I have two tables, the first one is dbo.formula
Id | Poste | Calculation | Montant
---+--------+-------------+--------
1 | Achats | 3801%+381% | .....
2 | Tva | 446%-445% | ....
3 | Tiers | 411%+401% | ....
The second table is dbo.value
Compte | Solde
--------+-------
380000 | 400.00
380100 | 500.00
381100 | 200.00
381200 | 100.00
4456600 | 100.00
4455400 | 150.00
I need to be the result in the first table in field Montant like
800.00
50.00
I tried a request but it changes only the 3 beginning compute.
Join the tables on your conditions and aggregate:
select f.ID, f.Poste, sum(v.Solde) total
from formula f inner join value v
on charindex('+' + left(v.Compte, 3) + '%', '+' + f.Calculation) > 0
group by f.ID, f.Poste
See the demo.
Results:
> ID | Poste | total
> -: | :----- | :------
> 1 | Achats | 1200.00
> 2 | Tva | 250.00
Related
I have 2 tables, with the same exact fields and fields names. i am trying to inner join them but im having some difficulty determining how i can get my results in my desired format.
I know i can do select a.customer, a.id, a.date, a.line, a.product, b.customer, b.id, b.date, b.line, b.product but instead of having my A data and B data on the same row, id like for them to be on seperate rows.
I have 2 tables, with the same exact fields and fields names, i am trying to inner join them so that unique line becomes a row.
Table A:
|customer| id | Date | line | Product|
|--------|-----|---------|------|--------|
| 445678 | 123 | 1/1/22 | 10 | 88975 |
| 853652 | 456 | 1/10/22 | 5 | 55876 |
| 845689 | 789 | 1/25/22 | 1 | 45587 |
TABLE B:
|customer| id | Date | line | Product|
|--------|-----|---------|------|--------|
| 445678 | 489 | 1/1/22 | 1 | 87574 |
| 853652 | 853 | 1/10/22 | 12 | 45678 |
| 587435 | 157 | 2/12/22 | 3 | 25896 |
DESIRED RESULTS:
|customer| id | Date | line | Product|
|--------|-----|---------|------|--------|
| 445678 | 123 | 1/1/22 | 10 | 88975 |
| 445678 | 489 | 1/1/22 | 1 | 87574 |
| 853652 | 456 | 1/10/22 | 5 | 55876 |
| 853652 | 853 | 1/10/22 | 12 | 45678 |
my query:
select a.customer, a.id, a.date, a.line, a.product
from data1 a
inner join data2 b
on a.date = b.date
and a.customer = b.customer
Let's say I have the following table (data is completely fiction):
ID | MonthDate | PersonID | Name | Status | MonthsAgoSinceLastCheck
1 | 2017-12 | 900 | Jack | Ill | -
2 | 2018-01 | 900 | Jack | Ill | 1
3 | 2018-02 | 900 | Jack | Ill | 2
4 | 2018-03 | 900 | Jack | Healthy | 1
5 | 2017-02 | 901 | Bill | Ill | -
6 | 2017-03 | 901 | Bill | Ill | 1
7 | 2017-05 | 901 | Bill | Healthy | 1
For each record, I would like to see the previous status that person had X months ago since last check (column MonthsAgoSinceLastCheck). Notice that MonthDate can skip months.
So in this case, the result would be
ID | MonthDate | PersonID | Name | Status | MonthsAgoSinceLastCheck | PreviousSatus
1 | 2017-12 | 900 | Jack | Ill | - | -
2 | 2018-01 | 900 | Jack | Ill | 1 | Ill
3 | 2018-02 | 900 | Jack | Ill | 2 | Ill
4 | 2018-03 | 900 | Jack | Healthy | 1 | Ill
5 | 2017-02 | 901 | Bill | Healthy | - | -
6 | 2017-03 | 901 | Bill | Healthy | 1 | Healthy
7 | 2017-05 | 901 | Bill | Ill | 2 | Healthy
Any sugestions/tips? I tried to do this with CTE's and self-joins but failed on both.
It's way easier to use full dates than year and months separately. The first thing you should do is generate a full date from your year + month. Then just self join with previous month, depending on the last check.
;WITH DataWithDates AS
(
SELECT
T.ID,
MonthDate = CONVERT(DATE, T.MonthDate + '-01'),
T.PersonID,
T.Name,
T.Status,
T.MonthsAgoSinceLastCheck
FROM
YourTable AS T
)
SELECT
D.ID,
D.MonthDate,
D.PersonID,
D.Name,
D.Status,
D.MonthsAgoSinceLastCheck,
PreviousStatus = N.Status
FROM
DataWithDates AS D
LEFT JOIN DataWithDates AS N ON
D.PersonID = N.PersonID AND
N.MonthDate = DATEADD(MONTH, -1 * D.MonthsAgoSinceLastCheck, D.MonthDate)
I'm assuming your MonthDate has values for all rows, otherwise the conversion will fail. I'm also assuming that your - values for MonthsAgoSinceLastCheck are actually NULL.
try this:
select *,LAG(Status) OVER(Partition by Name Order by MonthDate,Id) AS PreviousSatus
from tab1
order by id
SQl Fiddle:http://sqlfiddle.com/#!18/04407/4
I have a table with a data as bellow :
+--------+----------+-------+------------+--------------+
| month | code | type | date | PersonID |
+--------+----------+-------+------------+--------------+
| 201501 | 178954 | 3 | 2014-12-3 | 10 |
| 201501 | 178954 | 3 | 2014-12-3 | 10 |
| 201501 | 178955 | 2 | 2014-12-13 | 10 |
| 201501 | 178955 | 2 | 2014-12-13 | 10 |
| 201501 | 178956 | 2 | 2014-12-11 | 10 |
| 201501 | 178958 | 1 | 2014-12-10 | 10 |
| 201501 | 178959 | 2 | 2014-12-12 | 15 |
| 201501 | 178959 | 2 | 2014-12-12 | 15 |
| 201501 | 178954 | 1 | 2014-12-11 | 13 |
| 201501 | 178954 | 1 | 2014-12-11 | 13 |
+--------+----------+-------+------------+--------------+
In my first 6 lines i have the same PersonID in the same Month What i want if i have the same personID in the same Month i want to select the person who have the type is 2 with the recent date in my case the output will be like as bellow:
+--------+--------+------+------------+----------+
| month | code | type| date | PersonID |
+--------+--------+------+------------+----------+
| 201501 | 178955 | 2 | 2014-12-13 | 10 |
| 201501 | 178959 | 2 | 2014-12-12 | 15 |
| 201501 | 178954 | 2 | 2014-12-11 | 13 |
+--------+--------+------+------------+----------+
Also if they are some duplicate rows i don't want to display it
They are any solution to that ?
Simply use GROUP BY:
https://msdn.microsoft.com/de-de/library/ms177673(v=sql.120).aspx
SELECT mont, code, ... FROM tabelname GROUP BY PersonID, date, ...
Note that you have to specifiy all columns in the group by.
SELECT DISTINCT A.month, A.code, A.type, B.date, B.PersonID FROM YourTable A
INNER JOIN (SELECT PersonID, MAX(date) as date FROM YourTable
GROUP BY PersonID) B
ON (A.PersonID = B.PersonID
AND A.date = B.date)
WHERE A.type = 2 ORDER BY B.date DESC, A.PersonID
Just in case you/others are still wondering.
ID | NAME | AGE | ADDRESS | SALARY |
+----+----------+-----+-----------+----------+
| 1 | Ramesh | 32 | Ahmedabad | 2000.00 |
| 2 | Khilan | 25 | Delhi | 1500.00 |
| 3 | kaushik | 23 | Kota | 2000.00 |
| 4 | Chaitali | 25 | Mumbai | 6500.00 |
| 5 | Hardik | 27 | Bhopal | 8500.00 |
| 6 | Komal | 22 | MP | 4500.00 |
| 7 | Muffy | 24 | Indore | 10000.00
I want to show result below using ms sql server
SALARY
-------------------
0 - 1500 (1)
1500 - 3000(2)
3000 - 4500(1)
4500-6000(0)
6000-7500(0)
7500 - 9000(1)
9000-10500(1)
This is something of a pain, because you want the 0 counts. Here is one method:
with ranges as (
select 0 as low, 1500 as high union all
select 1500, 3000 union all
select 3000, 4500 union all
. . .
)
select r.low, r.high, count(t.salary)
from ranges r left join
t
on t.salary >= r.low and
t.salary < r.high
group by r.low, r.high
order by r.low;
If you really want, you can use string manipulations to put the range as a single character column. In general, I prefer to have them as two separate columns.
I have a table that holds values for particular months:
| MFG | DATE | FACTOR |
-----------------------------
| 1 | 2013-01-01 | 1 |
| 2 | 2013-01-01 | 0.8 |
| 2 | 2013-02-01 | 1 |
| 2 | 2013-12-01 | 1.55 |
| 3 | 2013-01-01 | 1 |
| 3 | 2013-04-01 | 1.3 |
| 3 | 2013-05-01 | 1.2 |
| 3 | 2013-06-01 | 1.1 |
| 3 | 2013-07-01 | 1 |
| 4 | 2013-01-01 | 0.9 |
| 4 | 2013-02-01 | 1 |
| 4 | 2013-12-01 | 1.8 |
| 5 | 2013-01-01 | 1.4 |
| 5 | 2013-02-01 | 1 |
| 5 | 2013-10-01 | 1.3 |
| 5 | 2013-11-01 | 1.2 |
| 5 | 2013-12-01 | 1.5 |
What I would like to do is pivot these using a calendar table (already defined):
And finally, cascade the NULL columns to use the previous value.
What I've got so far is a query that will populate the NULLs with the last value for mfg = 3. Each mfg will always have a value for the first of the year. My question is; how do I pivot this and extend to all mfg?
SELECT c.[date],
f.[factor],
Isnull(f.[factor], (SELECT TOP 1 factor
FROM factors
WHERE [date] < c.[date]
AND [factor] IS NOT NULL
AND mfg = 3
ORDER BY [date] DESC)) AS xFactor
FROM (SELECT [date]
FROM calendar
WHERE Datepart(yy, [date]) = 2013
AND Datepart(d, [date]) = 1) c
LEFT JOIN (SELECT [date],
[factor]
FROM factors
WHERE mfg = 3) f
ON f.[date] = c.[date]
Result
| DATE | FACTOR | XFACTOR |
---------------------------------
| 2013-01-01 | 1 | 1 |
| 2013-02-01 | (null) | 1 |
| 2013-03-01 | (null) | 1 |
| 2013-04-01 | 1.3 | 1.3 |
| 2013-05-01 | 1.2 | 1.2 |
| 2013-06-01 | 1.1 | 1.1 |
| 2013-07-01 | 1 | 1 |
| 2013-08-01 | (null) | 1 |
| 2013-09-01 | (null) | 1 |
| 2013-10-01 | (null) | 1 |
| 2013-11-01 | (null) | 1 |
| 2013-12-01 | (null) | 1 |
SQL Fiddle
Don't know if you need the dates to be dynamic from the calender table or if mfg can be more than 5 but this should give you some ideas.
select *
from (
select c.date,
t.mfg,
(
select top 1 f.factor
from factors as f
where f.date <= c.date and
f.mfg = t.mfg and
f.factor is not null
order by f.date desc
) as factor
from calendar as c
cross apply(values(1),(2),(3),(4),(5)) as t(mfg)
) as t
pivot (
max(t.factor) for t.date in ([20130101], [20130201], [20130301],
[20130401], [20130501], [20130601],
[20130701], [20130801], [20130901],
[20131001], [20131101], [20131201])
) as P
SQL Fiddle