Got quite a head-scratcher....
I'm using the VBScript function REPLACE to replace spaces in a decrypted field from a MSSQL DB with "/".
But the REPLACE function isn't "seeing" the spaces.
For example, if I run any one of the following, where the decrypted value of the field "ITF_U_ClientName_Denc" is "Johnny Carson":
REPLACE(ITF_U_Ledger.Fields("ITF_U_ClientName_Denc")," ","/")
REPLACE(ITF_U_Ledger.Fields("ITF_U_ClientName_Denc")," ","/")
REPLACE(ITF_U_Ledger.Fields("ITF_U_ClientName_Denc"),"Chr(160)","/")
REPLACE(CSTR(ITF_U_Ledger.Fields("ITF_U_ClientName_Denc"))," ","/")
REPLACE(ITF_U_Ledger.Fields("ITF_U_ClientName_Denc")," ","/",1,-1,1)
REPLACE(ITF_U_Ledger.Fields("ITF_U_ClientName_Denc")," ","/",1,-1,0)
The returned value is "Johnny Carson" (space not replaced with /)
The issue seems to be exclusively with spaces, because when I run this:
REPLACE(ITF_U_Ledger.Fields("ITF_U_ClientName_Denc"),"a","/")
I get "Johnny C/rson".
Also, the issue seems to be exclusively with spaces in the decrypted value, because when I run this:
REPLACE("Johnny Carson"," ","/")
Of course, the returned value is "Johnny/Carson".
I have checked what is being written to the source of the page and it is simply "Johnny Carson" with no encoding or special characters.
I have also tried the SPLIT function to see if it would "see" the space, but it doesn't.
Finally, thanks to a helpful comment, I tried VBS REGEX searching for \s.
Set regExp = New RegExp
regExp.IgnoreCase = True
regExp.Global = True
regExp.Pattern = "\s" 'Add here every character you don't consider as special character
strProcessed = regExp.Replace(ITF_U_Ledger.Fields("ITF_U_ClientName_Denc"), "?")
Unfortunately, strProcessed retruns "Johnny Carson" (ie. spaces not detected/removed).
If I replace regExp.Pattern = "a", strProcessed returns "Johnny C?rson".
Many thanks for your help!!
As we found, the right character code is 160, and that did the trick:
replace(..., ChrW(160), "...")
This seems to be data specific and, additionally, as an alternative you can try to get same encoding of the source script (i.e. save with Save As with Encoding), or convert received database value into a different target encoding.
Related
I am trying to save category name after convert in slug
So in entity I have used setter for convert my text to slug text
protected function _setName($name)
{
return Text::slug($name);
}
After send post request in input name "আমি তোমায় ভালোবাসি"
Has got in database
ami-tomaya-bhalobasi
After make transliteratorId false
return Text::slug($name,[
'transliteratorId' => false
]);
I got output : আম-ত-ম-য-ভ-ল-ব-স
My expected result is
আমি-তোমায়-ভালোবাসি
How can I get my desire result ?
The whole point of slugs is to obtain a "safe" pure US-ASCII string. If all you seemingly want is to remove white spaces you can use a simple regular expression:
preg_replace('/\s/u', '-', 'আমি তোমায় ভালোবাসি')
However, I recommend you double-check why you think this is necessary in the first place. A properly encoded URL would display spaces as %20 anyway, which is "ugly" in a Latin script text but will get unnoticed in other scripts:
var_dump(rawurlencode('আমি তোমায় ভালোবাসি'));
string(159) "%E0%A6%86%E0%A6%AE%E0%A6%BF%20%E0%A6%A4%E0%A7%8B%E0%A6%AE%E0%A6%BE%E0%A6%AF%E0%A6%BC%20%E0%A6%AD%E0%A6%BE%E0%A6%B2%E0%A7%8B%E0%A6%AC%E0%A6%BE%E0%A6%B8%E0%A6%BF"
૮₍ • ᴥ • ₎ა・Raiden ▬▭⋱𓂅
ᘏ⑅ᘏ╭╯Welcome╰╮𓂃ᘏᗢ
・・・・・・・・・・・・・・・・・・・・・
https://discord.gg/rsCC8y7WC4
・・・・・・・・・・・・・・・・・・・・・
Join!
・・・・・・・・・・・・・・・・・・・・・
How can I pull the "discord.gg/rsCC8y7WC4" link from a text like this
console.log(invitelink) ==> discord.gg/rsCC8y7WC4
Use String.match() for this. String.match accepts a regex argument which looks like this:
let str = 'hey there this is just a random string';
let res = str.match(/random/);
//res is now ['random']
Now for your problem, you are probably looking for this:
if(msg.content.match(/discord\.gg\/.+/) || msg.content.match(/discordapp\.com\/invite\/.+/)) return msg.channel.send('Hey! You put an invite in your message!');
Now that regex may look a bit messy/complicated but the \s are to escape the character and make sure regex knows that it’s not the special character it uses, and is actually just a character part of the search. To clarify why the above example should work, here’s a little explanation:
match() returns either an array (if it gets a match) or null (if it gets no match). You are searching for the strings 'discord.gg/' followed by any characters and also checking for the string 'discordapp.com/invite/' also followed by any characters.
If this doesn’t work, please tell me.
I am trying to write a GUI that will display the name of the sketch it was generated from using a simple text() command. However, I am running into trouble getting any of the general JS solutions to work for me. Many solutions I have found use the filename reserved word but that does not seem to be reserved in Processing 3.5.4. I have also tried parsing the strings using a similar method to what can be found here. I am very new to processing and this is only my 2nd attempt at using Processing.
Any advice would be greatly appreciated
You can get the path (as a string) to the sketch with sketchPath().
From there you could either parse the string (pull off everything after the last slash) to get the sketch name, or you can use sketchFile() to get a reference to the file itself and get the name from there:
String path = sketchPath();
File file = sketchFile(path);
String sketchName = file.getName();
println(sketchName);
You could combine this all into one line like so:
String sketchName = sketchFile(sketchPath()).getName();
I have done some searching but cannot see how to actually code this. I am new to Python and not really sure what method I should use to try to do this.
I have some files that I would like to rename. Unfortunately the portion towards the file extension is never the same and would like to just remove it.
File name is like AC_DC - Shot Down In Flames (Official Video)-UKwVvSleM6w.mp3
Any help would be appreciated.
Since this looks like the result from youtube-dl, the "random" substring is most likely the unique video id, which in my experience is always 11 characters long. It can, however, include dashes (-), so the regex-approach suggested by smitrp would not always work.
I use this "dirty" workaround:
>>> original_name="AC_DC - Shot Down In Flames (Official Video)-UKwVvSleM6w.mp3"
>>> new_name=original_name[:-16]+".mp3"
>>> new_name
'AC_DC - Shot Down In Flames (Official Video).mp3'
Edit:
If you really, REALLY want to find the "-XXXX"-portion, have a look at str.rfind(). This will help you to find the index of the last dash (-), which you can directly use for the slice notation of the string.
Disclaimer:
This will provide wrong results, if the video id contains a dash, e.g. here: https://www.youtube.com/watch?v=7WVBEB8-wa0
Then you will find the last dash, remove -wa0 and be left with -7WVBEB8 at the end of the filename.
Using idea of the above answer, one can also take into account that a normal word does not
contain more than one capital character.
def youtube_name_fix(folder):
import os
from pathlib import Path
import re
REGEX = re.compile(r'[A-Z]')
for name in os.listdir(folder):
basename = Path(name)
last_12 = basename.stem[-12:]
# check if the end string is not all uppercase (then it could be part of a valid name)
if not last_12.isupper():
# check if the last string has more than one uppercase letters
if len(REGEX.findall(last_12)) > 1:
# remove the end youtube string and create new full path
new_name = os.path.join(folder, basename.stem[:-12] + basename.suffix)
try:
os.rename(os.path.join(folder,name), new_name)
except Exception as e:
print(e)
> youtube_name_fix(p)
old name -> "4-Discrete and Continuous Probability Models-esHwigpYggU.mp4"
new name -> "4-Discrete and Continuous Probability Models.mp4"
Problem:
Hello, I have been struggling recently in my programming endeavours. I have managed to receive the output below from Google Speech to Text, but I cannot figure out how draw data from this block.
Excerpt 1:
[VoiceMain]: Successfully initialized
{"result":[]}
{"result":[{"alternative":[{"transcript":"hello","confidence":0.46152416},{"transcript":"how low"},{"transcript":"how lo"},{"transcript":"how long"},{"transcript":"Polo"}],"final":true}],"result_index":0}
[VoiceMain]: Successfully initialized
{"result":[]}
{"result":[{"alternative":[{"transcript":"hello"},{"transcript":"how long"},{"transcript":"how low"},{"transcript":"howlong"}],"final":true}],"result_index":0}
Objective:
My goal is to extract the string "hello" (without the quotation marks) from the first transcript of each block and set it equal to a variable. The problem arises when I do not know what the phrase will be. Instead of "hello", the phrase may be a string of any length. Even if it is a different string, I would still like to set it to the same variable to which the phrase "hello" would have been set to.
Furthermore, I would like to extract the number after the word "confidence". In this case, it is 0.46152416. Data type does not matter for the confidence variable. The confidence variable appears to be more difficult to extract from the blocks because it may or may not be present. If it is not present, it must be ignored. If it is present however, it must be detected and stored as a variable.
Also please note that this text block is stored within a file named "CurlOutput.txt".
All help or advice related to solving this problem is greatly appreciated.
You could do this with regex, but then I am assuming you will want to use this as a dict later in your code. So here is a python approach to building this result as a dictionary.
import json
with open('CurlOutput.txt') as f:
lines = f.read().splitlines()
flag = '{"result":[]} '
for line in lines: # Loop through each lin in file
if flag in line: # check if this is a line with data on it
results = json.loads(line.replace(flag, ''))['result'] # Load data as a dict
# If you just want to change first index of alternative
# results[0]['alternative'][0]['transcript'] = 'myNewString'
# If you want to check all alternative for confidence and transcript
for result in results[0]['alternative']: # Loop over each alternative
transcript = result['transcript']
confidence = None
if 'confidence' in result:
confidence = result['confidence']
# now do whatever you want with confidence and transcript.