I'm trying to find a better way to remove value pairs of an object that contain an empty string ""
my current state is:
this.state = {
searchParams:{
query: '',
colors: [],
text: '',
legalities: '',
setName: '',
pageSize: 4
}
}
I know this won't work with my state since it isn't an array, but something like this is what i'm trying to achieve right now
var search = this.state.searchParams.filter(function (el) {
return el !== "";
});
could anyone point me in the right direction and explain a better way to do this with an object, thanks :) ?
filter only use for a array, not is a object.
You can try my code
let searchParams =
Object.keys(this.state.searchParams)
.filter( key => this.state.searchParams[key] !== '' );
this.setState({searchParams })
You can use Object.entries and Object.fromEntries.
const filteredObject = Object.fromEntries(
Object.entries(searchParams)
.filter(([key, value]) => value !== "")
);
Will create anew object with all the keys for which the value was "" removed.
You can filter it this way with reduce method. Since it is an object, you have to combine object prototype .keys with array prototype .reduce to filter it.
const searchParams = {
query: '',
colors: [],
text: '',
legalities: '',
setName: '',
pageSize: 4
}
const notEmpty = Object.keys(searchParams).reduce((nonEmptyObj, currentKey) => {
if (searchParams[currentKey] !== '') {
nonEmptyObj[currentKey] = searchParams[currentKey];
}
return nonEmptyObj;
}, {})
console.log(notEmpty);
use Object.keys. In your case like this:
var search = Object.keys(this.state.searchParams).filter(el => {
// do something
})
the most simple way is by using Object.keys method and then iterate the whole object. then check if searchParams[ele] is true and add in another object.
var newObj = {};
Object.keys(this.state.searchParams).forEach(ele => {
if (searchParams[ele]) {
newObj = { ...newObj, [ele]: searchParams[ele] };
}
});
console.log(newObj); // new object generated with empty values eliminated
this.setState({searchParams:newObj})
If you want to filter out empty strings and strings (with white spaces only) as well, then
we have trim the string and then check its length. If its string and its length is 0 after trimming, then its considered as empty and will be filtered out.
const params = this.state.searchParams
Object.keys(this.state.searchParams).filter(key =>
!(typeof params[key] === 'string' && params[key].trim().length === 0)
)
If you don't want to trim, then:
const params = this.state.searchParams
Object.keys(this.state.searchParams).filter(key => params[key] !== '')
I would highly suggest you to not to use semicolon, as it takes space and JS can now ignore semicolon as well. Also, not to use double quotes unless required.
Related
this.crudService.get('user.php?mode=test')
.subscribe((data:any) => {
{ for (var key in data) { this[key] = data[key]; } };
}
);
This use to work on angular 7 now on angular 13 i get this error (look image)
In template i was using the values for example in json string was and array and i had users, in template was {{users}} , {{posts}} etc.. now the this[key] give error , please help me out its very important can't find solution
i'll show an example code, and then applied to your code:
Example
// creating global variables to receive the values
users: any = null;
posts: any = null;
// simulating the data you will receive
data: any[] = [
{users: ['user1', 'user2', 'user3']},
{posts: ['post1', 'post2', 'post3']}
];
getCrudService() {
// access each object of the array
this.data.forEach(obj => {
// getting keys name and doing something with it
Object.keys(obj).forEach(key => {
// accessing global variable and setting array value by key name
this[String(key)] = obj[String(key)]
})
})
}
Apllied to your code
this.crudService.get('user.php?mode=test').subscribe((data:any) => {
data.forEach(obj => {
Object.keys(obj).forEach(key => {
this[String(key)] = obj[String(key)]
});
});
});
I hope it helped you, if you need help, just reply me.
I'm new to JS and trying to figure out how to iterate through a json array and return only a subset of elements. Specifically I would like to know how to return only the 'first_name' and 'last_name' from the Mock data in the attached code snippet. It seems like it should be straightforward but I'm scratching my head.
let people = [{"id":1,"first_name":"Talbert","last_name":"Kohnert","email":"tkohnert0#wisc.edu","country":"Indonesia"},
{"id":2,"first_name":"Ruthie","last_name":"McKleod","email":"rmckleod1#gizmodo.com","country":"Sweden"},
{"id":3,"first_name":"Lenore","last_name":"Foister","email":"lfoister2#epa.gov","country":"Nicaragua"}]
people.forEach(person => {
for (let key in person) {
console.log(`${key} => ${person[key]}`);
}
Use the element names
people.forEach(person => {
console.log(JSON.stringify(person) + "\n");
console.log(person["first_name"], person["last_name"], "\n");
});
Produces this output:
{"id":1,"first_name":"Talbert","last_name":"Kohnert","email":"tkohnert0#wisc.edu","country":"Indonesia"}
Talbert Kohnert
{"id":2,"first_name":"Ruthie","last_name":"McKleod","email":"rmckleod1#gizmodo.com","country":"Sweden"}
Ruthie McKleod
{"id":3,"first_name":"Lenore","last_name":"Foister","email":"lfoister2#epa.gov","country":"Nicaragua"}
Lenore Foister
You can try Object destructuring assignment of ES6 to achieve the requirement.
Working Demo :
let people = [{"id":1,"first_name":"Talbert","last_name":"Kohnert","email":"tkohnert0#wisc.edu","country":"Indonesia"},
{"id":2,"first_name":"Ruthie","last_name":"McKleod","email":"rmckleod1#gizmodo.com","country":"Sweden"},
{"id":3,"first_name":"Lenore","last_name":"Foister","email":"lfoister2#epa.gov","country":"Nicaragua"}];
let res = people.map(({first_name, last_name}) => first_name + ' ' + last_name);
console.log(res);
There are numerous way of achieving this output. One of most frequently used method is using map() of es6.
let people = [{"id":1,"first_name":"Talbert","last_name":"Kohnert","email":"tkohnert0#wisc.edu","country":"Indonesia"},
{"id":2,"first_name":"Ruthie","last_name":"McKleod","email":"rmckleod1#gizmodo.com","country":"Sweden"},
{"id":3,"first_name":"Lenore","last_name":"Foister","email":"lfoister2#epa.gov","country":"Nicaragua"}]
//by map method
people.map((person,index)=>{
console.log(`${person.first_name} ${person.last_name}`)
})
// by forEach
people.forEach(person => {
console.log(`${person.first_name} ${person.last_name}`)
}
you can achieve this by using the map function.
map lets you iterate over each item in the array and return a new value for each iteration while returning a new array, so for your case:
let people = [
{"id":1,"first_name":"Talbert","last_name":"Kohnert","email":"tkohnert0#wisc.edu","country":"Indonesia"},
{"id":2,"first_name":"Ruthie","last_name":"McKleod","email":"rmckleod1#gizmodo.com","country":"Sweden"},
{"id":3,"first_name":"Lenore","last_name":"Foister","email":"lfoister2#epa.gov","country":"Nicaragua"}
]
const newArray = people.map((person) => {
return {
first_name: person.first_name,
last_name: person.last_name
}
})
console.log(newArray)
here you get a new array with just the properties you need.
I am trying to figure out how to do this but can't seem to wrap my head around it..
I have an address object
const obj = {
"address_type":"Home",
"country":"US",
"addressLine1":"123 Any Street",
"addressLine2":"",
"city":"Any Town",
"state":"Indiana",
"state_code":"IN",
"zip":"46220-4466",
"phone":"6715551313",
"mobile_number":"",
"extn":"",
"fax":"",
"county_name":"MyCounty"
}
I want to check for any key that has a value but only specific keys
const objProps = ["addressLine1","addressLine2","city","state_code","zip","county_name"];
I want to check all keys in objProps against my address object and if any one of them contains a value return true (doesn't matter if its 1 or all 6).. If all keys don't contain a value then return false (Sometimes I will get an address object that has all null values)
I've tried various ways to accomplish this but have failed in each one.
The variation I am working on now is using reduce. While it doesn't meet my needs I thought I could check the resulting array and if length was greater than 0 than I have my answer..
Work-in-progress:
function hasAddressData(obj: any) {
const objProps = ["addressLine1","addressLine2","city","state_code","zip","county_name"];
const keysWithData = objProps.reduce((accumulator, key) => {
const propExistsOnObj = obj.hasOwnProperty(key);
let keyHasData = [];
if (obj[key].length > 0 ) {
keyHasData = obj[key]
}
if (!propExistsOnObj) {
accumulator.push(key);
} else if (keyHasData) {
const equalValueKeyIndex = accumulator.indexOf(key);
accumulator.splice(equalValueKeyIndex, 1);
}
return accumulator;
});
return keysWithData;
}
The above is messed up I know and doesn't work.. Just learning this stuff.. anyone have a suggestion or comment?
Check that .some of the objProps, when looked up on the obj, contain a value. (Either with Boolean or by comparing against '')
const obj = {
"address_type":"Home",
"country":"US",
"addressLine1":"123 Any Street",
"addressLine2":"",
"city":"Any Town",
"state":"Indiana",
"state_code":"IN",
"zip":"46220-4466",
"phone":"6715551313",
"mobile_number":"",
"extn":"",
"fax":"",
"county_name":"MyCounty"
}
const objProps = ["addressLine1","addressLine2","city","state_code","zip","county_name"];
const somePopulated = objProps.some(prop => obj[prop]);
// or prop => obj[prop] !== ''
console.log(somePopulated);
const obj = {
"address_type":"Home",
"country":"US",
"addressLine1":"",
"addressLine2":"",
"city":"",
"state":"Indiana",
"state_code":"",
"zip":"",
"phone":"6715551313",
"mobile_number":"",
"extn":"",
"fax":"",
"county_name":""
}
const objProps = ["addressLine1","addressLine2","city","state_code","zip","county_name"];
const somePopulated = objProps.some(prop => obj[prop]);
// or prop => obj[prop] !== ''
console.log(somePopulated);
function checkKeys(target, props) {
return props.some((prop) => {
return target.hasOwnProperty(prop) && target[prop];
});
}
Explanation: some iterates through the props you want to check, returning true immediately when one is found (i.e. the callback returns true). If no props are found (i.e. no callback returns true), some returns false.
hasOwnProperty ensures that you are only checking properties on target, and not looking up the prototype chain. target[prop] checks for a truthy value. You may need to modify this last check if you're going to be handling values other than strings.
Hello I am trying to map through an array of objects and push them to a new array.
My ISSUE : only the last item of the object is being pushed to the new array
I believe this has to do with React life cycle methods but I don't know where I should I loop and push the values to the array to get the full list
//My object in an array named states
var states = [{"_id":"Virginia","name":"Virginia","abbreviation":"VN","__v":0},{"_id":"North Carolina","name":"North Carolina","abbreviation":"NC","__v":0},{"_id":"California","name":"California","abbreviation":"CA","__v":0}];
export function StateSelect()
{
**EDIT 1**
const options = [];
function getStates()
{
//This is how I am looping through it and adding to an array
{ states.length > 0 &&
states.map(item =>
(
console.log(`ITEM: ${JSON.stringify(item)}`),
options.push([{ value: `${item.name}`, label: `${item.name}`}])
))
}
}
return( {getStates()}: );
}
Thank you
It looks like your getStates() might not even be returning anything... but assuming it is, I believe you should be able to accomplish this using a forEach() fn in order to push values into your options array... Try adding the following into your map:
states.map((item) => {
console.log(`ITEM: ${JSON.stringify(item)}`);
let processed = 0;
item.forEach((i) => {
options.push([{ value: `${i.name}`, label: `${i.name}`}]);
processed++;
if(processed === item.length) {
// callback fn, or return
}
}
.map usually used to return another result, you could just use .forEach
In fact, you don't really need to declare options at all, just use .map on state to return the result would be fine.
return states.length > 0 && states.map(({ name }) => {
return { value: name, label: name };
});
Hello guys i am trying to clear my ng-model when i fire my change function but my problem that i don't want to delete all i want to exclude one item in the object.
function change() {
if (vm.location.type) {
angular.forEach(vm.location, function (value, index) {
delete vm.location;
});
}
}
so i don't want to delete the
vm.location.type
my
vm.location
has
vm.location.boundaries;
vm.location.region;
vm.location.address;
vm.location.name;
vm.location.nonVisitingRadius;
vm.location.visitingRadius;
See the code below,
var obj = { a:123, b:123, c:123 }
delete obj.a;
Hence obj will be like this {b:123, c:123}
Note: Dont need any for loop to delete property from object
Updated Answer:
var obj= {
a: 'aaa',
b: 'bbb',
c: 'ccc',
d: 'ddd'
};
var removeObj = function(obj, props) {
for(var i = 0; i < props.length; i++) {
if(obj.hasOwnProperty(props[i])) {
delete obj[props[i]];
}
}
};
removeObj (obj, ["a", "d"]);
i don't know if i understand correctly what you're asking, but if you want to clear all the fields of your object preserving only type and preserving the reference of the object with plain javascirpt (no libraries), loop over the fields and check if the i field is equal to type.
for(var i in model.location){
if(i !== 'type')
delete model[i];
}
with underscore.js you could define a default model like:
var defaultModel = {
location: {
region: '',
address: '',
name: '',
nonVisitingRadius: '',
visitingRadius: '',
type: 'defaultvalue'
}
}
and when ng-change is triggered inside the function
_.extend(model, defaultModel);
that will keep the default value for type and clear all the others.
You can do it this with a temporary object :
let tempLocation = {};
tempLocation.type = $scope.location.type;
$scope.location = tempLocation;