y/n loop at the end of a function - c

Question

good evening,
Here is my code. I am making a little calculator but I'm battling at the end to make the function repeat with a y/n loop. I have looked at others but can't seem to get the right answer.
Thanks.
#include <stdio.h>
int main()
{
int n, num1, num2, result;
char answer;
{
printf("\nWhat operation do you want to perform?\n");
printf("Press 1 for addition.\n");
printf("Press 2 for subtraction.\n");
printf("Press 3 for multiplication.\n");
printf("Press 4 for division.\n");
scanf("%d", &n);
printf("Please enter a number.\n");
scanf("%d", &num1);
printf("Please enter the second number.\n");
scanf("%d", &num2);
switch(n)
{
case 1: result = num1 + num2;
printf("The addition of the two numbers is %d\n", result );
break;
case 2: result = num1 - num2;
printf("The subtraction of the two numbers is %d\n", result );
break;
case 3: result = num1 * num2;
printf("The multiplication of the two numbers is %d\n", result );
break;
case 4: result = num1 / num2;
printf("The division of the two numbers is %d\n", result );
break;
default: printf("Wrong input!!!");
}
printf("\nDo you want to continue, y/n?\n");
scanf("%c", &answer);
while(answer == 'y');
}
return 0;
}

Answer 1

You have this code
char answer;
{
printf("\nWhat operation do you want to perform?\n");
//...
//... more code
//...
printf("\nDo you want to continue, y/n?\n");
scanf("%c", &answer);
while(answer == 'y');
}
Try to change it to:
char answer;
do {
printf("\nWhat operation do you want to perform?\n");
//...
//... more code
//...
printf("\nDo you want to continue, y/n?\n");
scanf("%c", &answer);
} while(answer == 'y');
So the basic form is:
do {
// code to repeat
} while (Boolean-expression);
BTW - You should always check the value returned by scanf
Example:
if (scanf("%c", &answer) != 1)
{
// Add error handling
}
Also notice that you often want a space before %c to remove any white space (including newlines) in the input stream. Like
if (scanf(" %c", &answer) != 1)
{
// Add error handling
}