Calculate total running time from start/stop timestamps - sql-server

I have a table containing a number of timestamps per day, they represents start and stop events.
ID TimeStamp
----------------------
1 2008-01-01 07:00:00
1 2008-01-01 08:15:00
1 2008-01-01 10:00:00
1 2008-01-01 11:00:00
1 2008-01-02 10:30:00
1 2008-01-02 12:00:00
I would like to calcuate the total running time per day, like this:
ID Date RunningTime
-------------------------
1 2008-01-01 02:15:00
1 2008-01-02 01:30:00
Do anyone have a nice T-SQL solution for my problem?

WITH q AS
(
SELECT *,
CONVERT(DATETIME, CONVERT(VARCHAR(8), TimeStamp, 112), 112) AS dte,
ROW_NUMBER() OVER (PARTITION BY id, CONVERT(DATETIME, CONVERT(VARCHAR(8), TimeStamp, 112), 112) ORDER BY TimeStamp) AS rn
FROM mytable
)
SELECT qb.id, qb.dte, SUM(DATEDIFF(second, qb.TimeStamp, qe.TimeStamp))
FROM q qb
JOIN q qe
ON qe.id = qb.id
AND qe.dte = qb.dte
AND qe.rn = qb.rn + 1
WHERE qb.rn % 2 = 1
GROUP BY
qb.id, qb.dte
This assumes that every record open on a certain day should also be closed on the same day.

Related

Snowflake- Calculate day of Quarter

Snowflake has the simply function Quarter(timestamp()) which returns current quarter, but wondering how to do day of QTR , all tutorials reference Postgres/ sql server.
Goal - create a date table, and show what day of the quarter it is for the next 20 years.
SELECT column1::timestamp as d,
DATE_TRUNC('QUARTER',d) as q,
DATEDIFF('day',q, d) as doq
FROM VALUES ('2019-10-30'),('2019-10-01');
gives 0 for the first day of the quarter, so if you need that to be 1 you can +1 that datadiff.
D Q DOQ
2019-10-30 00:00:00.000 2019-10-01 00:00:00.000 29
2019-10-01 00:00:00.000 2019-10-01 00:00:00.000 0
[Edit:] After re-reading your goal of a 20 year table, here is some code I have used in snowflake in the past to just that:
CREATE OR REPLACE TABLE twenty_years_of_days(date) AS
SELECT DATEADD(day, rn, CURRENT_DATE) as date,
DATE_TRUNC('QUARTER',date) as quarter,
DATEDIFF('day',quarter, date) as doq
FROM (
SELECT row_number() over(order by 1) as rn
FROM TABLE(GENERATOR(rowCount => 365*20)) v
);

SQL Server: update table with value from previous record

I have tried several ways using LAG(), ROW_NUMBER() and so on, but I cannot get it working... Please help.
Assume we have this table:
Date Time Amount Balance
---------------------------------------------
20171001 12:44:00 102.00 102.00
20171002 09:32:12 10.00 null
20171002 20:00:00 123.00 null
20171003 07:43:12 5.29 null
My goal is to update the Balance but these records are not ordered in this table.
I have tried to use this code:
with t1 as
(
select
Date, Time, Amount, Balance,
lag(Balance) over (order by Date, Time) Balance_old
from
table1
)
update table1
set Balance = Amount + Balance_old
where Balance_old is not null
However, this seems to only update 1 record instead of 3 in the above example. Even when I try to do something similar with ROW_NUMBER() then I do not get the results I require.
The results I would like to have are as follows:
Date Time Amount Balance
---------------------------------------------
20171001 12:44:00 102.00 102.00
20171002 09:32:12 10.00 112.00
20171002 20:00:00 123.00 235.00
20171003 07:43:12 5.29 240.29
Please notice: in my situation there is always a record which has a value in Balance. This is the starting point which can be 0 or <>0 (but not null).
As one of the approaches is to simply use sum() over() window function.
-- set up
select *
into t1
from (
select cast('20171001' as date) Date1, cast('12:44:00' as time) Time1, 102.00 Amount, 102.00 Balance union all
select cast('20171002' as date), cast('09:32:12' as time), 10.00, null union all
select cast('20171002' as date), cast('20:00:00' as time), 123.00, null union all
select cast('20171003' as date), cast('07:43:12' as time), 5.29, null
) q
-- UPDATE statement
;with t2 as(
select date1
, time1
, amount
, balance
, sum(isnull(balance, amount)) over(order by date1, time1) as balance1
from t1
)
update t2
set balance = balance1
The result:
Date1 Time1 Amount Balance
---------- ---------------- ---------- -------------
2017-10-01 12:44:00.0000000 102.00 102.00
2017-10-02 09:32:12.0000000 10.00 112.00
2017-10-02 20:00:00.0000000 123.00 235.00
2017-10-03 07:43:12.0000000 5.29 240.29

Split date range into one row per month in SQL Server pt2

This question relates to this post: Split date range into one row per month in sql server
But I'm new to Stackoverflow and new users are not allowed to place comments to provided solutions.That's why I am now adding this as a new question.
The question was this:
I have a table with two column called "from_date" and "to_date"
The table looks like this:
Table (I am not allowed to embed my picture here, so please click the link)
I want result like:-
from_date || to_date
----------- ------------
2013-11-25 || 2013-11-30
2013-12-01 || 2013-12-05
That date is splits from 2013-11-25 to 2013-11-30 and another date split from 2013-12-01 to 2013-12-05... Is it possible to split like this ?
Aaron Bertrand's solution is this:
DECLARE #d TABLE(from_date DATE, to_date DATE);
INSERT #d VALUES ('2013-11-25','2013-12-05');
;WITH n(n) AS
(
SELECT ROW_NUMBER() OVER (ORDER BY [object_id])-1
FROM sys.all_columns
),
d(n,f,t,md,bp,ep) AS
(
SELECT n.n, d.from_date, d.to_date,
DATEDIFF(MONTH, d.from_date, d.to_date),
DATEADD(MONTH, n.n, DATEADD(DAY, 1-DAY(from_date), from_date)),
DATEADD(MONTH, n.n+1, DATEADD(DAY, 0-DAY(from_date), from_date))
FROM n
INNER JOIN #d AS d ON d.to_date >= DATEADD(MONTH, n.n-1, d.from_date)
)
SELECT original_from_date = f, original_to_date = t,
new_from_date = CASE n WHEN 0 THEN f ELSE bp END,
new_to_date = CASE n WHEN md THEN t ELSE ep END
FROM d
WHERE md >= n
ORDER BY original_from_date, new_from_date;
Results:
original_from_date original_to_date new_from_date new_to_date
------------------ ---------------- ------------- -----------
2013-11-25 2013-12-05 2013-11-25 2013-11-30
2013-11-25 2013-12-05 2013-12-01 2013-12-05
Aaron Bertrand's answer is a super powerful query, but it seems it only works well if the startdate is in a month following a month with 31 days. If you change the startdate to, for example, 2013-5-25 (following April, with only 30 days), the new_to_date values are incorrect: all full months suddenly get a max of 30 days then:
original_from_date original_to_date new_from_date new_to_date
2013-05-25 2013-12-05 2013-05-25 2013-05-30
2013-05-25 2013-12-05 2013-06-01 2013-06-30
2013-05-25 2013-12-05 2013-07-01 2013-07-30
2013-05-25 2013-12-05 2013-08-01 2013-08-30
2013-05-25 2013-12-05 2013-09-01 2013-09-30
2013-05-25 2013-12-05 2013-10-01 2013-10-30
2013-05-25 2013-12-05 2013-11-01 2013-11-30
2013-05-25 2013-12-05 2013-12-01 2013-12-05
Can anyone edit the query so that end dates are correct (28,30,31 days, and 29 feb leap) regardless of what month the start date is in? I can't figure out how to do it.
Many thanks, Martijn Vermunt
The answer has been provided, the query has been edited and made perfect. Thank you #Aaron Bertrand
for updating the query!
DECLARE #d TABLE(from_date DATE, to_date DATE);
INSERT #d VALUES ('2013-11-25','2013-12-05');
;WITH n(n) AS
(
SELECT ROW_NUMBER() OVER (ORDER BY [object_id])-1 FROM sys.all_columns
),
d(n,f,t,md,bp,ep) AS
(
SELECT n.n, d.from_date, d.to_date,
DATEDIFF(MONTH, d.from_date, d.to_date),
DATEADD(MONTH, n.n, DATEADD(DAY, 1-DAY(from_date), from_date)),
DATEADD(DAY, -1, DATEADD(MONTH, 1, DATEADD(MONTH, n.n,
DATEADD(DAY, 1-DAY(from_date), from_date))))
FROM n INNER JOIN #d AS d
ON d.to_date >= DATEADD(MONTH, n.n-1, d.from_date)
)
SELECT original_from_date = f, original_to_date = t,
new_from_date = CASE n WHEN 0 THEN f ELSE bp END,
new_to_date = CASE n WHEN md THEN t ELSE ep END
FROM d WHERE md >= n
ORDER BY original_from_date, new_from_date;

SQL count where between dates by month

Consider the below data:
ID Reference Manager LeaseFirstStart LeaseStop
1 KLEIN John 2008-04-02 00:00:00.000 2010-04-01 00:00:00.000
2 HAWKER John 2008-12-18 00:00:00.000 2010-09-17 00:00:00.000
3 SLEEP Bob 2008-01-23 00:00:00.000 2009-01-22 00:00:00.000
4 CODD Bob 2009-08-03 00:00:00.000 2010-08-02 00:00:00.000
5 ALLEN Bob 2008-01-30 00:00:00.000 2009-07-31 00:00:00.000
The earliest month is Jan 2008 and the latest month is Sep 2010.
How can I count the number of leases that were current per month? The output should look like this:
Month Number of Leases
2008-01 2
2008-02 2
2008-03 2
2008-04 3
2008-05 3
2008-06 3
2008-07 3
2008-08 4
… …
Ultimately, I want to use the answer to the question to create the dataset below for use in excel by the user so they can see who had how many leases during the data period.
Month Manager Number of Leases
2008-01 Bob 2
2008-01 John 0
2008-02 Bob 2
2008-02 John 0
2008-03 Bob 2
2008-03 John 0
2008-04 Bob 2
2008-04 John 1
2008-05 Bob 2
2008-05 John 1
2008-06 Bob 2
2008-06 John 1
2008-07 Bob 2
2008-07 John 1
2008-08 Bob 3
2008-08 John 1
… … …
I know I've done it before, but it was a long time ago and I remember it being messy. Thanks in advance!
select sum (no) as no,datet from ( SELECT COUNT (*) as no ,(convert(varchar,datepart (yyyy,[ Start] )) + '-' + convert(varchar, MONTH([ Start] ))) as datet
FROM <tbl>
GROUP BY (convert(varchar,datepart (yyyy,[ Start] )) + '-' + convert(varchar, MONTH([ Start] )))
union SELECT COUNT (*) as no ,(convert(varchar,datepart (yyyy,[ End] )) + '-' + convert(varchar, MONTH([ End] ))) as datet
FROM <tbl>
GROUP BY (convert(varchar,datepart (yyyy,[ End] )) + '-' + convert(varchar, MONTH([ End] )) ) ) t
This is very logical question, finally I created the sql which gives the desired result.. I verified every date and month count and its all ok.
Declare #t table (ID int, Reference varchar(50), Manager varchar(50),LeaseFirstStart datetime,LeaseStop datetime)
insert into #t
values
(1,'KLEIN','John','2008-04-02 00:00:00.000','2010-04-01 00:00:00.000'),
(2,'HAWKER','John','2008-12-18 00:00:00.000','2010-09-17 00:00:00.000'),
(3,'SLEEP','Bob','2008-01-23 00:00:00.000','2009-01-22 00:00:00.000'),
(4,'CODD','Bob','2009-08-03 00:00:00.000','2010-08-02 00:00:00.000'),
(5,'ALLEN','Bob','2008-02-28 00:00:00.000','2009-07-31 00:00:00.000')
declare #lowerdate datetime , #currentdt datetime
select #lowerdate = min(leasefirststart), #currentdt= max(leasestop) from #t
;with cte as
(
select firstday,DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, FirstDay) + 1, 0)) Lastday, mng from
( select dateadd(m,datediff(m,0,#lowerdate)+v.number,0) as FirstDay
From master..spt_values v
Where v.type='P' and v.number between 0 and datediff(m, #lowerdate, #currentdt)
) as a
, (select distinct manager mng from #t ) as b
)
select (convert(varchar,datepart (yyyy,FirstDay )) + '-' + convert(varchar, MONTH(FirstDay ))) MonthAndYear ,mng as mng , count( manager ) cnt
from cte
left join #t on
(
firstday between LeaseFirstStart and LeaseStop
or
Lastday between LeaseFirstStart and LeaseStop
) and cte.mng = Manager
group by firstday, mng
order by FirstDay

Fetching dates monthly from the table

Can you help out with a problem
I have table price table which has daily prices starting 31st Dec 2010 till todays date.The table contains daily prices
2009-12-31 00:00:00.000 1.0020945351
2010-01-01 00:00:00.000 1.0021009300
2010-01-04 00:00:00.000 1.0021910181
2010-01-05 00:00:00.000 1.0022005986
2010-01-06 00:00:00.000 1.0022428696
2010-01-07 00:00:00.000 1.0022647147
2010-01-08 00:00:00.000 1.0022842726
2010-01-11 00:00:00.000 1.0023374302
2010-01-12 00:00:00.000 1.0023465374
2010-01-13 00:00:00.000 1.0023638081
2010-01-14 00:00:00.000 1.0023856533
2010-01-00 00:00:00.000 1.0024083955
2010-01-18 00:00:00.000 1.0024779677
2010-01-19 00:00:00.000 1.0025020553
2010-01-20 00:00:00.000 1.002521135
2010-01-21 00:00:00.000 1.0025420688
2010-01-22 00:00:00.000 1.0025593397
2010-01-25 00:00:00.000 1.0026180146
2010-01-26 00:00:00.000 1.002637573
2010-01-27 00:00:00.000 1.0026648447
2010-01-28 00:00:00.000 1.0026957934
2010-01-29 00:00:00.000 1.0027267421
2010-02-01 00:00:00.000 1.0028195885
2010-02-02 00:00:00.000 1.0028573523
2010-02-03 00:00:00.000 1.0028964611
2010-02-04 00:00:00.000 1.00293557
2010-02-05 00:00:00.000 1.002973334
2010-02-08 00:00:00.000 1.0030879717
2010-02-09 00:00:00.000 1.0031279777
2010-02-10 00:00:00.000 1.003171166
2010-02-11 00:00:00.000 1.0032007452
2010-02-12 00:00:00.000 1.0032575895
2010-02-00 00:00:00.000 1.0033749191
2010-02-1 00:00:00.000 1.0034140292
2010-02-17 00:00:00.000 1.003452691
2010-02-18 00:00:00.000 1.0034918013
2010-02-19 00:00:00.000 1.0035395633
2010-02-22 00:00:00.000 1.0036664439
2010-02-23 00:00:00.000 1.0037042097
2010-02-24 00:00:00.000 1.0037510759
2010-02-25 00:00:00.000 1.0038001834
2010-02-26 00:00:00.000 1.003850077
I need to write a query to get index based on
(Last day of current month/Previous month last day) - 1 * 100.So that output comes something like this
31-Jan-10 0.01%
28-Feb-10 0.02%
31-Mar-10 0.00%
Following is one of the solution I thought about however please share best ideas to implement this problem
Extract last day of all the months with values into a temp table and then order by dates so that they subtract and put the values into another temp table
Looking forward to your help.
Try this....
DECLARE #StartDate DATETIME = '2010-01-01',
#EndDate DATETIME = GETDATE();
WITH data AS (
SELECT 1 AS i, CONVERT(DATETIME, NULL) AS StartDate, DATEADD(MONTH, 0, #StartDate) - 1 AS EndDate
UNION ALL
SELECT i + 1, data.EndDate, DATEADD(MONTH, i, #StartDate) - 1 AS EndDate
FROM data
WHERE DATEADD(MONTH, i, #StartDate) - 1 < #EndDate
)
SELECT (
((SELECT TOP 1 Rate FROM RateTable WHERE Date <= data.EndDate ORDER BY Date DESC) /
(SELECT TOP 1 Rate FROM RateTable WHERE Date <= data.StartDate ORDER BY Date DESC)- 1) * 100)
FROM DATA -- parenthesis were causing issues
WHERE data.StartDate IS NOT NULL
OPTION (MAXRECURSION 10000);
You'll need to replace the
(SELECT Rate FROM RateTable WHERE Date = data.StartDate)
and
(SELECT Rate FROM RateTable WHERE Date = data.EndDate)
With the values for your rate table. as you didn't mention column and table names in your question.
rwking indicated that there might be gaps in the rates table that would cause issues.
I've modified the subquery to bring back the first rate on or nearest the start and end dates.
Hope that helps
You can use the LAG function introduced in SQL2012 to make it a bit easier:
WITH DataWithOrder AS
(
SELECT DateField, PriceField,
ROW_NUMBER() OVER(PARTITION BY YEAR(DateField), Month(DateField) ORDER BY DateField DESC) AS Pos
FROM PriceTable
)
SELECT
DateField,
PriceField,
LAG(PriceField) OVER(ORDER BY DateField) AS PriceLastMonth,
((PriceField / LAG(PriceField) OVER(ORDER BY DateField)) - 1) * 100 AS PCIncrease
FROM DataWithOrder
WHERE Pos = 1
ORDER BY DateField
I took a very different approach than the other guy. His is more elegant and would work better if the daily data does represent every single day of every month. If there are gaps in days, however, as your sample data represents, you can try the following code.
with cte as (select mydate
, price
, ROW_NUMBER() over(partition by YEAR(mydate), MONTH(mydate)
order by day(mydate) desc) row_n
from #temp)
select mydate, price, ROW_NUMBER() over(order by mydate desc) row_num
into #temp2
from cte
where row_n = 1
alter table #temp2
add idx float
declare #counter int = 1
while #counter < (select MAX(row_num)+1 from #temp2)
begin
update t2
set t2.idx = ((t2.price/t3.price)-1)*100
from #temp2 t2 left join
#temp2 t3 on 1 = 1
where t2.row_num = #counter and t3.row_num = #counter + 1
set #counter = #counter + 1
end
select mydate, idx
from #temp2
As the other poster mentioned, you didn't provide column or table names. My process was to insert your data into a table called [#temp] with column names [mydate] and [price].
Also, the data sample you provided contains two invalid dates that I changed to arbitrary dates just for the purposes of getting code to run. (2010-01-00 and 2010-02-00)

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