Snowflake has the simply function Quarter(timestamp()) which returns current quarter, but wondering how to do day of QTR , all tutorials reference Postgres/ sql server.
Goal - create a date table, and show what day of the quarter it is for the next 20 years.
SELECT column1::timestamp as d,
DATE_TRUNC('QUARTER',d) as q,
DATEDIFF('day',q, d) as doq
FROM VALUES ('2019-10-30'),('2019-10-01');
gives 0 for the first day of the quarter, so if you need that to be 1 you can +1 that datadiff.
D Q DOQ
2019-10-30 00:00:00.000 2019-10-01 00:00:00.000 29
2019-10-01 00:00:00.000 2019-10-01 00:00:00.000 0
[Edit:] After re-reading your goal of a 20 year table, here is some code I have used in snowflake in the past to just that:
CREATE OR REPLACE TABLE twenty_years_of_days(date) AS
SELECT DATEADD(day, rn, CURRENT_DATE) as date,
DATE_TRUNC('QUARTER',date) as quarter,
DATEDIFF('day',quarter, date) as doq
FROM (
SELECT row_number() over(order by 1) as rn
FROM TABLE(GENERATOR(rowCount => 365*20)) v
);
Related
I have some sample donation history:
ID TransactionDate Amount
10 2001-12-19 00:00:00.000 75.00
10 2001-07-11 00:00:00.000 760.00
10 2010-10-15 00:00:00.000 2200.00
10 2012-08-15 00:00:00.000 1220.00
10 2013-09-16 00:00:00.000 610.00
100 2000-09-26 00:00:00.000 3000.00
100 1999-01-01 00:00:00.000 5000.00
I am trying to get a summary of giving by year by donor. The total does not have to be for consecutive years, but will just total overall # of years given. The total does not need to equal the number of transactions per year, just that the ID donated in that particular year.
For instance, ID 10 above would equal 4 indicating giving in 4 calendar years (2 donations in 2001, 1 in 2010, 1 in 2012, and 1 in 2013). ID 100 would equal 2.
The donations date back many years, so hard-coding dates is not very feasible.
Any ideas are appreciated.
Try this:
SELECT ID, DATEPART(yy,TransactionDate) Year, COUNT(*)
FROM tableName
GROUP BY ID, DATEPART(yy,TransactionDate)
You just need to return and then group on the relevant parts of your data, which is the ID and the year of the TransactionDate:
select d.ID
,count(1) as DonationYears
from(select distinct ID -- Sub query returns one row per ID and Year, which is counted up by ID in the outer query
,year(TransactionDate) as TranYear
from Donations
) d
group by d.ID
Can you help out with a problem
I have table price table which has daily prices starting 31st Dec 2010 till todays date.The table contains daily prices
2009-12-31 00:00:00.000 1.0020945351
2010-01-01 00:00:00.000 1.0021009300
2010-01-04 00:00:00.000 1.0021910181
2010-01-05 00:00:00.000 1.0022005986
2010-01-06 00:00:00.000 1.0022428696
2010-01-07 00:00:00.000 1.0022647147
2010-01-08 00:00:00.000 1.0022842726
2010-01-11 00:00:00.000 1.0023374302
2010-01-12 00:00:00.000 1.0023465374
2010-01-13 00:00:00.000 1.0023638081
2010-01-14 00:00:00.000 1.0023856533
2010-01-00 00:00:00.000 1.0024083955
2010-01-18 00:00:00.000 1.0024779677
2010-01-19 00:00:00.000 1.0025020553
2010-01-20 00:00:00.000 1.002521135
2010-01-21 00:00:00.000 1.0025420688
2010-01-22 00:00:00.000 1.0025593397
2010-01-25 00:00:00.000 1.0026180146
2010-01-26 00:00:00.000 1.002637573
2010-01-27 00:00:00.000 1.0026648447
2010-01-28 00:00:00.000 1.0026957934
2010-01-29 00:00:00.000 1.0027267421
2010-02-01 00:00:00.000 1.0028195885
2010-02-02 00:00:00.000 1.0028573523
2010-02-03 00:00:00.000 1.0028964611
2010-02-04 00:00:00.000 1.00293557
2010-02-05 00:00:00.000 1.002973334
2010-02-08 00:00:00.000 1.0030879717
2010-02-09 00:00:00.000 1.0031279777
2010-02-10 00:00:00.000 1.003171166
2010-02-11 00:00:00.000 1.0032007452
2010-02-12 00:00:00.000 1.0032575895
2010-02-00 00:00:00.000 1.0033749191
2010-02-1 00:00:00.000 1.0034140292
2010-02-17 00:00:00.000 1.003452691
2010-02-18 00:00:00.000 1.0034918013
2010-02-19 00:00:00.000 1.0035395633
2010-02-22 00:00:00.000 1.0036664439
2010-02-23 00:00:00.000 1.0037042097
2010-02-24 00:00:00.000 1.0037510759
2010-02-25 00:00:00.000 1.0038001834
2010-02-26 00:00:00.000 1.003850077
I need to write a query to get index based on
(Last day of current month/Previous month last day) - 1 * 100.So that output comes something like this
31-Jan-10 0.01%
28-Feb-10 0.02%
31-Mar-10 0.00%
Following is one of the solution I thought about however please share best ideas to implement this problem
Extract last day of all the months with values into a temp table and then order by dates so that they subtract and put the values into another temp table
Looking forward to your help.
Try this....
DECLARE #StartDate DATETIME = '2010-01-01',
#EndDate DATETIME = GETDATE();
WITH data AS (
SELECT 1 AS i, CONVERT(DATETIME, NULL) AS StartDate, DATEADD(MONTH, 0, #StartDate) - 1 AS EndDate
UNION ALL
SELECT i + 1, data.EndDate, DATEADD(MONTH, i, #StartDate) - 1 AS EndDate
FROM data
WHERE DATEADD(MONTH, i, #StartDate) - 1 < #EndDate
)
SELECT (
((SELECT TOP 1 Rate FROM RateTable WHERE Date <= data.EndDate ORDER BY Date DESC) /
(SELECT TOP 1 Rate FROM RateTable WHERE Date <= data.StartDate ORDER BY Date DESC)- 1) * 100)
FROM DATA -- parenthesis were causing issues
WHERE data.StartDate IS NOT NULL
OPTION (MAXRECURSION 10000);
You'll need to replace the
(SELECT Rate FROM RateTable WHERE Date = data.StartDate)
and
(SELECT Rate FROM RateTable WHERE Date = data.EndDate)
With the values for your rate table. as you didn't mention column and table names in your question.
rwking indicated that there might be gaps in the rates table that would cause issues.
I've modified the subquery to bring back the first rate on or nearest the start and end dates.
Hope that helps
You can use the LAG function introduced in SQL2012 to make it a bit easier:
WITH DataWithOrder AS
(
SELECT DateField, PriceField,
ROW_NUMBER() OVER(PARTITION BY YEAR(DateField), Month(DateField) ORDER BY DateField DESC) AS Pos
FROM PriceTable
)
SELECT
DateField,
PriceField,
LAG(PriceField) OVER(ORDER BY DateField) AS PriceLastMonth,
((PriceField / LAG(PriceField) OVER(ORDER BY DateField)) - 1) * 100 AS PCIncrease
FROM DataWithOrder
WHERE Pos = 1
ORDER BY DateField
I took a very different approach than the other guy. His is more elegant and would work better if the daily data does represent every single day of every month. If there are gaps in days, however, as your sample data represents, you can try the following code.
with cte as (select mydate
, price
, ROW_NUMBER() over(partition by YEAR(mydate), MONTH(mydate)
order by day(mydate) desc) row_n
from #temp)
select mydate, price, ROW_NUMBER() over(order by mydate desc) row_num
into #temp2
from cte
where row_n = 1
alter table #temp2
add idx float
declare #counter int = 1
while #counter < (select MAX(row_num)+1 from #temp2)
begin
update t2
set t2.idx = ((t2.price/t3.price)-1)*100
from #temp2 t2 left join
#temp2 t3 on 1 = 1
where t2.row_num = #counter and t3.row_num = #counter + 1
set #counter = #counter + 1
end
select mydate, idx
from #temp2
As the other poster mentioned, you didn't provide column or table names. My process was to insert your data into a table called [#temp] with column names [mydate] and [price].
Also, the data sample you provided contains two invalid dates that I changed to arbitrary dates just for the purposes of getting code to run. (2010-01-00 and 2010-02-00)
I have a table of data similar to below where I need to calculate the sum of all the paused time up until today. The columns can have any date in them, so PauseStart can be a future date , and PauseEnd can also be a future date. A Null date (20991231) is considered open ended, i.e. no end date to the pause was selected.
NB : Dates are UK date format
The data
PauseID RecID PauseStart PauseEnd
1022 10 2013-01-04 15:52:04.320 2013-01-21 00:00:00.000
1023 10 2013-01-01 00:00:00.000 2013-01-02 00:00:00.000
1024 10 2013-01-05 00:00:00.000 2099-01-01 00:00:00.000
The data above shows that we had a pause between 1/1/2013 and 2/1/2013, a pause between 4/1/2013 and 21/1/2013 (which should register in the sum as 4/1/2013 to 7/1/2013 11:00:00) and 5/1/2013 -> open (which should register in the sum as 5/1/2013 to 7/1/2013 11:00:00)
The columns are not indexed.
The TSQL which I have come up with looks like this
SELECT
SUM (
CASE
WHEN NULLIF(PauseEnd,'20991231') IS NULL THEN
DATEDIFF(mi, PauseStart, ISNULL(NULLIF(PauseEnd,'20991231'), GetDate()))
WHEN PauseEnd > GetDate() THEN
DATEDIFF(mi, PauseStart, GetDate())
ELSE
DATEDIFF(mi, PauseStart, ISNULL(NULLIF(PauseEnd,'20991231'), GetDate()))
END
) AS Datedifference
FROM Pauses
WHERE Pauses.RecID = 10
AND PauseStart < GetDate()
This gives me the results
4021
1440
3533
which seem correct, however my question remains,
Is this the most efficient way of achieving this result?
addendum, this table could start holding millions of records, so I'd like to make the tsql that calculates the sum efficient in the first instance.
I would do it like this:
SELECT
PauseStart,
DATEDIFF(mi, PauseStart, CASE WHEN PauseEnd > GetDate() THEN GetDate() ELSE PauseEnd END) as Datedifference
FROM Pauses
WHERE Pauses.RecID = 10 AND PauseStart < GetDate()
I have a sql query that is grouping rows by calendar week
select count(*),datepart(wk,mydate)
from MyTable
where mydate between '12/26/2010' and '1/8/2011'
group by datepart(wk,mydate)
The date range is two weeks but three rows come back because Jan 1 is a saturday and is the only day in the range that DATEPART returns a 1 the other dates return 53 or 2.
I want jan 1 to be grouped with the dates that return a 53, but I want it to be a generic answer not something like CASE WHEN datepart(wk,mydate) = 53 then 1 else datepart(wk,mydate) end because that will work for that specific date range not for other years.
I'm just wondering what a good solution would be
thanks in advance.
We use to choose as week of a date, the week of his last sunday (first day of the week in SQL). So, for each date, you can ask for the week of his last sunday with the following query:
select count(*),datepart(wk,mydate-DATEPART(dw,mydate)+1)
from MyTable
where mydate between '12/26/2010' and '1/8/2011'
group by datepart(wk,mydate-DATEPART(dw,mydate)+1)
Perhaps you can use iso_week instead of wk.
select count(*),datepart(iso_week,mydate)
from MyTable
where mydate between '12/26/2010' and '1/8/2011'
group by datepart(iso_week,mydate)
Sample:
declare #T table (Val datetime)
insert into #T values
('2010-12-30'),
('2010-12-31'),
('2011-01-01'),
('2011-01-02'),
('2011-01-03'),
('2011-01-04'),
('2011-01-05')
select
Val,
datepart(iso_week, Val) as ISO_WEEK
from #T
Result:
Val ISO_WEEK
----------------------- -----------
2010-12-30 00:00:00.000 52
2010-12-31 00:00:00.000 52
2011-01-01 00:00:00.000 52
2011-01-02 00:00:00.000 52
2011-01-03 00:00:00.000 1
2011-01-04 00:00:00.000 1
2011-01-05 00:00:00.000 1
Try DateDiff() instead with your start date as the date to compare.
I have a table containing a number of timestamps per day, they represents start and stop events.
ID TimeStamp
----------------------
1 2008-01-01 07:00:00
1 2008-01-01 08:15:00
1 2008-01-01 10:00:00
1 2008-01-01 11:00:00
1 2008-01-02 10:30:00
1 2008-01-02 12:00:00
I would like to calcuate the total running time per day, like this:
ID Date RunningTime
-------------------------
1 2008-01-01 02:15:00
1 2008-01-02 01:30:00
Do anyone have a nice T-SQL solution for my problem?
WITH q AS
(
SELECT *,
CONVERT(DATETIME, CONVERT(VARCHAR(8), TimeStamp, 112), 112) AS dte,
ROW_NUMBER() OVER (PARTITION BY id, CONVERT(DATETIME, CONVERT(VARCHAR(8), TimeStamp, 112), 112) ORDER BY TimeStamp) AS rn
FROM mytable
)
SELECT qb.id, qb.dte, SUM(DATEDIFF(second, qb.TimeStamp, qe.TimeStamp))
FROM q qb
JOIN q qe
ON qe.id = qb.id
AND qe.dte = qb.dte
AND qe.rn = qb.rn + 1
WHERE qb.rn % 2 = 1
GROUP BY
qb.id, qb.dte
This assumes that every record open on a certain day should also be closed on the same day.