Remove characters from a word - VBA - arrays

Question

I want to remove characters from a string based on the position. i use the below code and i manage to:
Insert all word letters in an array
Loop the array and replace the letters that i want with nothing
BUT i dont know have to remove nothing from the array, recreate array index and create the word again without those characters.
'Create an array with all letters
For j = 1 To Len(SheetName2)
ReDim Preserve arrWord(k)
arrWord(k) = Mid(SheetName2, j, 1)
k = k + 1
Next j
Counter = (Len(SheetName2) - 31) * 2
'Loop array and replace with nothing
For w = Counter - 1 To 0 Step -2
arrWord(w) = ""
Next w

Answer 1

You don't need an array of the characters. Just read every second character into a new string.
Public Sub OutputEverySecondChar()
Dim TestString As String
TestString = "abcdefghij"
Dim OutputString As String
Dim iChar As Long
For iChar = 1 To Len(TestString) Step 2
OutputString = OutputString & Mid$(TestString, iChar, 1)
Next iChar
Debug.Print OutputString 'output is: acegi
End Sub
Or even better as re-useable function:
Public Sub test()
Debug.Print ReturnEveryXcharcter(InputString:="abcdefghij", FirstChar:=1, xChar:=2, CharLength:=1)
End Sub
Public Function ReturnEveryXcharcter(InputString As String, FirstChar As Long, xChar As Long, CharLength As Long) As String
Dim iChar As Long
For iChar = FirstChar To Len(InputString) Step xChar
ReturnEveryXcharcter = ReturnEveryXcharcter & Mid$(InputString, iChar, CharLength)
Next iChar
End Function
So the function is even more flexible and you can eg use the following to delete every 3ʳᵈ character (beginning with the first):
Debug.Print ReturnEveryXcharcter(InputString:="abcdefghij", FirstChar:=2, xChar:=3, CharLength:=2)
'output will be: bcefhi
Edit according comment:
Then loop until it is less then 31 characters:
Public Sub test()
Dim SheetName As String
SheetName = "1234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890"
Do
SheetName = ReturnEveryXcharcter(InputString:=SheetName, FirstChar:=1, xChar:=2, CharLength:=1, LengthLimit:=31)
Loop While Len(SheetName) > 31
Debug.Print SheetName
End Sub

Answer 2

My solution:
If Len(SheetName1) > 31 Then
SheetName2 = Replace(SheetName1, " ", "")
'Third check - Remove letter by letter starting from the beginning
If Len(SheetName2) > 31 Then
Counter = (Len(SheetName2) - 31) * 2
Part_1 = Left(SheetName2, Counter)
Part_2 = Mid(SheetName2, Counter + 1, Len(SheetName2) - (Counter))
Semi_Part = ""
For j = 1 To Counter Step 2
'Use only Part_1 because it ll be the same in all occurance
Semi_Part = Semi_Part + Mid(Part_1, j, 1)
Next j
FinalSheetname = Semi_Part & Part_2
Else
FinalSheetname = SheetName2
End If
Else
FinalSheetname = SheetName1
End If

Answer 3

Just for interest, you can also do this with a worksheet function if you have one of the more recent versions of Excel (O365 or 2016+) that has the CONCAT function.
The "trick" is to create an array that includes the positions of the characters you wish to retain.
In the case of deleting every even space positioned character (retaining the odd positions):
=CONCAT(MID(A1,(ROW(INDEX($A:$A,1,1):INDEX($A:$A,ROUNDUP(LEN(A1)/2,0),1))-1)*2+1,1))
Since this is an array formula, you need to "confirm" it by holding down ctrl + shift while hitting enter. If you do this correctly, Excel will place braces {...} around the formula as observed in the formula bar