Get all course, chapter in one column SQL Server - sql-server

Question

Course
+-----+----------+
| id | c_name |
+-----+----------+
| 1 | course1 |
| 7 | course2 |
+-----+----------+
Chapter
+-----+----------+------------+
| id | Ch_name | c_id |
+-----+----------+------------+
| 3 | Chapter1 | 1 |
| 9 | Chapter2 | 7 |
| 11 | Chapter3 | 1 |
| 17 | Chapter4 | 1 |
+-----+----------+------------+
I'm trying to select all data so that I can generate the following output:
+-----+-- |
|Course |
+-----+-- |
|Course1 |
|Chapter1 |
|Chapter3 |
|Chapter4 |
| |
|Course2 |
|Chapter2 |
I have tried in this way:
select
c.CourseID ,
'Course' as table_name,
c.CourseName as Course,
'' as Chapter
from [MstCourse]c
union
select
s.CourseID,
'Chapter' as table_name,
c.CourseName as Course,
s.ChapterName as Chapter
from [MstCourse] c
inner JOIN [ManageChapter] s ON c.CourseID= s.CourseID
order by Course, Chapter
But I am not getting the results in a single column.

Answer 1

You could achieve this with a group by ... with rollup clause.
Sample data
create table course
(
id int,
name nvarchar(10)
);
insert into course(id, name) values
(1, 'Course1'),
(7, 'Course2');
create table chapter
(
id int,
name nvarchar(10),
c_id int
);
insert into chapter(id, name, c_id) values
(3 , 'Chapter1', 1),
(9 , 'Chapter2', 7),
(11, 'Chapter3', 1),
(17, 'Chapter4', 1);
Solution
select coalesce(ch.Name, co.Name) as [Course]
from course co
join chapter ch
on ch.c_id = co.id
group by co.Name, ch.Name with rollup
having grouping(co.Name) <> 1
order by co.Name, ch.Name;
For some background on how this solution works, have a look at this fiddle.