Calling valiable name from another variable - arrays

Please help to call the variable from another variable.
I have the script which is taking EC2 instances and return in "*ec2.Instance" variable.
I can print information from static text, for example :
fmt.Println(instance.InstanceType) // t3.small
But I have the list of reqired fields like and don't know how dynamic use name from this list :
fields := []string{"InstanceId", "InstanceType", "PrivateIpAddress"}
for i := range fields {
fmt.Println(fields[i])
fmt.Println(instance.fields[i]) // Not correct ... :(
}

You need to use reflection to do this in go.
The key takeaway is you need to "analyze" the returned value at runtime and access properties by name from the "reflected" structure. Reflection basically means analyzing objects at runtime.
package main
import (
"fmt"
"reflect"
)
type whatever struct {
cat string
dog string
animals int
something string
}
func main() {
wantProps := []string{ "cat", "animals"}
we := whatever{cat: "meow", animals: 22}
r := reflect.ValueOf(we)
for _, propName := range wantProps {
prop := r.FieldByName(propName)
fmt.Println(propName, prop)
}
}
More details:
Golang dynamic access to a struct property

Related

type interface {} does not support indexing in golang

I have such map:
Map := make(map[string]interface{})
This map is supposed to contain mapping from string to array of objects. Arrays can be of different types, like []Users or []Hosts. I populated this array:
TopologyMap["Users"] = Users_Array
TopologyMap["Hosts"] = Hosts_Array
but when I try to get an elements from it:
Map["Users"][0]
it gives an error:
(type interface {} does not support indexing)
How can I overcome it?
You have to explicitly convert your interface{} to a slice of the expected type to achieve it. Something like this:
package main
import "fmt"
type Host struct {
Name string
}
func main() {
Map := make(map[string]interface{})
Map["hosts"] = []Host{Host{"test.com"}, Host{"test2.com"}}
hm := Map["hosts"].([]Host)
fmt.Println(hm[0])
}
Playground link
First thing to be noted is the interface{} can hold any data type including function and struct or []struct. Since the error gives you :
(type interface {} does not support indexing)
It means that it holds no slice or no array values. Because you directly call the index in this case is 0 to an interface{} and you assume that the Map["Users"] is an array. But it is not. This is one of very good thing about Go it is statically type which mean all the data type is check at compiled time.
if you want to be avoid the parsing error like this:
panic: interface conversion: interface {} is []main.User, not
[]main.Host
To avoid that error while your parsing it to another type like Map["user"].([]User) just in case that another data type pass to the interface{} consider the code snippet below :
u, ok := myMap["user"].([]User)
if ok {
log.Printf("value = %+v\n", u)
}
Above code is simple and you can use it to check if the interface match to the type you are parsing.
And if you want to be more general passing the value to your interface{} at runtime you can check it first using reflect.TypeOf() please consider this code :
switch reflect.TypeOf(myMap["user"]).String() {
case "[]main.User":
log.Println("map = ", "slice of user")
logger.Debug("map = ", myMap["user"].([]User)[0])
case "[]main.Host":
log.Println("map = ", "slice of host")
logger.Debug("map = ", myMap["user"].([]Host)[0])
}
after you know what's the value of the interface{} you can confidently parse it the your specific data type in this case slice of user []User. Not that the main there is a package name you can change it to yours.
This is how I solved it for unstructured data. You have to parse to index string until you reach the end. Then you can print key value pairs.
yamlStr := `
input:
bind: 0.0.0.0:12002
interface: eth0
reaggregate: {}
versions: {}
output:
destination: owl-opsw-sw-dev-4.opsw:32001
interface: eth0
`
var obj map[string]interface{}
if err := yaml.Unmarshal([]byte(yamlStr), &obj); err != nil {
// Act on error
}
// Set nested object to map[string]
inputkv := streamObj["input"].(map[string]interface{})
for key, value := range inputkv {
// Each value is an interface{} type, that is type asserted as a string
fmt.Println(key, value.(string))
}
Result
bind 0.0.0.0:12002
interface eth0

How to set new value to struct member of explicit type from interface{} value (reflection)? Golang

I want to understand some subtle moments of using reflect package. Please, see example below, it describes better what I want to know:
type Robot struct {
id int
model string
}
func change(i interface{}, fields ...string) {
v := reflect.ValueOf(i).Elem()
// here I emulate function by slice that could return any value,
// so here I need to check if I can store incoming values to existing struct
returns := []interface{}{100, "Something"}
for i, name := range fields {
x := reflect.ValueOf(&returns[i]).Elem()
//check if value representing x is the same of struct member
v.FieldByName(name).Set(x)
// ^ here I want to store 100 to Robot.id when i = 0,
// and "Something" to Robot.model when i = 1
}
}
func main() {
robot := &Robot{id: 1, model: "T310"}
change(robot, "model", "id")
// now robot become as follows: &Robot{100, "Something"}
}
Why does it need for?
// It is need for retrieving values from sql DB into struct members
// (only for training purposes :))
// Example:
f := func(q string, structs interface{}, fields ...string) {
rows, _ := db.Query(q)
for i := 0; rows.Next(); i++ {
rows.Scan(&structs[i])
// very dirty here! it's hard to understand how to implement it
}
}
var robots = []*Robot
f("select id, model from robots", robots, "id", "model")
// now each member of robots var should contain values from DB
I tried to be descriptive and explain as short as possible. I hope you understand me..
You can only set exported fields via reflection, so capitalize those first. Otherwise, if you're counting on positional values, make sure they are properly aligned.
Something like this for example: http://play.golang.org/p/ItnjwwJnxe
type Robot struct {
ID int
Model string
}
func change(i interface{}, fields ...string) {
returns := []interface{}{100, "Something"}
v := reflect.ValueOf(i).Elem()
for i, name := range fields {
val := reflect.ValueOf(returns[i])
v.FieldByName(name).Set(val)
}
}
func main() {
robot := &Robot{ID: 1, Model: "T310"}
fmt.Println(robot)
change(robot, "ID", "Model")
fmt.Println(robot)
}

Unmarshalling top-level JSON array in Go

I'm learning Go by writing a simple http server and I need to handle some JSON responses.
With an object response, I can unmarshal it idiomatically with 2 lines of code:
structResult := Foo{}
json.Unmarshal(structBody, &structResult)
I don't know how to do the same for an array response (see the example below). Is there a way to specify (possibly via json tag) that top-level array should go into a given struct field?
package main
import "fmt"
import "encoding/json"
type Foo struct {
Id uint64 `json:"id"`
Name string `json:"name"`
}
type BaseResult struct {
Error string `json:"error"`
}
type FooResult struct {
BaseResult
Foos []Foo
}
func main() {
// Simple and works.
structBody := []byte(`{"id": 1,"name": "foo"}`)
structResult := Foo{}
json.Unmarshal(structBody, &structResult)
fmt.Printf("%#v\n", structResult)
// Doesn't work.
arrayBody := []byte(`[{"id": 1,"name": "foo"},{"id": 2,"name": "bar"},{"id": 3,"name": "foobar"}]`)
arrayResult := FooResult{}
json.Unmarshal(arrayBody, &arrayResult)
fmt.Printf("%#v\n", arrayResult)
}
I know I could make FooResult an array:
type FooResult []Foo
but then I lose the ability to specify base object which I would like to use to store error message and such. I also know that I can unmarshal into &fooResult.Foos directly, but I want the code to work with both objects and arrays.
UPDATE
Implementing UnmarshalJSON as suggested by #dyoo partially solves my problem, but I was hoping that I could use BaseResult to store parse error in case JSON has a different structure:
arrayBody := []byte(`{"error": "foo"}`)
arrayResult := FooResult{}
json.Unmarshal(arrayBody, &arrayResult)
fmt.Printf("%#v\n", arrayResult)
Of course I could implement more complex logic inside UnmarshalJSON - but isn't there a simpler way to do it?
You can implement the json.Unmarshaler interface in your FooResult, to customize exactly how it responds to unmarshaling. (Similarly, there's a json.Marshaler interface.)
Add:
func (f *FooResult) UnmarshalJSON(bs []byte) error {
return json.Unmarshal(bs, &f.Foos)
}
after which your code should otherwise work. http://play.golang.org/p/oMdoB2e-rB
You might try something like:
func (f *FooResult) UnmarshalJSON(bs []byte) error {
err1 := json.Unmarshal(bs, &f.BaseResult)
err2 := json.Unmarshal(bs, &f.Foos)
if err1 != nil && err2 != nil {
// Arbitrarily choose an error.
return err1
}
return nil
}
although even this is beginning to look dubious. Handling union type results is not quite what the json library is designed to handle automatically for you. You'll need to explicitly code the coercion logic if your JSON has dynamic type.
See: How to unmarshall an array of different types correctly? and http://blog.golang.org/json-and-go for related issues.
Just specify Foos when you Unmarshal
package main
import "fmt"
import "encoding/json"
type Foo struct {
Id uint64 `json:"id"`
Name string `json:"name"`
}
type BaseResult struct {
Error string `json:"error"`
}
type FooResult struct {
BaseResult
Foos []Foo
}
func main() {
// Simple and works.
structBody := []byte(`{"id": 1,"name": "foo"}`)
structResult := Foo{}
json.Unmarshal(structBody, &structResult)
fmt.Printf("%#v\n", structResult)
// Doesn't work.
arrayBody := []byte(`[{"id": 1,"name": "foo"},{"id": 2,"name": "bar"},{"id": 3,"name": "foobar"}]`)
arrayResult := FooResult{}
if err := json.Unmarshal(arrayBody, &arrayResult.Foos); err != nil {
arrayResult.BaseResult.Error = string(arrayBody)
}
fmt.Printf("%#v\n", arrayResult)
}

How to create an associative map in golang?

I'm trying to create an 'associative' map. The issue is that the superMap collects all the values of aMap.
Basically even if I want to store only one instance of amap on each look I endup storing the current instance plus all the previous loops. supermap[value] = amap[value] . However the snippet below stores supermap[value] = amap. The reason is that I can't find any way to fix this. If I delete the old values of aMap after each loop they are deleted from supermap as well.
package main
import (
"fmt"
)
func main() {
aData := map[int]string{
0: "apple",
1: "samsung",
2: "htc",
3: "sony",
}
dir := []string{"user", "doc", "bin", "src"}
aMap := make(map[int]string)
superMap := make(map[string]map[int]string)
for k, v := range dir {
aMap[k] = aData[k]
superMap[v] = aMap
}
hello(superMap)
}
func hello(superMap map[string]map[int]string) {
fmt.Printf("superMap of user is %v \n", superMap["user"])
cnt := len(superMap["user"])
if cnt > 1{
fmt.Printf("expected only one value received %v", cnt)
}
}
Play
As Arjan said in the comment, you need to move the creation of aMap into the for loop. The reason is because, in the original code you posted you are dealing with one instance of aMap in memory. That means, only one map called aMap is created and when you assign another variable to the value of aMap you are assigning a reference. This means, any variable that hold a reference (to aMap) where state is mutated, will be observed in all other variables also holding the reference because they all resolve to the same object in memory.
When the aMap is moved into the for/range loop, this means that 4 individual instances of aMap will be created all with their own memory. Mutating the state of one of those aMaps will not affect the others because they are their own objects in memory. Now, if you took one of those objects and made a reference to it again with another variable then you'd end up in the same boat as the first case.
package main
import (
"fmt"
)
func main() {
aData := map[int]string{
0: "apple",
1: "samsung",
2: "htc",
3: "sony",
}
dir := []string{"user", "doc", "bin", "src"}
//aMap := make(map[int]string) //only one map instance is created in memory
superMap := make(map[string]map[int]string)
for k, v := range dir {
//multiple map instances are created in memory
aMap := make(map[int]string)
aMap[k] = aData[k]
superMap[v] = aMap
}
hello(superMap)
}
func hello(superMap map[string]map[int]string) {
fmt.Printf("superMap of user is %v \n", superMap["user"])
cnt := len(superMap["user"])
if cnt > 1 {
fmt.Printf("expected only one value received %v", cnt)
}
}

Go: how to convert struct to []byte?

I'm trying to use "appengine/memcache" to store data in the cache,
memcache.Item's Value field is []byte
how do I convert a struct to []byte for storing it ?
for example:
type Link struct {
Files []string
}
See the memcache.Codec type, this can be used to convert memcache items. The appengine/memcache package has two codecs already prepared, memcache.Gob and memcache.JSON. You use these codecs instead of the direct call to store and retrieve items from the cache, for example like this for a gob encoded item:
item := &memcache.Item{
Key: myCacheKey,
Object: &myLinkVar,
}
err := memcache.Gob.Set(context, item)
The encoding/gob package is probably your best option.
You could also use the encoding/json package.
If you use encoding/json you get the benefit of being able to read the values from languages other than Go.
If you use encoding/gob you get more speed.
You can use gob#Encoder.Encode:
package main
import (
"bytes"
"encoding/gob"
"fmt"
)
type link struct {
Files []string
}
func main() {
s := link{
[]string{"south", "north"},
}
b := new(bytes.Buffer)
gob.NewEncoder(b).Encode(s)
// "\x1d\xff\x81\x03\x01\x01\x04link\x01\xff\x82\x00\x01\x01\x01\x05Files\x01\xff\x84\x00\x00\x00\x16\xff\x83\x02\x01\x01\b[]string\x01\xff\x84\x00\x01\f\x00\x00\x11\xff\x82\x01\x02\x05south\x05north\x00"
fmt.Printf("%q\n", b)
}
https://golang.org/pkg/encoding/gob#Encoder.Encode

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