How to read a file that was fseeked? - c

I have no idea why this does not work:
#include <stdio.h>
int main(){
FILE* fp = fopen("txt2","wr");
if(!fp) return 1;
fprintf(fp,"20");
fseek(fp,0,SEEK_SET);
fprintf(fp,"19");
rewind(fp);
char c;
while((c=fgetc(fp))!=EOF)
printf("%c",c);
}
Here should be write 20, then rewrite to 19, set the position to start of file, and the read the char till EOF (so should print 19). But prints nothing. Why is that?
I have tried to make better check for return poitner to fp (because of wr):
EDIT:
#include <stdio.h>
int main(){
FILE *fp = fopen("txt","wr");
if(!fp){
printf("nada\n");
return 1;
}
}
But it compiles without problem. Why is that? The wr should be UB (and thus cause segfault or another err) or?

The mode "wr" is not valid string for POSIX fopen() or Microsoft fopen(). You probably want to use "w+". Using "r+" would be an alternative, but then the file must exist before you open it.
The implementation of fopen() that you're using probably treats "wr" as equivalent to "w" (unless it reports an error and your program exits — it is a good idea to report why you are exiting). You can't read from a write-only file stream.
Strictly, you should also use int and not char for the variable c because fgetc() returns an int.

Related

can't access a place in memory

I'm trying to read a binary file of 32 bytes in C, however I'm keep getting "segmentation fault (code dumped)" when I run my program,
it would be great if somebody can help me out by pointing where did I go wrong?.
my code is here below:
int main()
{
char *binary = "/path/to/myfiles/program1.ijvm";
FILE *fp;
char buffer[32];
// Open read-only
fp = fopen(binary, "rb");
// Read 128 bytes into buffer
fread (buffer, sizeof(char), 32, fp);
return 0;
}
It's because of the path. Make sure that "/path/to/myfiles/program1.ijvm" points to an existing file.
You should always check the return value of fopen.
\\Open read-only
fp = fopen(binary, "rb");
if(fp==NULL){
perror("problem opening the file");
exit(EXIT_FAILURE);
}
Notice also that you are reading 32 bytes in your buffer and not 128 as your comment says.
You must check the return result from fopen().
I'm assuming you are getting the segfault in the fread() call because your data file doesn't exist, or couldn't be opened, and you are trying to work on a NULL FILE structure.
See the following safe code:
#include <stdio.h>
#include <stdint.h>
#define SIZE_BUFFER 32
int main()
{
char *binary = "data.txt";
FILE *fp = NULL;
char buffer[SIZE_BUFFER];
// Open read-only
fp = fopen(binary, "rb");
// Read SIZE_BUFFER bytes into buffer
if( fp )
{
printf("Elements read %ld\n", fread (buffer, sizeof(char), SIZE_BUFFER, fp));
fclose(fp);
}
else
{
// Use perror() here to show a text description of what failed and why
perror("Unable to open file: ");
}
return 0;
}
When I execute this code it doesn't crash and will print the number of elements read if the file is opened or it will print "Unable to open file" if the file could not be opened.
As mentioned in the comments you should also close the file being exiting. Another thing you can do is the following:
FILE *fp = fopen(.....);
Instead of declaring and assigning in two separate steps.
There are two possible reasons
The fopen(3) function failed due to some reason, which means fp is NULL, and then you are trying to use the null-pointer in fread(3). This can crash. #OznOg has already given a subtle hint to look into this direction.
If the fopen call is a success (i.e. fp is non-NULL after calling fopen), the code can still crash because you are reading 32 chars into the variable binary, while binary has been initialized with only 30 chars.

read operation without fseek in a+ mode causes extra white spaces in the file

When I executed below code, m2.txt created correctly as expected with the specified data.
#include <stdio.h>
int main()
{
FILE *fp1;
char ch;
fp1=fopen("m2.txt", "a+");
fputs("Hello, data is appended\0", fp1);
fseek(fp1,0,SEEK_SET);
while((ch=getc(fp1))!=EOF)
{
putc(ch,stdout);
}
fclose(fp1);
return 0;
}
Now I commented fseek and executed the below code. (I deleted this m2.txt file before executing)
#include <stdio.h>
int main()
{
FILE *fp1;
char ch;
fp1=fopen("m2.txt", "a+");
fputs("Hello, data is appended\0", fp1);
//fseek(fp1,0,SEEK_SET);
while((ch=getc(fp1))!=EOF)
{
putc(ch,stdout);
}
fclose(fp1);
return 0;
}
To my surprise, displayed data on the screen had just whitespaces. Even "Hello, data is appended"was missing. Also the m2.txt file had many white spaces.
Why this problem? If fseek is not done before read, it should affect only read operation I thought. Why extra spaces are getting written to the file?
In a+ mode, read pointer is pointing to the beginning if no write operation is done. But in case write operation is done, pointer will be at the end I suppose. In such case, read should not be displaying anything without fseek right? In anycase, issues could be there with read. But why write is having issues even though write is done before read.
I am using Codeblock 15.12 and default mingw came with codeblock.
Edited:
I further thought if it could be some compiler related issue. Grabbed old Visual Studio 6 and compiled. Several lines of unreadable characters are printed at the end. So it is not compiler issue. Somewhere some silly issue is there it looks.
After some search, I found that fflush() or fclose() or fseek() is needed before reading the file. Otherwise the entire write buffer may be filled/affected. Tried with fflush() and write operation did not write any junk at the end even if fseek() is not called. Here is the code (Of course fseek() will be there inplace of fflush() in actual code. I just commented fseek and added fflush() for testing purpose).
int main()
{
FILE *fp1;
char ch;
fp1=fopen("m2.txt", "a+");
fputs("Hello, data is appended", fp1);
fflush(fp1);
// fseek(fp1,0,SEEK_SET);
while((ch=getc(fp1))!=EOF)
{
putchar(ch);
}
fclose(fp1);
return (0);
}

Why is rewind() not working as expected in this simple program?

Why is the below program not printing the first character of the newly created text file ("E") as expected? It's a simple program and I tried to look at the issue from all aspects but couldn't find the reason. The text file is being created on my D drive with the content "EFGHI", but for some reason "E" is not being read even if I rewind and read using getc() and the output is -1.
#include<stdio.h>
#include<stdlib.h>
int main()
{
int x;
FILE *fp;
fp=fopen("F:\\demo.txt","w");
if(fp==NULL)
puts("Write error");
fputs("EFGHI",fp);
rewind(fp);
x=getc(fp);
printf("%d",x);
fclose(fp);
}
UPDATED:
#include<stdio.h>
#include<stdlib.h>
int main()
{
int x;
FILE *fp;
fp=fopen("F:\\demo.txt","w+");
if(fp==NULL)
{
puts("Write error");
exit(EXIT_SUCCESS);
}
fputs("EFGHI",fp);
rewind(fp);
while(!feof(fp))
{
x=getc(fp);
printf("%d\n",x);
}
fclose(fp);
}
File mode "w" opens the file for writing only.
Use "w+" to open a file for writing and reading.
(Please see man fopen for more file modes.)
Regarding getc() returning -1, verbatim from man getc:
[...] getc() [...] return[s] the character read as an unsigned char cast to an int or EOF on end of file or error.
EOF typically equals -1. To test this do a printf("EOF=%d\n", EOF);
fp=fopen("F:\\demo.txt","w");
Opens the file for writing, then you try to read from it. That's not going to work.
I'll also note that your program keeps trying to use fp even if it fails to be created since your if checking fp only prints an error, it doesn't stop the program.

Prevent popen() from displaying error on stderr

I have the following code to find the release of the Linux distribution that I am using.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
return print_osinfo();
}
int print_osinfo()
{
FILE *fp;
extern FILE* popen();
char buffer[128];
int index = 0;
memset(buffer,0,sizeof(buffer));
fp = popen("/etc/centos-release", "r");
if(!fp)
{
pclose(fp);
fp = popen("/etc/redhat-release", "r");
if(!fp)
{
pclose(fp);
return 1;
}
}
while(fgets(buffer, sizeof(buffer), fp)!= NULL)
{
printf("%s\n",buffer);
}
pclose(fp);
return 0;
}
If I run the above code on Ubuntu 14.04 I get the following error.
sh: 1: /etc/centos-release: not found
I fail to understand why it is not trying to open redhat-release and then return -1. Also, is there a way to prevent the above error from being displayed on the screen?
popen is a function more suited for accessing the output of a subprocess than for simply accessing the contents of a file. For that, you should use fopen. fopen takes a file path and a mode as arguments, so all you would need to do is replace your popens with fopens and it should work perfectly.
If you really want to use popen, it takes a shell command as it's first argument, not a filename. Try popen("cat /etc/centos-release","r"); instead.
Now, you might be a bit confused, because both of these functions return a FILE pointer. fopen returns a pointer to the file you passed as an argument. popen, however, returns a pipe pointing to the output of the command you passed to it, which C sees as a FILE pointer. This is because, in C, all i/o is file access; C's only connection to the outside world is through files. So, in order to pass the output of some shell command, popen creates what C sees as a FILE in memory, containing the output of said shell command. Since it is rather absurd to run a whole other program (the shell command) just to do what fopen does perfectly well, it makes far more sense to just use fopen to read from files that already exist on disk.

Is it legal to use freopen and after it fopen ?

Suppose I have a string char* str.
I print it to the buffer in the following way:
char buf[MAX_LEN];
freopen("tmp","w",stdout);
printf("%s\n",str);
fflush(stdout);
fp = fopen(tmp,"r");
if (fp == NULL) return;
fgets(buf,MAX_LEN,fp);
fclose(fp);
fclose(stdout);
May this code cause invalid stream buffer handle?
Is it legal to use freopen and after it fopen?
Based on constrains of my system I can't use fprintf and sprintf.
In theory, it's perfectly legal and works fine. It's even its main use case, according to its man page :
The freopen() function opens the file whose name is the string
pointed to by path and associates the stream pointed to by stream with
it. The original stream (if it exists) is closed. The mode argument
is used just as in the fopen() function. The primary use of the
freopen() function is to change the file associated with a standard
text stream (stderr, stdin, or stdout)
In practice, your code won't work : there are some mistake mainly between "tmp" and tmp & missing headers. This code will work:
#include <stdio.h>
#define MAX_LEN 512
int main() {
const char* str = "data\n";
FILE* fp;
char buf[MAX_LEN];
freopen("tmp","w",stdout);
printf("%s\n",str);
fflush(stdout);
fp = fopen("tmp","r");
if (fp == NULL) return;
fgets(buf,MAX_LEN,fp);
// here, buf gets str's content
fclose(fp);
fclose(stdout);
return 0;
}

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