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#include <stdio.h>
int main()
{
int x=3;
float y=3.0;
if(x==y)
printf("\n x and y are equal");
else
printf("\n x and y are not equal")
return 0;
}
The code prints "x and y are equal".
Please explain how did this happen.
When comparing an int variable to a float variable using ==, the int is converted to a float implicitly first, and then the comparison is made.
Hence, float(x) == y means 3.0f == 3.0f, which is true, that's why you it executes:
printf("\n x and y are equal");
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How we could get three numbers without ordering and then check if they form a Pythagorean triple or not?
So, pythagorean(3, 4, 5) or pythagorean(5, 3, 4) will print/return true, while pythagorean(4, 3, 6) will print/return false.
You can use this algotrithm :
#include<stdio.h>
int main(){
long long int a, b, c ;
scanf("%llu %llu %llu", &a, &b, &c);
if (a*a==b*b+c*c || b*b==a*a+c*c || c*c==a*a+b*b)
{
printf("YES");
}
else
printf("NO");
return 0;
}
If you use the equation, a^2 + b^2 = c^2, c should be the largest number and the order of a and b should not matter. Just find the largest number, set that equal to c, and then set the other two values to a and b and check to see if the equality is true.
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I executed a code in the C language, However I am unable to understand its output.
#include <stdio.h>
int main()
{
int a=5;
int b= ++a + 0!=0;
printf("%d %d",++a, b);
return 0;
}
The output for the above program is
7 1
I am unable to understand why it is so.
Order of operations causes this to be treated as:
int b = (((++a) + 0) != 0);
Therefore:
int b = (6 != 0);
6 isn't 0, so that has a value of true aka 1.
int b = 1;
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How do I first convert numbers that I'm adding to scientific notation in C program . Then add them together, and once I have my final answer, then convert it back to scientific notation and return it?
What's wrong with:
#include <stdio.h>
int main(void)
{
double a, b, c;
printf("Enter two numbers: ");
if (scanf("%lf %lf", &a, &b) != 2)
{
fprintf(stderr, "Expected two floating point numbers\n");
return 1;
}
c = a + b;
printf("%13.6e + %13.6e = %13.6e\n", a, b, c);
return 0;
}
Example run:
Enter two numbers: 13.456e34 +11.44225534e33
1.345600e+35 + 1.144226e+34 = 1.460023e+35
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#include<stdio.h>
double sum_1(int n)
{
int i=1;
double s;
while(n>0)
{
s=s+i/(2*i+2);
i=i+2;
n--;
}
return s;
}
int main()
{
int n=5;
double s1;
printf("Enter n:\n");
scanf("%d",&n);
s1= sum_1(n);
printf("sum = %lf",s1);
return 0;
}
The problem is
s=s+i/(2*i+2);
in the first iteration, s is used uninitialized. Since this is a type which can have trap representation, and it's address is never taken, trying to use the uninitialized value here invokes undefined behavior.
That said, the grouping of the statement
s=s+i/(2*i+2);
is same as
s = s + ( i / (2*i+2) );
^^^^^^^^^^^^^---- integer division
so, it involves integer division, which is most likely what you don't want. You need to enforce floating point arithmetic, like
s=s+i/(float)(2*i+2);
Finally, for printing a double, %f is sufficient, %lf is not needed and has no effect.
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I'm looking for a way to create a "variable-function" in C language.
In MATLAB i'm able to create something like:
my_function = (#x) sin(x) + x^2 + x;
so that i'm able to evaluate it for any value of 'x' i like:
my_point = 3.09;
my_function(my_point);
is there anything like that for C language?
That's just a regular C function. The terminology would be: "A function with arguments"
double my_function(double x)
{
return sin(x) + x*x + x;
}
#include <stdio.h>
#include<math.h>
#define my_function(x) sin(x) + pow(x,2) + x
int main()
{
double my_point = 3.09;
printf("%lf",my_function(my_point));
return(0);
}