Replace a matching string in each line with another string - batch-file

Question

I am trying to replace the number at the end of every line of a given file with an incremented number(+1).
My Input file looks like
C:\documents\a.txt,1988,15.01.00.0059
C:\documents\we.txt,1988,15.01.00.0059
C:\documents\gh.txt,1987,1988,15.01.00.0059
my out put file should be
C:\documents\a.txt,1988,15.01.00.0060
C:\documents\we.txt,1988,15.01.00.0060
C:\documents\gh.txt,1988,15.01.00.0060
My attempt is like
#echo off
setlocal enableextensions disabledelayedexpansion
set "search="
for /F "tokens=1-3 delims=," %%i in (%1) do (
#echo %%i %%j %%k
set "search=%%k"
)
set "replace="
REM #echo %replace%
set "textFile=%1"
for /f "delims=" %%i in ('type "%textFile%" ^& break ^> "%textFile%" ') do (
set "line=%%i"
setlocal enabledelayedexpansion
>>"%textFile%" echo(!line:%search%=%replace%!
endlocal
)
i could able to get 15.01.00.0059 from the input file but dont know how to change to 15.01.00.0060 .
replacing to the same input file is also working . I just need to know how to increment the value and assign to "replace".
Thank you
Bhargav.k

Answer 1

This should be flexible enough:
#echo off
setlocal EnableDelayedExpansion EnableExtensions
1>out.txt (
FOR /F tokens^=*^ delims^=.^ eol^= %%L in (input.txt) do (
set "line=%%L"
set "x=!line:.= !"
FOR %%T in (!x!) do set "lastToken=%%T"
cmd /c exit /b !lastToken!
set/a"lstrip=!ERRORLEVEL!+1"
>getlen.tmp echo(!lasttoken!
FOR %%L in (getlen.tmp) do set/a"len=%%~zL-2" %= get length of last token, minus CRLF =%
FOR %%N in (1 1 !len!) do set "lstrip=0!lstrip!" PREFIX lstrip with zeroes
FOR %%N in (!len!) do (
set "lstrip=!lstrip:~-%%N!"
echo !line:~0,-%%N!!lstrip!
)
)
)
del getlen.tmp
ENDLOCAL
This is not a straightforward approach.
The script counts the # of zeroes prefixed before the last token by the ERRORLEVEL returned by EXIT /B, compared with the original token.