I have an array of type "User" and I'd like to delete all users that are 10 years old. My code :
struct User: Identifiable {
var id = UUID()
var name: String
var age: String
}
var array: User = [
User[name: "AZE", age: "10"]
User[name: "QSD", age: "37"]
]
What is the function for deleting an object from an element of that object? I hope you understood my problem and thank you for your answer.
You can use filter to keep only the elements of the array whose age property doesn't equal 10.
let filtered = array.filter { $0.age != "10" }
Unrelated to your question, but why is age a String? It should be an Int instead, since it represents a numeric value. Also, you should always make properties immutable (let) by default and only make them mutable (var) if they really need to be mutable.
Related
I'm trying to create an array of structs (User structs below) where, if the user.name does not yet exist in the array, it appends the user -- but if the user.name is already present ("Mcdonalds" in the below example), then it will simply add the item.amount to the existing struct.
In other words, the below code should create an array of 4 Users, with the User Mcdonalds item.amount totaling 23.44 + 12.33.
I remember doing this sort of thing in JS no sweat, but I can't for the life of me figure out how to do this in Swift. Thanks for any help!
struct User {
var name: String
var amount: Double
}
var user1 = User(name: "Mcdonalds", amount: 23.44)
var user2 = User(name: "Wendys", amount: 15.44)
var user3 = User(name: "Cabanos", amount: 12.22)
var user4 = User(name: "Shell Gas", amount: 23.33)
var user5 = User(name: "Mcdonalds", amount: 12.33)
To loop over the users they'll need to be in an array to start.
Then you can use .reduce(into:) to reduce them into one condensed dictionary (the dictionary will allow you to have a unique key (the name of the user here) so that you don't have duplicate entries). Then you can use .map() to just get the value and not the key of that dictionary so that the final result will be an array of users.
struct User {
var name: String
var amount: Double
}
var users = [
User(name: "Mcdonalds", amount: 23.44),
User(name: "Wendys", amount: 15.44),
User(name: "Cabanos", amount: 12.22),
User(name: "Shell Gas", amount: 23.33),
User(name: "Mcdonalds", amount: 12.33)
]
var reducedUsers = users.reduce(into: [String: User]()) { (result, nextUser) in
if let existing = result[nextUser.name] {
result[nextUser.name] = User(name: nextUser.name, amount: existing.amount + nextUser.amount)
} else {
result[nextUser.name] = nextUser
}
}.map { $0.value }
A clean and swifty way is to write an extension for Array. Swift is highly protocol-oriented, which means you are able to extend any existing system or self-written class with new functions.
This is just a simple implementation, which uses a function to append or update any given user object:
extension Array where Element == User {
/// Appends a not existing user to the array or updates the amount value if user is already present
mutating func appendOrUpdate(_ userObject: Element) {
// Check if user is already in the array
if let index = self.firstIndex(where: { $0.name == userObject.name }) {
// Update the amount
self[index].amount += userObject.amount
}
else {
// Append the user
self.append(userObject)
}
}
}
As the where clause specifies the extension the Element of the array only to be applied when the given object is your User struct, it is only available when you pass in an user object.
Usage:
var userArray: [User] = []
userArray.appenOrUpdate(User(name: "Mcdonalds", amount: 23.44))
userArray.appenOrUpdate(User(name: "Wendys", amount: 15.44))
userArray.appenOrUpdate(User(name: "Cabanos", amount: 12.22))
userArray.appenOrUpdate(User(name: "Shell Gas", amount: 23.33))
userArray.appenOrUpdate(User(name: "Mcdonalds", amount: 12.33))
This will result in an array with just four entries and the double entry 'Mcdonalds' user's amount cumulated.
Note that the function has the mutating keyword in front, as if not you will not be able to modify the array and its entries. This is necessary due the nature of arrays being Structs themselves.
You can also write a function like the know Array's append(contentsOf:) and pass in an array of user objects and loop through them updating or appending the given objects.
Best way is to put this extension in a separate file called Array+User.swift according to best practise naming conventions.
You can read more about extensions in Swift and their power here: https://docs.swift.org/swift-book/LanguageGuide/Extensions.html
Matthew Gray's answer is very good, and can be used for a wide variety of problems that may be more complex than this one. But for this specific problem, it can be done much more simply.
let reducedUsers = users.reduce(into: [:]) { (result, user) in
result[user.name, default: 0] += user.amount
}
.map(User.init)
The point of this is that it tears apart the struct into key and value in a Dictionary, and then reassembles the values into an Array at the end. Swift is smart enough to figure out the type of the [:], so there's no need to specify that.
Note that there is a time-space tradeoff here. This creates a temporary Dictionary that can be very large. If this kind of operation is common and the dataset is large, you should consider storing this data in a Dictionary ([String: User] or [String: Double]) all the time rather than converting back and forth.
This is a fundamental thing that I should know but don't know at a deep level and therefore find confusing. Dictionaries seem to be unordered list of keys and values. I want to create an ordered list of keys and values so that I can sort and otherwise keep track of order. I think this means I have to convert the dictionary into a multi-dimensional Array that has the key and value and also an index value ie 0,1,2,3 etc.
If my dictionary looks like the following:
var myScores = [String: Float]()
myScores = ["player1":22,"player2":33]
How do I convert it into an Array where player1:22 is the first element and player2:33 is the second element?
Edit:
Alternative without creating struct is to create an empty array of dictionaries in the form of your dictionary and then append your dictionary to the array.
var myArray = [[String: Float]]()//note double brackets
propArray.append(myScores)
What you want is an array of structs.
struct Score {
let playerName: String
let score: Int
}
let scores = [Score(playerName: "player1", score: 22),
Score(playerName: "player2", score: 33),
]
let sortedScores = scores.sorted(by: { $0.playerName < $1.playerName })
To get key-value pairs out of a dictionary is straightforward, though it forces you to work with tuples, which are not a particularly friendly type. Even so, it's done this way:
let sortedScores = myScores.sorted { $0.key < $1.key }
That will create:
[(key: "player1", value: 22.0), (key: "player2", value: 33.0)]
Or
for (name, score) in myScores.sorted(by: { $0.key < $1.key }) {
print(name, score)
}
You can keep the dictionary as-is. One possible solution is to create an array that contains just the keys in the desired order. Then you can iterate the key array and access the elements of the dictionary.
var myScores: [String:Float] = ["player1":22, "player2":33]
var myPlayers = myScores.keys.sorted()
for player in myPlayers {
let score = myScores[player]
}
This works when you want to show the data in some particular order, such as in a table view.
I am currently struggling with obtaining a value from an array inside an array of dictionaries. Basically I want to grab the first "[0]" from an array stored inside an array of dictionaries. This is basically what I have:
var array = [[String:Any]]()
var hobbies:[String] = []
var dict = [String:Any]()
viewDidLoad Code:
dict["Name"] = "Andreas"
hobbies.append("Football", "Programming")
dict["Hobbies"] = hobbies
array.append(dict)
/// - However, I can only display the name, with the following code:
var name = array[0]["Name"] as! String
But I want to be able to display the first value in the array stored with the name, as well. How is this possible?
And yes; I know there's other options for this approach, but these values are coming from Firebase (child paths) - but I just need to find a way to display the array inside the array of dictionaries.
Thanks in advance.
If you know "Hobbies" is a valid key and its dictionary value is an array of String, then you can directly access the first item in that array with:
let hobby = (array[0]["Hobbies"] as! [String])[0]
but this will crash if "Hobbies" isn't a valid key or if the value isn't [String].
A safer way to access the array would be:
if let hobbies = array[0]["Hobbies"] as? [String] {
print(hobbies[0])
}
If you use a model class/struct things get easier
Given this model struct
struct Person {
let name: String
var hobbies: [String]
}
And this dictionary
var persons = [String:Person]()
This is how you put a person into the dictionary
let andreas = Person(name: "Andreas", hobbies: ["Football", "Programming"])
persons[andreas.name] = Andreas
And this is how you do retrieve it
let aPerson = persons["Andreas"]
is it possible to have a dictionary, that contains multiple values for one key?
For example I have multiple IDs (101,102,103,104...) and all of those IDs have some values (colour: green, number: 4, city: New York). I am new to programming and not sure how should I store it.
I was thinking about custom class:
class myClass: NSObject {
var ID: Int
var colour: String
var number: Int
var city: String
init(ID: Int, colour: String, number: Int, city: String) {
self.ID = ID
self.colour = colour
self.number = number
self.city = city
}
}
And the create some variable var myData = myClass() and just everything there, but then how could I access lets say ID 102 and modify its colour?
So my question how to store data provided in my example with an option to be able select specific ID and modify values belonging to that ID.
A dictionary must contain exactly one value for each key. However, that value could be an array, or a dictionary, or an object etc. etc. so that is no practical restriction.
Since instance of classes are stored as references, the dictionary values could be references to class instances. So you can extract the reference to an instance from the dictionary, and then modify the instance. Be aware that anyone holding a reference to the same instance will see the same changes.
Assuming you have two instances of your class
let item101 = MyClass(ID: 101, colour: "red", number: 4, city: "NewYork")
let item102 = MyClass(ID: 102, colour: "green", number: 7, city: "Chicago")
You can store them in a dictionary using the ID as key
let dictionary = [101: item101, 102: item102]
and retrieve a value by ID with
if let id101 = dictionary[101] {
// use id101
} else {
print("ID 101 not found")
}
or you can use an array
let array = [item101, item102]
and get an item by ID with the filter function
let filtered = array.filter{ $0.ID == 102 }
if !filtered.isEmpty {
let id102 = filtered[0]
} else {
print("ID 102 not found")
}
Declare you id with Array and foreach in that ID
var ID: [Int]
I am not expert in Swift and I have been using it for few months to build Mac Apps. I would like to represent in memory a data structure like that of PHP associative arrays but in Swift. Let's imagine that I have a table of data to load in memory with the following fields/records:
ID Surname Name
1 XXX YYY
2 ZZZ WWW
3 JJJ KKK
What I would like to obtain is an associative array like the one I would be able to obtain in PHP:
$arr[1]["Surname"] = "XXX"
$arr[1]["Name"] = "YYY"
$arr[2]["Surname"] = "ZZZ"
$arr[2]["Name"] = "WWW"
I just cannot find the right data structure in Swift to obtain the same result. I tried with the following piece of code:
class resObject: NSObject {
private var cvs = [Int: [String: String]]()
override init() {
self.cvs[0] = ["Name" : "XXX"]
self.cvs[0] = ["Surname" : "YYY"]
self.cvs[1] = ["Name" : "ZZZ"]
self.cvs[1] = ["Surname" : "WWW"]
for (key, arr) in cvs {
let sur = arr["Surname"]
let nam = arr["Name"]
println("Row \(key) - Surname: \(sur), Name: \(nam)")
}
super.init()
}
}
It looks to me pretty close, but it does not work. What I get in the output is the following (I don't care about the "Optional(s)":
Row 0 - Surname: Optional("XXX"), Name: nil
Row 1 - Surname: Optional("ZZZ"), Name: nil
I tried to make some tests in debug and I noticed that the data that are saved in memory are just that of the last key:value pair used (i.e. if I assign Surname first and Name second I get Surname as nil and Name with the correct value).
Please consider that, as in the example, I don't know the data structure when I declare the variable, so I declare it empty and fill it programmatically later.
I don't know if it is just me not declaring the data structure correctly, or if it is Swift that does not allow to do that. Any help will be greatly appreciated.
Thanks a lot.
Regards,
Alessio
One way is a Dictionary of structs. Consider:
struct Person {
var firstName: String
var lastName: String
}
var peopleByID = [ Int: Person ]()
peopleByID[1] = Person(firstName: "First", lastName: "Last")
peopleByID[27] = Person(firstName: "Another", lastName: "LastName")
var myID = 1 // Try changing this to 2 later
if let p = peopleByID[myID] {
println("Found: \(p.firstName) with ID: \(myID)")
}
else {
println("No one found with ID: \(myID)")
}
You can then update the structure:
peopleByID[1].firstName = "XXX"
peopleByID[27].lastName = "ZZZ"
You can iterate freely:
for p in peopleByID.keys {
println("Key: \(p) value: \(peopleByID[p]!.firstName)")
}
Note that a mere array of [Person] isn't so hot, because the IDs:
-- may not be Ints, but are often Strings
-- even if they remain Ints, an array takes up storage in proportion to the highest numbered index, whereas a Dictionary only takes up storage in proportion to the number of stored objects. Imagine storing just two ID's: 523123, and 2467411.
EDIT
It seems like you don't know the attributes ahead of time that will go into each Person object. That's odd, but you should then do:
struct Person {
var attributes = [String : String]() // A dictionary of String keys and String values
}
var peopleByID = [ Int : Person ]()
// and then:
var p1 = Person()
var p2 = Person()
p1.attributes["Surname"] = "Somename"
p1.attributes["Name"] = "Firstname"
p2.attributes["Address"] = "123 Main St."
peopleByID[1] = p1
peopleByID[2] = p2
if let person1 = peopleByID[1] {
println(person1.attributes["Surname"]!)
for attrKey in person1.attributes.keys {
println("Key: \(attrKey) value: \(person1.attributes[attrKey]!)")
}
}