can you modify my program to use "y/n" statement in c - c

Question

Here, i am writing a c programming code i need help form you guys! I want to modify my program and want to use this in a loop i.e if a user enters "y" & if "n" will be entered it must end the program, I am trying this with switch case, I tried my best to end the program, it is returning to end but i don't know how to use "y" value for running the program again!
#include<conio.h>
#include<stdio.h>
int main()
{
char n, A, B;
float kmTOm = 0.621371;
float inchesTOfoot = 0.0833333;
float cmTOinches = 0.393701;
float poundtokg = 0.453592;
float inchesTOmeter = 0.0254;
float a, b;
while (1)
{
printf("Enter the input character. q to quit\n1. kms to miles\n2. inches to foot\n3. cms to inches\n4. pound to kgs\n5. inches to meters\n");
scanf(" %c", &n);
switch (n)
{
case 'q':
printf("Quitting the program...");
goto end;
break;
case '1':
printf("Enter quantity in terms of a unit\n");
scanf("%f", &a);
b = a * kmTOm;
printf("%.2f Kms is equal to %.2f Miles\n\n\n", a, b);
break;
case '2':
printf("Enter quantity in terms of a unit\n");
scanf("%f", &a);
b = a * inchesTOfoot;
printf("%f Inches is equal to %f Foot\n", a, b);
break;
case '3':
printf("Enter quantity in terms of a unit\n");
scanf("%f", &a);
b = a * cmTOinches;
printf("%f Cms is equal to %f Inches\n", a, b);
break;
case '4':
printf("Enter quantity in terms of a unit\n");
scanf("%f", &a);
b = a * poundtokg;
printf("%f Pounds is equal to Kgs %f \n", a, b);
break;
case '5':
printf("Enter quantity in terms of a unit\n");
scanf("%f", &a);
b = a * inchesTOmeter;
printf("%f inches is equal to %f meters \n", a, b);
break;
default:
printf("In default now");
break;
}
}
end:
return 0;
}
I want a kindful modification from you developers to help me as I am a beginner and learing from a month, I except that the actual output must come like this ----o/p- do you want to quit press "q" ,do you want to run again press "y"

Answer 1

If you change the while(1) to a variable, then you can test after every loop whether it's time to exit.
The changes I made to your code all have comments below:
#include<conio.h>
#include<stdio.h>
int main()
{
char n, A, B;
float kmTOm = 0.621371;
float inchesTOfoot = 0.0833333;
float cmTOinches = 0.393701;
float poundtokg = 0.453592;
float inchesTOmeter = 0.0254;
float a, b;
n = 'y'; //set n to make sure while repeats
while (n != 'n') //change while to test "n" instead of 1, this way the value of n can be changed and the loop can be exited
{
printf("Enter the input character. q to quit\n1. kms to miles\n2. inches to foot\n3. cms to inches\n4. po
und to kgs\n5. inches to meters\n");
scanf(" %c", &n);
switch (n)
{
case 'q':
printf("Quitting the program...");
return(0); //exit entire program
break;
case '1':
printf("Enter quantity in terms of a unit\n");
scanf("%f", &a);
b = a * kmTOm;
printf("%.2f Kms is equal to %.2f Miles\n\n\n", a, b);
break;
case '2':
printf("Enter quantity in terms of a unit\n");
scanf("%f", &a);
b = a * inchesTOfoot;
printf("%f Inches is equal to %f Foot\n", a, b);
break;
case '3':
printf("Enter quantity in terms of a unit\n");
scanf("%f", &a);
b = a * cmTOinches;
printf("%f Cms is equal to %f Inches\n", a, b);
break;
case '4':
printf("Enter quantity in terms of a unit\n");
scanf("%f", &a);
b = a * poundtokg;
printf("%f Pounds is equal to Kgs %f \n", a, b);
break;
case '5':
printf("Enter quantity in terms of a unit\n");
scanf("%f", &a);
b = a * inchesTOmeter;
printf("%f inches is equal to %f meters \n", a, b);
break;
default:
printf("In default now");
break;
}
//Ask the user if they want to run again. The code will exit if the user types 'n', it will repeat if they type anything else (including 'y').
printf("\nRun again? y/n:");
scanf(" %c",&n);
}
return 0;
}