T-SQL Limited Cross Join - sql-server

Question

I want to join 2 tables such that I get the NAR for every combination of Type and BillingID where it exists.
Where a BillingID doesn't have a certain Type, then either NULL or 0 is returned for the NAR along with the Type and BillingID.
Is something like this even possible using SQL?
A simplified version of my data is shown below:
Type list:
+----------+
| Type |
+----------+
| NEW |
| CHNG |
| LAP |
+----------+
Data:
+----------+-----------+-----+
| Type | BillingID | NAR |
+----------+-----------+-----+
| NEW | ABC | 5 |
| CHNG | ABC | 15 |
| LAP | ABC | 10 |
| CHNG | DEF | 20 |
+----------+-----------+-----+
Desired result:
+----------+-----------+-----+
| Type | BillingID | NAR |
+----------+-----------+-----+
| NEW | ABC | 5 |
| CHNG | ABC | 15 |
| LAP | ABC | 10 |
| CHNG | DEF | 20 |
| NEW | DEF | 0 |
| LAP | DEF | 0 |
+----------+-----------+-----+
The last 2 rows are what is causing me problems.

Answer 1

I think you can do it like this:
declare #table table (type1 varchar(5))
insert into #table
values
('new'),
('chng'),
('lap')
declare #table2 table (typeid varchar(5),billingid varchar(5),nar int)
insert into #table2
values
( 'NEW', 'ABC', 5 ),
( 'CHNG' , 'ABC', 15 ),
( 'LAP' , 'ABC', 10 ),
( 'CHNG' , 'DEF', 20 )
select Z.*,case when c.nar IS null then 0 else c.nar end as nar from (
select * from #table a
outer apply (select distinct billingid from #table2 b ) p
)Z
left join #table2 c on Z.type1 = c.typeid and Z.billingid = c.billingid
order by billingid
Result