So I have an IsNumber() function which checks if an user input is a number or not, if it isn't the the program stops, however the function just isn't working for some reason.
Here is where it's implemented:
bool IsNumber(const char* pStr);
int main()
{
int user;
char decision;
char * str[256] = {user};
bool valid;
scanf("%d",&user);
clear_stdin(); // function to remove
sprintf(str, "%d", user); // to convert input into string so to validate number with function IsNumber
valid = IsNumber(str);
if (valid == false)
{
printf("Entered input is not a number, exiting now.");
exit(1);
}
}
And here is the function itself:
bool IsNumber(const char* pStr)
{
if(NULL == pStr || *pStr == "\0")
return false;
int dotCount = 0;
int plusCount = 0;
int minusCount = 0;
while (*pStr)
{
char c = *pStr;
switch(c)
{
case '.':
if (++dotCount > 1)
return false;
break;
case '-':
if (++minusCount > 1)
return false;
break;
case '+':
if (++plusCount > 1)
return false;
default:
if (c < '0' || c > '9')
return false;
}
pStr++;
}
return true;
}
your function does not check for the most of the errors (for example 345+456). You need to remember that some chars can be only at the particular places to make number valid.
Here you have a bit better one (very simple for the sake of simplicity of the answer).
int isNumber(const char *str)
{
int result = 1;
int dotFound = 0;
const char *saved = str;
if(str || *str)
{
while(*str && result)
{
if(*str == '-' || *str == '+')
{
if(str != saved) result = 0;
}
else
{
if(*str == '.')
{
if(dotFound) result = 0;
dotFound = 1;
}
else
{
if(!isdigit(*str)) result = 0;
}
}
str++;
}
}
return result;
}
Your test idea is wrong. sprintf will always print a valid int number. it will also never generate the string with the dot '.' inside.
https://godbolt.org/z/d_Bah9
There are several issues with your code:
The line
char *str[256] = {user};
You are declaring an array of 256 pointers to char, none of them is initialized along your code, so they point to nothing, furthermore you are trying to assign an int variable to a char pointer.
The line
sprintf(str, "%d", user);
str is not a valid argument, you could use str[0], but, again, str[0] points to nowhere.
The line
if(NULL == pStr || *pStr == "\0")
^^^^
You are comparing a single character with a string, a valid comparison would be:
if(NULL == pStr || *pStr == '\0')
^^^^
Other issues are:
A missing break in case '+'.
char decision is never used.
Related
I am in the stage of preparing myself for exams, and the thing that I m least proud of are my skills with strings. What I need to do is remove a word from a sentence, without using <string.h> library at all.
This is what I've got so far. It keeps showing me that certain variables are not declared, such as start and end.
#include <stdio.h>
/* Side function to count the number of letters of the word we wish to remove */
int count(char *s) {
int counter = 0;
while (*s++) {
counter++;
s--;
return counter;
}
/* Function to remove a word from a sentence */
char *remove_word(const char *s1, const char *s2) {
int counter2 = 0;
/* We must remember where the string started */
const char *toReturn = s1;
/* Trigger for removing the word */
int found = 1;
/* First we need to find the word we wish to remove [Don't want to
use string.h library for anything associated with the task */
while (*s1 != '\0') {
const char *p = s1;
const char *q = s2;
if (*p == *q)
const char *start = p;
while (*p++ == *q++) {
counter2++;
if (*q != '\0' && counter2 < count(s2))
found = 0;
else {
const char *end = q;
}
}
/* Rewriting the end of a sentence to the beginning of the found word */
if (found) {
while (*start++ = *end++)
;
}
s1++;
}
return toReturn;
}
void insert(char niz[], int size) {
char character = getchar();
if (character == '\n')
character = getchar();
int i = 0;
while (i < size - 1 && character != '\n') {
array[i] = character;
i++;
character = getchar();
}
array[i] = '\0';
}
int main() {
char stringFirst[100];
char stringSecond[20];
printf("Type your text here: [NOT MORE THAN 100 CHARACTERS]\n");
insert(stringFirst, 100);
printf("\nInsert the word you wish to remove from your text.");
insert(stringSecond, 20);
printf("\nAfter removing the word, the text looks like this now: %s", stringFirst);
return 0;
}
your code is badly formed, i strongly suggest compiling with:
gcc -ansi -Wall -pedantic -Werror -D_DEBUG -g (or similar)
start with declaring your variables at the beginning of the function block, they are known only inside the block they are declared in.
your count function is buggy, missing a closing '}' (it doesn't compile)
should be something like
size_t Strlen(const char *s)
{
size_t size = 0;
for (; *s != '\n'; ++s, ++size)
{}
return size;
}
implementing memmove is much more efficient then copy char by char
I reformatted you code for small indentation problems and indeed indentation problems indicate real issues:
There is a missing } in count. It should read:
/* Side function to count the number of letters of the word we wish to remove */
int count(char *s) {
int counter = 0;
while (*s++) {
counter++;
}
return counter;
}
or better:
/* Side function to count the number of letters of the word we wish to remove */
int count(const char *s) {
const char *s0 = s;
while (*s++) {
continue;
}
return s - s0;
}
This function counts the number of bytes in the string, an almost exact clone of strlen except for the return type int instead of size_t. Note also that you do not actually use nor need this function.
Your function insert does not handle EOF gracefully and refuses an empty line. Why not read a line with fgets() and strip the newline manually:
char *input(char buf[], size_t size) {
size_t i;
if (!fgets(buf, size, stdin))
return NULL;
for (i = 0; buf[i]; i++) {
if (buf[i] == '\n') {
buf[i] = '\0';
break;
}
}
return buf;
}
In function remove_word, you should define start and end with a larger scope, typically the outer while loop's body. Furthermore s1 should have type char *, not const char *, as the phrase will be modified in place.
You should only increment p and q if the test succeeds and you should check that p and q are not both at the end of their strings.
last but not least: you do not call remove_word in the main function.
The complete code can be simplified into this:
#include <stdio.h>
/* Function to remove a word from a sentence */
char *remove_word(char *s1, const char *s2) {
if (*s2 != '\0') {
char *dst, *src, *p;
const char *q;
dst = src = s1;
while (*src != '\0') {
for (p = src, q = s2; *q != '\0' && *p == *q; p++, q++)
continue;
if (*q == '\0') {
src = p; /* the word was found, skip it */
} else {
*dst++ = *src++; /* otherwise, copy this character */
}
}
*dst = '\0'; /* put the null terminator if the string was shortened */
}
return s1;
}
char *input(char buf[], size_t size) {
size_t i;
if (!fgets(buf, size, stdin))
return NULL;
for (i = 0; buf[i]; i++) {
if (buf[i] == '\n') {
buf[i] = '\0';
break;
}
}
return buf;
}
int main() {
char stringFirst[102];
char stringSecond[22];
printf("Type your text here, up to 100 characters:\n");
if (!input(stringFirst, sizeof stringFirst))
return 1;
printf("\nInsert the word you wish to remove from your text: ");
if (!input(stringSecond, sizeof stringSecond))
return 1;
printf("\nAfter removing the word, the text looks like this now: %s\n",
remove_word(stringFirst, stringSecond));
return 0;
}
Your start and end pointers are defined within a block which makes their scope limited within that block. So, they are not visible to other parts of your code, and if you attempt to reference them outside their scope, the compiler will complain and throw an error. You should declare them at the beginning of the function block.
That said, consider the following approach to delete a word from a string:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int delete_word(char *buf,
const char *word);
int main(void)
{
const char word_to_delete[] = "boy";
fputs("Enter string: ", stdout);
char buf[256];
fgets(buf, sizeof(buf), stdin);
if (delete_word(buf, word_to_delete))
{
printf("Word %s deleted from buf: ", word_to_delete);
puts(buf);
}
else
{
printf("Word %s not found in buf: ", word_to_delete);
puts(buf);
}
system("PAUSE");
return 0;
}
int chDelimit(int ch)
{
return
(ch == '\n' || ch == '\t') ||
(ch >= ' ' && ch <= '/') ||
(ch >= ':' && ch <= '#') ||
(ch >= '[' && ch <= '`') ||
(ch >= '{' && ch <= '~') ||
(ch == '\0');
}
char *find_pattern(char *buf,
const char *pattern)
{
size_t n = 0;
while (*buf)
{
while (buf[n] && pattern[n])
{
if (buf[n] != pattern[n])
{
break;
}
n++;
}
if (!pattern[n])
{
return buf;
}
else if (!*buf)
{
return NULL;
}
n = 0;
buf++;
}
return NULL;
}
char *find_word(char *buf,
const char *word)
{
char *ptr;
size_t wlen;
wlen = strlen(word);
ptr = find_pattern(buf, word);
if (!ptr)
{
return NULL;
}
else if (ptr == buf)
{
if (chDelimit(buf[wlen]))
{
return ptr;
}
}
else
{
if (chDelimit(ptr[-1]) &&
chDelimit(ptr[wlen]))
{
return ptr;
}
}
ptr += wlen;
ptr = find_pattern(ptr, word);
while (ptr)
{
if (chDelimit(ptr[-1]) &&
chDelimit(ptr[wlen]))
{
return ptr;
}
ptr += wlen;
ptr = find_pattern(ptr, word);
}
return NULL;
}
int delete_word(char *buf,
const char *word)
{
size_t n;
size_t wlen;
char *tmp;
char *ptr;
wlen = strlen(word);
ptr = find_word(buf, word);
if (!ptr)
{
return 0;
}
else
{
n = ptr - buf;
tmp = ptr + wlen;
}
ptr = find_word(tmp, word);
while (ptr)
{
while (tmp < ptr)
{
buf[n++] = *tmp++;
}
tmp = ptr + wlen;
ptr = find_word(tmp, word);
}
strcpy(buf + n, tmp);
return 1;
}
If you have to do it manually, just loop over the indicies of your string to find the first one that matches and than you’ll have a second loop that loops for all the others that matches and resets all and jumps to the next index of the first loop if not matched something in order to continue the searching. If I recall accuretaly, all strings in C are accesible just like arrays, you’ll have to figure it out how. Don’t afraid, those principles are easy! C is an easy langugae, thiught very long to write.
In order to remove: store the first part in an array, store the second part in an array, alloc a new space for both of them and concatinate them there.
Thanks, hit the upvote button.
Vitali
EDIT: use \0 to terminate your newly created string.
i wanted to write a code which would allow me to find a position of a fist occurence of a letter, this is what i have come up so far. As you can see, what the function returns is actually a value and not the index. Is there a way to find it without simply giving the initial value of index as in the code no.2?
char *recFirstPosition(char * source, int letter)
{
if(*source == letter)
return *source;
if (*source =='\0')
return 0;
recFirstPosition(++source, letter);
}
char *recFirstPosition(char * source, int letter, int index)
{
if(*(source+index) == letter)
return index;
if (*(source+index) =='\0')
return 0;
recFirstPosition(source, letter, ++index);
}
Simply detach * from the first return and add return for the recursive call of your first version.
char *recFirstPosition(char * source, int letter)
{
if(*source == letter)
return source;
if (*source =='\0')
return 0;
return recFirstPosition(++source, letter);
}
It will make the code work. Your first version causes a type error.
The following is more readable version than the above:
char *recFirstPosition(char *source, char letter)
{
if (*source == '\0')
return NULL;
else if (*source == letter)
return source;
else
return recFirstPosition(++source, letter);
}
The above code also changed the type of the second parameter, but is written mostly inspired by several comments (Special thanks to Yuli and Dmitri).
And you may use the function as follows:
int main()
{
char *s = "Hello";
char *p = recFirstPosition(s, 'l');
if (p != NULL) {
int index = p - s;
printf("%s[%d] = %c\n", s, index, *p);
}
return 0;
}
Here is what I think could work. Please test it more since I did not have enough time to work with it
Edit: This return the position of the last occurrence but should give you enough to work with.
Edit2: Updated the function so now it works for
#include <stdio.h>
char *recFirstPosition(const char *s, int c, char *find){
if(s==NULL) return NULL;
if(*s == '\0') return (c == '\0') ? (char*)s : find;
if(*s == c) return (char*) s;
return recFirstPosition(s + 1, c, *s == c ? (char*)s : find);
}
int main ()
{
char str[] = "This is a sample string";
char * pch;
printf ("Looking for the 's' character in \"%s\"...\n",str);
pch=recFirstPosition(str,'s', NULL);
// Uncomment the while loop to get all instances positions
//while (pch!=NULL)
//{
printf ("found at %d\n",pch-str+1);
// pch=recFirstPosition(pch+1,'s',NULL);
//}
return 0;
}
output
Looking for the 's' character in "This is a sample string"...
found at 4
How can I fill an empty Char Array with keyboard?
something like
char a_string[];
while("if not Q")
{
printf("Enter a number: ");
scanf("%c", a_string);
}
I know this is wrong
I just want to know how to give values to my a_string[], without limiting the size.
so the size will vary depend on how many keys i'm gonna enter from keyboard.
Thanks!
If you will know at the start of runtime how many keys you'll enter, you can have it ask first for the number of keys and then for the individual characters, as in the untested snippet below.
Otherwise, you have to set some real-world maximum (e.g. 10000) that will never be reached, or, if that's not possible, set a per-array maximum and make provisions for rollover into a new array. That last option really is the same (eventually bounded by memory) but gives you a larger maximum.
char *mychars;
int numchars;
printf("Please enter the total number of characters:\n");
if (scanf("%d", &numchars) == NULL) {
printf("couldn't read the input; exiting\n");
exit(EXIT_FAILURE);
}
if (numchars <= 0) {
printf("this input must be positive; exiting\n");
exit(EXIT_FAILURE);
}
mychars = (char *) malloc (numchars * sizeof(char));
int current_pos = 0;
printf("Enter a digit and hit return:\n");
while (scanf("%c", &mychars[current_pos]) != NULL && current_pos < numchars) {
current_pos++;
printf("Enter a digit and hit return:\n");
}
Try this:
#include <stdlib.h>
#include <stdio.h>
int main() {
char *string = NULL;
char *newstring = NULL;
char c = '\0';
unsigned int count = 0;
while(c != 'Q'){
c = getc(stdin);
if(string == NULL){
string = (char *) malloc(sizeof(char)); // remember to include stdlib.h
string[0] = c;
}
else{
newstring = (char *) realloc(string, sizeof(char)*count);
string = newstring;
string[count] = c;
}
count++;
}
string[count-1] = '\0'; // remove the Q character
fprintf(stderr,"here you are: %s",string);
free(string); // remember this!
return 0;
}
Repetitive calls to realloc() will meet the need.
Double realloc() size as needed to avoid O(n) calls.
char *GetQLessString(void) {
size_t size_alloc = 1;
size_t size_used = size_alloc;
char *a_string = malloc(size_alloc);
if (a_string == NULL) {
return NULL; // Out of memory
}
char ch;
while(scanf("%c", &ch) == 1 && (ch != 'Q')) {
size_used++;
if (size_used > size_alloc) {
if (size_alloc > SIZE_MAX/2) {
free(a_string);
return NULL; // Too big - been typing a long time
}
size_alloc *= 2;
char *new_str = realloc(a_string, size_alloc);
if (new_str == NULL) {
free(a_string);
return NULL; // Out of memory
}
a_string = new_str;
}
a_string[size_used - 2] = ch;
}
a_string[size_used - 1] = '\0';
return a_string;
}
Code could do a final realloc(a_string, size_used) to trim excess memory allocation.
Calling routine needs to call free() when done with the buffer.
The following would be cleaner.
int ch;
while((ch = fgetc(stdin)) != EOF && (ch != 'Q')) {
I'm trying to tokenize a sting and here is my attempt.
char new_str[1024];
void tokenize_init(const char str[]){//copy the string into global section
strcpy(new_str,str);
}
int i = 0;
char *tokenize_next() {
const int len = strlen(new_str);
for(; i <= len; i++) {
if ( i == len) {
return NULL;
}
if ((new_str[i] >= 'a' && new_str[i] <= 'z') ||
(new_str[i] >= 'A' && new_str[i] <= 'Z')) {
continue;
}else {
new_str[i] = '\0';
i = i + 1;
return new_str;
}
}
return NULL;
}
//main function
int main(void) {
char sentence[] = "This is a good-sentence for_testing 1 neat function.";
printf("%s\n", sentence);
tokenize_init(sentence);
for (char *nt = tokenize_next();
nt != NULL;
nt = tokenize_next())
printf("%s\n",nt);
}
However, it just print out the first word of the sentence(which is "This") and then stop. Can someone tell me why? My guess is my new_str is not persisent and when the main function recall tokenize_next() the new_str become just the first word of the sentence. Thanks in advance.
The reason that it only prints out "This" is because you iterate to the first non-letter character which happens to be a space, and you replace this with a null terminating character at this line:
new_str[i] = '\0';
After that, it doesn't matter what you do to the rest of the string, it will only print up to that point. The next time tokenize_next is called the length of the string is no longer what you think it is because it is only counting the word "This" and since "i" has already reached that amount the function returns and so does every successive call to it:
if ( i == len)
{
return NULL;
}
To fix the function you would need to somehow update your pointer to look past that character on the next iteration.
However, this is quite kludgy. You are much better off using one of the mentioned functions such as strtok or strsep
UPDATE:
If you cannot use those functions then a redesign of your function would be ideal, however, per your request, try the following modifications:
#include <string.h>
#include <cstdio>
char new_str[1024];
char* str_accessor;
void tokenize_init(const char str[]){//copy the string into global section
strcpy(new_str,str);
str_accessor = new_str;
}
int i = 0;
char* tokenize_next(void) {
const int len = strlen(str_accessor);
for(i = 0; i <= len; i++) {
if ( i == len) {
return NULL;
}
if ((str_accessor[i] >= 'a' && str_accessor[i] <= 'z') ||
(str_accessor[i] >= 'A' && str_accessor[i] <= 'Z')) {
continue;
}
else {
str_accessor[i] = '\0';
char* output = str_accessor;
str_accessor = str_accessor + i + 1;
if (strlen(output) <= 0)
{
str_accessor++;
continue;
}
return output;
}
}
return NULL;
}
//main function
int main(void) {
char sentence[] = "This is a good-sentence for_testing 1 neater function.";
printf("%s\n", sentence);
tokenize_init(sentence);
for (char *nt = tokenize_next(); nt != NULL; nt = tokenize_next())
printf("%s\n",nt);
}
Just a quick one: in C I have a buffer full of data like below:
char buffer[255]="CODE=12345-MODE-12453-CODE1-12355"
My question is how to search through this. For example for the CODE=12345, section bear in mind that the numbers change, so I would like to search like this CODE=***** using wildcard or preset amount of spaces after the CODE= part.
This method wont compile last one left to try
#include <stdio.h>
#include <string.h>
#include <windows.h>
int main ()
{
char buf[255]="CODE=12345-MODE-12453-CODE1-12355";
#define TRIMSPACES(p) while(*p != '\0' && isspace((unsigned char)*p) != 0) ++p
#define NSTRIP(p, n) p += n
#define STRIP(p) ++p
char* getcode(const char *input)
{
char *p = (char*) input, *buf, *pbuf;
if((buf = malloc(256)) == NULL)
return NULL;
pbuf = buf;
while(*p != '\0') {
if(strncmp(p, "CODE", 3) == 0) {
NSTRIP(p, 4); //remove 'code'
TRIMSPACES(p);//trim white-space after 'code'
if(*p != '=')
return NULL;
STRIP(p); // remove '='
TRIMSPACES(p); //trim white-spaces after '='
/* copy the value until found a '-'
note: you must be control the size of it,
for avoid overflow. we allocated size, that's 256
or do subsequent calls to realloc()
*/
while(*p != '\0' && *p != '-')
*pbuf ++ = *p++;
// break;
}
p ++;
}
//put 0-terminator.
*pbuf ++ = '\0';
return buf;
}
//
}
You could use the sscanf() function:
int number;
sscanf(buffer, "CODE = %i", &number);
for that to work well your buffer has to be null terminated.
Another way to do it instead of sscanf():
char *input, *code;
input = strstr(buf, "CODE");
if(input == NULL) {
printf("Not found CODE=\n");
return -1;
}
code = strtok(strdup(input), "=");
if(code != NULL) {
code = strtok(NULL, "-");
printf("%s\n", code); // code = atoi(code);
} else {
//not found '='
}
Or more robust way.. a bit more complex:
#define TRIMSPACES(p) while(*p != '\0' && isspace((unsigned char)*p) != 0) ++p
#define NSTRIP(p, n) p += n
#define STRIP(p) ++p
char* getcode(const char *input, size_t limit)
{
char *p = (char*) input, *buf, *pbuf;
size_t i = 0;
while(*p != '\0') {
if(strncmp(p, "CODE", 3) == 0) {
NSTRIP(p, 4); //remove 'code'
TRIMSPACES(p);//trim all white-spaces after 'code'
/* check we have a '=' after CODE (without spaces).
if there is not, returns NULL
*/
if(*p != '=')
return NULL;
/* ok. We have.. now we don't need of it
just remove it from we output string.
*/
STRIP(p);
/* remove again all white-spaces after '=' */
TRIMSPACES(p);
/* the rest of string is not valid,
because are white-spaces values.
*/
if(*p == '\0')
return NULL;
/* allocate space for store the value
between code= and -.
this limit is set into second parameter.
*/
if((buf = malloc(limit)) == NULL)
return NULL;
/* copy the value until found a '-'
note: you must be control the size of it,
for don't overflow. we allocated 256 bytes.
if the string is greater it, do implementation with
subjecents call to realloc()
*/
pbuf = buf;
while(*p != '\0' && *p != '-' && i < limit) {
*pbuf ++ = *p++;
i ++;
}
*pbuf ++ = '\0';
return buf;
}
p ++;
}
return NULL;
}
And then:
char buf[255] = "foo baa CODE = 12345-MODE-12453-CODE-12355";
char *code = getcode(buf,256);
if(code != NULL) {
printf("code = %s\n", code);
free(code);
} else {
printf("Not found code.\n");
}
output:
code = 12345
Check out this online.
if you want to don't differentiate case, you can use the strncasecmp() that's POSIX function.
Assuming the CODE= part always comes at the beginning of the string, it's pretty easy:
sscanf(buffer, "CODE = %d", &number);
...but you want buffer to be char[255], not unsigned long.
Edit: If the CODE= part isn't necessarily at the beginning of the string, you can use strstr to find CODE in the buffer, do your sscanf starting from that point, then look immediately following that:
int codes[256];
char *pos = buffer;
size_t current = 0;
while ((pos=strstr(pos, "CODE")) != NULL) {
if (sscanf(pos, "CODE = %d", codes+current))
++current;
pos += 4;
}
Edit2:
For example, you'd use this something like this:
#include <stdio.h>
#include <string.h>
#include <windows.h>
int main ()
{
// This is full of other junk as well
char buffer[255]="CODE=12345 MODE-12453 CODE=12355" ;
int i;
int codes[256];
char *pos = buffer;
size_t current = 0;
while ((pos=strstr(pos, "CODE")) != NULL) {
if (sscanf(pos, "CODE = %d", codes+current))
++current;
pos += 4;
}
for (i=0; i<current; i++)
printf("%d\n", codes[i]);
return 0;
}
For me, this produces the following output:
12345
12355
...correctly reading the two "CODE=xxx" sections, but skipings over the "MODE=yyy" section.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char *getcode(const char *str, const char *pattern){
//pattern: char is match, space is skip, * is collect
static const char *p=NULL;
char *retbuf, *pat;
int i, match, skip, patlen;
if(str != NULL) p=str;
if(p==NULL || *p=='\0') return NULL;
if(NULL==(retbuf=(char*)malloc((strlen(p)+1)*sizeof(char))))
return NULL;
pat = (char*)pattern;
patlen = strlen(pat);
i = match = skip = 0;
while(*p){
if(isspace(*p)){
++p;
++skip;
continue;
}
if(*pat){
if(*p == *pat){
++match;
++p;
++pat;
} else if(*pat == '*'){
++match;
retbuf[i++]=*p++;
++pat;
} else {
if(match){//reset
pat=(char*)pattern;
p -= match + skip -1;
i = match = skip = 0;
} else //next
++p;
}
} else {
break;
}
}
if(i){//has match
retbuf[i++]='\0';
retbuf=realloc(retbuf, i);
return retbuf;
} else {
free(retbuf);
return NULL;
}
}
int main (){
char *code;
code=getcode("CODE=12345-MODE-12453-CODE1-12355", "CODE=*****");
printf("\"%s\"\n",code);//"12345"
free(code);
code=getcode(" CODE = 12345-MODE-12453-CODE1-12355", "CODE=*****");
printf("\"%s\"\n",code);//"12345"
free(code);
code=getcode("CODE-12345-MODE-12453-CODE1-12355", "CODE=*****");
if(code==NULL)printf("not match\n");//not match
code=getcode("CODE=12345-MODE-12453-CODE=12355", "CODE=*****");
printf("\"%s\"\n",code);//"12345"
free(code);
code=getcode(NULL, "CODE=*****");
printf("\"%s\"\n",code);//"12355"
free(code);
code=getcode("CODE=12345-MODE-12453-CODE1-12355", "CODE=*****");
printf("\"%s\"\n",code);//"12345"
free(code);
code=getcode(NULL, "CODE1-*****");
printf("\"%s\"\n",code);//"12355"
free(code);
return 0;
}