how do i pick a memory in an array that i create after displaying the array value. how to slect thte value with cin when the program run - arrays

Question

string bookname [5] = {"STPM BOOKS","SPM BOOKS","PMR BOOKS","TEXT BOOK","PRACTICAL BOOK"};
float price [5] = {30.90,24.90,19.90,45.90,15.90};
for(int i = 0; i < 5 ; i++)
{
cout << i+1 << "book name " << bookname[i] << " ---- RM " << price[i] << endl;}
i want to select the value for example like stpm books and its price from the array and display it to cout after selecting from a cin and doing the selection when the code was excercuted
}

Answer 1

Based on your updated query, asking for an exit condition, I have modified the code. Please note that I have used getline(cin, answer) to handle the input. I use getline() because I am less likely to mess up when I use getline() over cin >> answer.
Note that getline(cin, answer) does a few things for you:
Returns true if input was received
Fills in the answer
Gets an entire line, until user provides new line
Thus, the line while (std::getline(std::cin, answer) && answer != "n") will get an entire book, even if there are spaces. The && allows for a check of the answer for "n" before entering the while loop's body.
As answer is a std::string, the comparison is to "n", not 'n'.
#include <iostream>
#include <string>
#include <iomanip> // setprecision
int main()
{
std::string bookname[5] =
{"STPM BOOKS", "SPM BOOKS", "PMR BOOKS", "TEXT BOOK", "PRACTICAL BOOK"};
float price[5] = {30.90, 24.90, 19.90, 45.90, 15.90};
std::string answer;
float cost;
std::cout << "Please provide the name of a book or type 'n' to exit"
<< std::endl;
// get one line into answer, and also exit while if answer is "n"
while (std::getline(std::cin, answer) && answer != "n") {
bool found = false;
for (int i = 0; i < 5; i++) {
if (bookname[i] == answer) {
std::cout << "The book " << bookname[i] << " costs $" << std::fixed
<< std::setprecision(2) << price[i] << std::endl;
found = true;
break; // /no need to continue inside the for loop
}
}
// on last loop, give up
if (!found) {
std::cout << "The book " << answer << " is not in our inventory"
<< std::endl;
}
}
}