Display the values of a Json file - c

Question

I have many objects saved in a file as the following form:
{
"name":"name1",
"city":"city1",
"phone":"125698745663"
},
I have a file that content objects as these last, So I would write a function that take as parameter a file, then give us as an output a list of strings, every string is an object of the file, for example name1 city1 125698745663.
Actually I found that a little hard and I have been searching many days for that, I don't want to use libraries already exist cause I have read many documentation but they was difficult to understand for me.
I tried to write some functions.
That's my essay:
#include<stdlib.h>
/*
{
"name":"name1",
"city":"city1",
"phone":"125698745663"
}
/* Boxes of my list */
typedef_struct box
{
char* current_string;
box* next;
}box;
/* Define the structure of the list that I'll return after*/
typedef_struct list
{
box* beginning;
}list;
/*The function that return the list of the objects that existed in our files*/
**char lire (FILE* my_file) //It is possibly to put the path of the file as an argument
{
char* nameFile;
printf("enter the name of the file");
scanf("%s", &nameFile);
my_file = fopen( "nameFile","r");
if (my_file != NULL)
{
box* temp;
int i=0;
list* my_list;
int first_time = 0;
/* browse file elements */
do
{
char c = fgetc(my_file);
/* I put the following condition to get the value without its key*/
if(c == ":")
{
while(c!=",")
{
temp->current_string[i] = c;
i++;
// printf("%c",c);
c=fgetc(my_file);
}
}
/*I put this condition to pass to the following element of the list and fill it*/
if(c == "}")
{
first_time++;
/*This condition is for getting the begining of the list because it is what distinguishes the list*/
if(first_time==1)
my_list->beginning->current_string = temp->current_string;
temp = temp->next;
}
} while (c != EOF);
fclose(my_file);
}
return my_list;
}```

Answer 1

Well, I believe that C, especially without JSON library like cjson is not the appropriate tool to do that.
You might have a look to a list of command-line tools related to JSON:
https://ilya-sher.org/2018/04/10/list-of-json-tools-for-command-line/
I think the best is to download a command-line tool (pre-compiled if possible) and extract the information you need.
An example how to use jq:
Get outputs from jq on a single line
You can download jq from here:
https://stedolan.github.io/jq/download/
EDIT: give an example
After jq download, you can use it from the command line cmd.exe:
jq-win64.exe
jq - commandline JSON processor [version 1.6]
Usage: jq-win64.exe [options] <jq filter> [file...]
jq-win64.exe [options] --args <jq filter> [strings...]
jq-win64.exe [options] --jsonargs <jq filter> [JSON_TEXTS...]
...
test.json
[{
"name":"name1",
"city":"city1",
"phone":"125698745663"
},
{
"name":"name2",
"city":"city2",
"phone":"125698745663"
}
]
jq command line:
> jq-win64.exe ".[]|.name+\",\"+.city+\",\"+.phone" test.json
"name1,city1,125698745663"
"name2,city2,125698745663"
.[] basically means that one wants to iterate over a JSON array.
|.name basically means that one wants to extract name, add a , and .city and so on.