc(sizeof(struct Node));
ptr->data=x;
ptr->next=NULL;
if (q->top==NULL && q->bottom==NULL)
{
q->top=q->bottom=ptr;
}
else
{
q->top->next=ptr;
q->top=ptr;
}
}
char Read ()
{
if(q->bottom==NULL)
{
printf("Empty QUEUE!");
return 0;
}
struct Node *ptr=malloc(sizeof(struct Node));
ptr=q->bottom;
if(q->top==q->bottom)
{
q->top=NULL;
}
q->bottom=q->bottom->next;
char x=ptr->data;
free(ptr);
return x;
}
int main()
{
q= malloc(sizeof(struct queue));
q->top=q->bottom=NULL;
char ch='a';
printf("NOTE: To stop the entry, please enter 'q'!\n\n Enter a String: \n");
while(ch!='q')
{
scanf("%c",&ch);
Write(ch);
}
printf("\nThe entered String:\n\n");
while(q->bottom!=NULL)
{
ch=Read();
printf("%c",ch);
}
printf("\n\n");
system("PAUSE");
return 0;
}
So I am editing it like this (the code below) and I get error "[Error] incompatible types when assigning to type 'char[10]' from type 'char *'"
#include <stdio.h>
#include <stdlib.h>
struct Node
{
char data[10];
struct Node *next;
};
struct queue
{
struct Node *top;
struct Node *bottom;
}*q;
void Write(char x[10])
{
struct Node *ptr=malloc(sizeof(struct Node));
ptr->data=x;
ptr->next=NULL;
if (q->top==NULL && q->bottom==NULL)
{
q->top=q->bottom=ptr;
}
else
{
q->top->next=ptr;
q->top=ptr;
}
}
char Read ()
{
if(q->bottom==NULL)
{
printf("Empty QUEUE!");
return 0;
}
struct Node *ptr=malloc(sizeof(struct Node));
ptr=q->bottom;
if(q->top==q->bottom)
{
q->top=NULL;
}
q->bottom=q->bottom->next;
char x=ptr->data;
free(ptr);
return x;
}
int main()
{
q= malloc(sizeof(struct queue));
q->top=q->bottom=NULL;
char ch][10]='a';
printf("NOTE: To stop the entry, please enter 'q'!\n\n Enter a String: \n");
while(ch!='q')
{
scanf("%c",&ch);
Write(ch);
}
printf("\nThe entered String:\n\n");
while(q->bottom!=NULL)
{
ch=Read();
printf("%c",ch);
}
printf("\n\n");
system("PAUSE");
return 0;
}
I can't solve this problem, so I would love to get some help...

Answer 1

You can't assign to an array, but you can copy to it.
To copy a string use strcpy:
strcpy(ptr->data, x);
Or since you have a limited array, maybe use strncpy:
strncpy(ptr->data, x, sizeof(ptr->data) - 1);
ptr->data[sizeof(ptr->data) - 1] = '\0';
For strncpy it will not add the terminating '\0' character if the source is equal or longer than the specified length, so we have to make sure that the string is properly terminated.