Repeat the c program according to user - c

Question

I want this program to repeat every time when users wants to continue.
I want user to choose "yes" to continue the program using other options but it's not executable. I used 'if else' statement for that but I am not getting any applicable or satisfying results. Can someone help me on this matter?
#include <stdio.h>
int main() {
float a, b;
int p;
char q;
printf("Enter the first number:");
scanf("%f", &a);
printf("Enter the second number:");
scanf("%f", &b);
printf("Choose the option:\n1.Sum\n \n2.Subtraction\n \n3.Multiplication\n \n4.Divison\n \nyour choice=");
scanf("%d", &p);
switch (p)
{
case 1:
printf("The sum of above numbers is: %f", a + b);
break;
case 2:
printf("The subtraction of above numbers is:%f", a - b);
break;
case 3:
printf("The multiplication of above numbers is:%f", a * b);
break;
case 4:
printf("The division of above numbers is:%f", a / b);
break;
}
printf("\n\nDo u want to continue:(y for yes and n for no) :");
scanf("%c", &q);
if (q == 'y')
return main();
else
return 0;
}

Answer 1

You need to use a loop for this. Explanations in the comments:
int main() {
float a, b;
int p;
char q;
do // use a loop here
{
printf("Enter the first number:");
scanf("%f", &a);
printf("Enter the second number:");
scanf("%f", &b);
printf("Choose the option:\n1.Sum\n \n2.Subtraction\n \n3.Multiplication\n \n4.Divison\n \nyour choice=");
scanf("%d", &p);
switch (p)
{
case 1:
printf("The sum of above numbers is: %f", a + b);
break;
case 2:
printf("The subtraction of above numbers is:%f", a - b);
break;
case 3:
printf("The multiplication of above numbers is:%f", a * b);
break;
case 4:
printf("The division of above numbers is:%f", a / b);
break;
}
printf("\n\nDo you want to continue: (y for yes and n for no) :");
scanf(" %c", &q); // use " %c" instead of "%c", the white space
// will absorb any blank space (including newlines)
} while (q == 'y'); // continue loop if user has entered 'y'
return 0;
}