convert JSON array to bash array preserving whitespaces - arrays

I want to transform JSON file into bash array of strings that i will later be able to iterate over. My JSON structure is as follows:
[
{
"USERID": "TMCCP",
"CREATED_DATE": "31/01/2020 17:52"
},
{
"USERID": "TMCCP",
"CREATED_DATE": "31/01/2020 17:52"
}
]
And this is my bash script:
test_cases=($(jq -c '.[]' data.json))
echo ${test_cases[0]}
echo ${test_cases[1]}
echo ${test_cases[2]}
echo ${test_cases[3]}
As you can see it returns array with 4 elements instead of 2. Output:
{"USERID":"TMCCP","CREATED_DATE":"31/01/2020
17:52"}
{"USERID":"TMCCP","CREATED_DATE":"31/01/2020
17:52"}
For some reason having whitespace in date field causes some parsing issues. Any idea how to get over this?

Use readarray instead.
$ readarray -t test_cases < <(jq -c '.[]' file)
$ declare -p test_cases
declare -a test_cases=([0]="{\"USERID\":\"TMCCP\",\"CREATED_DATE\":\"31/01/2020 17:52\"}" [1]="{\"USERID\":\"TMCCP\",\"CREATED_DATE\":\"31/01/2020 17:52\"}")
And read can be used as shown below where readarray is unavailable.
IFS=$'\n' read -d '' -a test_cases < <(jq -c '.[]' file)

Use readarray to populate the array, rather than using an unquoted command substitution; bash doesn't care about JSON quoting when it splits the result into separate words.
readarray -t test_cases < <(jq -c '.[]' data.json)
In bash 3.2 (which is what you appear to be stuck with), you need something slightly more unwieldy
while IFS= read -r line; do
test_cases+=("$line")
done < <(jq -c '.[]' data.json)

Related

How to parse and convert string list to JSON string array in shell command?

How to parse and convert string list to JSON string array in shell command?
'["test1","test2","test3"]'
to
test1
test2
test3
I tried like below:
string=$1
array=${string#"["}
array=${array%"]"}
IFS=',' read -a array <<< $array;
echo "${array[#]}"
Any other optimized way?
As bash and jq are tagged, this solution relies on both (without summoning eval). The input string is expected to be in $string, the output array is generated into ${array[#]}. It is robust wrt spaces, newlines, quotes, etc. as it uses NUL as delimiter.
mapfile -d '' array < <(jq -j '.[] + "\u0000"' <<< "$string")
Testing
string='["has spaces\tand tabs","has a\nnewline","has \"quotes\""]'
mapfile -d '' array < <(jq -j '.[] + "\u0000"' <<< "$string")
printf '==>%s<==\n' "${array[#]}"
==>has spaces and tabs<==
==>has a
newline<==
==>has "quotes"<==
eval "array=($( jq -r 'map( #sh ) | join(" ")' <<<"$json" ))"

return nvme list as array using jq and loop thru it

This is how I am grabbing all the NVME volumes:
all_nvme_volumes=$(sudo nvme list -o json | jq .Devices[].DevicePath)
This how the output looks like:
"/dev/nvme0n1" "/dev/nvme1n1" "/dev/nvme2n1" "/dev/nvme3n1" "/dev/nvme4n1" "/dev/nvme6n1"
How do I loop thru them process them individually?
I tried for r in "${all_nvme_volumes[#]}"; do echo "Device Name: $r"; done but the output is Device Name: "/dev/nvme0n1" "/dev/nvme1n1" "/dev/nvme2n1" "/dev/nvme3n1" "/dev/nvme4n1" "/dev/nvme6n1"
which is one string instead of each element of array:
Populating a bash array with mapfile from null delimited raw output from jq:
#!/usr/bin/env bash
mapfile -d '' all_nvme_volumes < <(
sudo nvme list --output-format=json |
jq --join-output '.Devices[].DevicePath + "\u0000"'
)
A solution for bash < 4.4:
#!/bin/bash
IFS=$'\t' read -r -a all_nvme_volumes < <(
sudo nvme list -o json | jq -r '[ .Devices[].DevicePath ] | #tsv'
)
note: device paths shouldn't be escaped by #tsv, so you won't need to unescape the values, but in case you use this trick for other purposes, you can unescape a value with printf -v value '%b' "$value"
How do I loop thru them process them individually?
Well, once you have the array, you can loop though its elements with:
for nvme_volume in "${all_nvme_volumes[#]}"
do
# process "$nvme_volume"
done
But, if you only need to loop though the nvme volumes without storing them then you can use #LĂ©aGris null delimiter method with a while loop:
#!/bin/bash
while IFS='' read -r -d '' nvme_volume
do
# process "$nvme_volume"
done < <(sudo nvme list -o json | jq -j '.Devices[].DevicePath + "\u0000"')

Bash. Split text to array by delimiter [duplicate]

This question already has answers here:
How to split a string into an array in Bash?
(24 answers)
Closed 1 year ago.
Can somebody help me out. I want to split TEXT(variable with \n) into array in bash.
Ok, I have some text-variable:
variable='13423exa*lkco3nr*sw
kjenve*kejnv'
I want to split it in array.
If variable did not have new line in it, I will do it by:
IFS='*' read -a array <<< "$variable"
I assumed the third element should be:
echo "${array[2]}"
>sw
>kjenve
But with new line it is not working. Please give me right direction.
Use readarray.
$ variable='13423exa*lkco3nr*sw
kjenve*kejnv'
$ readarray -d '*' -t arr < <(printf "%s" "$variable")
$ declare -p arr
declare -a arr=([0]="13423exa" [1]="lkco3nr" [2]=$'sw\nkjenve' [3]="kejnv")
mapfile: -d: invavlid option
Update bash, then use readarray.
If not, replace separator with zero byte and read it element by element with read -d ''.
arr=()
while IFS= read -d '' -r e || [[ -n "$e" ]]; do
arr+=("$e")
done < <(printf "%s" "$variable" | tr '*' '\0');
declare -p arr
declare -a arr=([0]="13423exa" [1]="lkco3nr" [2]=$'sw\nkjenve' [3]="kejnv")
You can use the readarray command and use it like in the following example:
readarray -d ':' -t my_array <<< "a:b:c:d:"
for (( i = 0; i < ${#my_array[*]}; i++ )); do
echo "${my_array[i]}"
done
Where the -d parameter defines the delimiter and -t ask to remove last delimiter.
Use a ending character different than new line
end=.
read -a array -d "$end" <<< "$v$end"
Of course this solution suppose there is at least one charecter not used in your input variable.

Parse variables from string and add them to an array with Bash

In Bash, how can I get the strings between acolades (without the '_value' suffix) from for example
"\\*\\* ${host_name_value}.${host_domain_value} - ${host_ip_value}\\*\\*"
and put them into an array?
The result for the above example should be something like:
var_array=("host_name" "host_domain")
The string could also contain other stuff such as:
"${package_updates_count_value} ${package_updates_type_value} updates"
The result for the above example should be something like:
var_array=("package_updates_count" "package_updates_type")
All variables end with _value. There could 1 or more variables in the string.
Not sure what would be the most efficient way and how I'd best handle this. Regex? Sed?
input='\\*\\* ${host_name_value}.${host_domain_value} \\*\\*'
# would also work with cat input or the like.
myarray=($(echo "$input" | awk -F'$' \
'{for(i=1;i<=NF;i++) {match($i, /{([^}]*)_value}/, a); print a[1]}}'))
Split your line(s) on $. Check if a column contains { }. If it does, print what's after { and before _value}. (If not, it will print out the empty string, which bash array creation will ignore.)
If there are only two variables, this will work.
input='\\*\\* ${host_name_value}.${host_domain_value} \\*\\*'
first=$(echo $input | sed -r -e 's/[}].+//' -e 's/.+[{]//')
last=$(echo $input | sed -r -e 's/.+[{]//' -e 's/[}].+//')
output="var_array=(\"$first\" \"$last\")"
Maybe not very efficient and beautiful, but it works well.
Starting with a string variable:
$ str='\\*\\* ${host_name_value}.${host_domain_value} - ${host_ip_value}\\*\\*'
Use grep -o to print all matching words.
$ grep -o '\${\w*_value}' <<< "$str"
${host_name_value}
${host_domain_value}
${host_ip_value}
Then remove ${ and _value}.
$ grep -o '\${\w*_value}' <<< "$str" | sed 's/^\${//; s/_value}$//'
host_name
host_domain
host_ip
Finally, use readarray to safely read the results into an array.
$ readarray -t var_array < <(grep -o '\${\w*_value}' <<< "$str" | sed 's/^\${//; s/_value}$//')
$ declare -p var_array
declare -a var_array=([0]="host_name" [1]="host_domain" [2]="host_ip")

Getting the output of a cat command into an array

How can I get just the filenames into an array using the cat command?
How I've been trying:
array=()
while IFS= read -r -d $'\0'; do
array+=("$REPLY")
done < <(cat /proc/swaps | grep "swap")
This either grabs all the information from the output into an array, or just doesn't work. How can I successfully get my expected output of [/swapfile, /dev/hda1, /some/other/swap] into an array form using the cat command?
readarray array < <(awk '/swap/{print $1}' /proc/swaps)
Bash introduced readarray in version 4 which can take the place of the while read loop. readarray is the solution you want.
here is the syntax
readarray variable < inputfile
echo "${variable[0]}" ' to print the first element in array

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