Excel Quartile function in SQL Server SQL Query - sql-server

Question

I have an set of values like this:
40
50
50
66
83
100
100
100
100
100
100
100
100
100
100
100
100
When I do the quartile function in excel, i get these four values for my first quartile (25), second quartile(50), third quartile(75) and max (100)
Quartile =
83.33, 100, 100, 100
So when I compare a sales rep who got 80% then they will fall in the bottom quartile according to excel calculation.
I need to redo same functionality in sql and have given my code below.
declare #sales table(
salesRepId int,
percentageSales int)
insert into #sales(salesRepId, percentageSales)
values(1,40)
,(2,50)
,(3,50)
,(4,66.7)
,(5,83.33)
,(6,100)
,(7,100)
,(8,100)
,(9,100)
,(10,100)
,(11,100)
,(12,100)
,(13,100)
,(14,100)
,(15,100)
,(16,100)
,(17,100);
with quintile as(
select percentagesales, ntile(4) over(order by percentagesales)
as quintile
from (select distinct percentagesales from #sales) as s
)
select salesrepid, r.percentagesales, q.quintile
from #sales r
join quintile q on r.percentagesales = q.percentagesales
order by q.quintile, percentagesales
When I run this i get the following result set:
Query results
salesrepid percentagesales quintile
1 40 1
2 50 1
3 50 1
4 66 2
5 83 3
6 100 4
7 100 4
8 100 4
9 100 4
10 100 4
11 100 4
12 100 4
13 100 4
14 100 4
15 100 4
16 100 4
17 100 4
Accoridng to sql, the 80% will fall in the medium quartile.
How can I get the four percentile values similar to excel in SQL query

Answer 1

Change int to decimal in percentageSales:
declare #sales table(
salesRepId int,
percentageSales decimal(8,2))
insert into #sales(salesRepId, percentageSales)
values(1,40)
,(2,50)
,(3,50)
,(4,66.7)
,(5,83.33)
,(6,100)
,(7,100)
,(8,100)
,(9,100)
,(10,100)
,(11,100)
,(12,100)
,(13,100)
,(14,100)
,(15,100)
,(16,100)
,(17,100);
with quintile as(
select percentagesales, ntile(4) over(order by percentagesales)
as quintile
from (select distinct percentagesales from #sales) as s
)
select salesrepid, r.percentagesales, q.quintile
from #sales r
join quintile q on r.percentagesales = q.percentagesales
order by q.quintile, percentagesales

Answer 2

I tried percentile_cont suggested Larnu, I get the four quartile values as
83,100,100,100
but technically it should be 83.33,100,100,100
Here is the query i have so far
declare #sales table(
salesRepId int,
percentageSales int)
insert into #sales(salesRepId, percentageSales)
values(1,40.00)
,(2,50.00)
,(3,50.00)
,(4,66.77)
,(5,83.33)
,(6,100.00)
,(7,100.00)
,(8,100.00)
,(9,100.00)
,(10,100.00)
,(11,100.00)
,(12,100.00)
,(13,100.00)
,(14,100.00)
,(15,100.00)
,(16,100.00)
,(17,100.00);
with quintile as(
select percentagesales, ntile(100) over(order by percentagesales) as quintile
from (select distinct percentagesales from #sales) as s
)
select salesrepid, r.percentagesales, q.quintile
from #sales r
join quintile q on r.percentagesales = q.percentagesales
order by q.quintile, percentagesales;
declare #p Decimal(2,2) = 0.25;
with quartile as(
select
salesRepId,
percentageSales
,cast(percentile_cont(.25) within group(order by percentagesales) over() as decimal(36,2)) as quartile25th
,cast(percentile_cont(.5) within group(order by percentagesales) over() as decimal(36,2)) as quartile50th
,cast(percentile_cont(.75) within group(order by percentagesales) over() as decimal(36,2)) as quartile75th
,cast(percentile_cont(1) within group(order by percentagesales) over() as decimal(36,2)) as quartile100th
from #sales
)
select
s.salesRepId
,s.percentageSales
, case
when s.percentageSales < q.quartile25th then 'red'
when s.percentageSales >=q.quartile25th and s.percentageSales <q.quartile75th then 'yellow'
when s.percentageSales >= q.quartile75th then 'green'
end as color
From #sales s
join quartile q on q.percentageSales = s.percentageSales and q.salesRepId = s.salesRepId
How do I achieve quartile values exactly like I get in excel.
Thank you