Horizontal Bar In Word Counting - c

Question

So I have been trying to solve a problem about printing a histogram of the lenghts of words in its input and question indicates it is easy to draw it horizontally so thats what I tried but when I write HELLO WORLD I get 1 = ----- which is correct and 2 = ---- which is 4 lines instead of 5 meaning False output.
To understand the problem I added putchar to my code and I realized that compiler doesnt count the 'w' of the world can anyone explain why?
OUTPUT:
HELLO ORLD
1== -----
2==----
#include <stdio.h>
#define IN 1
#define OUT 0
#define MAX 100
int main()
{
int c, word = 1;
int lenght[MAX];
int state = IN;
int leng = 0;
int i, j;
for (i = 0; i < MAX; i++)
{
lenght[i] = 0;
}
while ((c = getchar()) != EOF && word < MAX)
{
if (c == ' ' || c == '\n' || c == '\t')
{
state = OUT;
}
else if (state == IN)
{
leng++;
putchar(c);
}
else if (state == OUT)
{
putchar(' ');
lenght[word] = leng;
word++;
leng = 0;
state = IN;
}
}
lenght[word] = leng;
for (i = 1; i <= word; ++i)
{
printf("%3d: ", i);
for (j = 0; j < lenght[i]; j++)
putchar('-');
putchar('\n');
}
}

Answer 1

Your code is ignoring the first character of every but the first word.
Assuming input HELLO WORLD:
First word is counted properly.
At the space character, the first if-branch is taken, state gets set to OUT. The space character is not processed.
At W, the last if-branch is taken, outputting a space. The current character is not processed and leng gets set to 0 even though we already saw the first character.
consequently W is not output and the length of the rest of the word sums up to 4.

Answer 2

I am sorry for not having the patience to understand the logic of your program and find the bug. However here is an alternative approach that you may prefer:
#include <stdio.h>
#define SIZE 100
#define MAX 100
int main()
{
char word[SIZE];
int lengths[MAX], i, j;
for (i = 0; scanf(" %s", word) == 1; i++)
{
printf("%d = ", i);
for (j = 0; word[j] != '\0'; j++) {
printf("-");
}
lengths[i] = j;
puts("");
}
return 0;
}